加法豎式運算式子c語言

『壹』 簡單的用c語言寫一個計算器程式，加減乘除能用就好

簡單的用c語言寫一個計算器程式，加減乘除能用就好 #include"stdio.h"
void main()
{
float a,b,c;
char e;
printf("input a,e,b\n");/*輸入兩個數和符號，例如3+8*/
scanf("%f%c%f",&a,&e,&b);
switch(e)
{
case '+':c=a+b;break;
case '-':c=a-b;break;
case '*':c=a*b;break;
case '/':
if(b==0.0) printf("error\n");
else c=a/b;break;
}
printf("%f%c%f=%f",a,e,b,c);
}
如何用vc++編寫一個簡單的（只有加減乘除）計算器程式?
先設定介面如下
加法按鈕程式碼
void CMy03Dlg::OnBnClickedButton1()
{
TODO：在此新增控制元件通知處理程式程式碼
UpdateData(TRUE);
m_Nub3=m_Nub1+m_Nub2;
UpdateData(FALSE);
}
減法按鈕程式碼
void CMy03Dlg::OnBnClickedButton2()
{
TODO：在此新增控制元件通知處理程式程式碼
UpdateData(TRUE);
m_Nub3=m_Nub1-m_Nub2;
UpdateData(FALSE);
}
乘法按鈕程式碼
void CMy03Dlg::OnBnClickedButton3()
{
TODO：在此新增控制元件通知處理程式程式碼
UpdateData(TRUE);
m_Nub3=m_Nub1*m_Nub2;
UpdateData(FALSE);
}
除法按鈕程式碼
void CMy03Dlg::OnBnClickedButton4()
{
TODO：在此新增控制元件通知處理程式程式碼
UpdateData(TRUE);
if(m_Nub2!=0)
m_Nub3=m_Nub1 / m_Nub2;
else
AfxMessageBox("被除數不能為0");
UpdateData(FALSE);
}
清除按鈕程式碼
void CMy03Dlg::OnBnClickedButton5()
{
TODO：在此新增控制元件通知處理程式程式碼
UpdateData(TRUE);
m_Nub3=0;
m_Nub1=0;
m_Nub2=0;
UpdateData(FALSE);
}
結束按鈕程式碼
void CMy03Dlg::OnBnClickedButton6()
{
TODO：在此新增控制元件通知處理程式程式碼
CDialog::OnOK();
}
如果只允許在輸入框中輸入資料應該怎樣處理？
製作托盤程式
目的：在工作列中建立一個圖示，使該程式永遠駐留在記憶體中。例如郵件檢查程式可以作為駐留程式，一旦有郵件來了，就可以接收郵件。
Shell_NotifyIcon函式傳送訊息來增加、刪除、修改工作列的圖示
BOOL TrayMessage(HWND hWnd, DWORD dwMessage, HICON hIcon, PSTR pszTip)
{
BOOL res;
NOTIFYICONDATA tnd;
tnd.cbSize = sizeof(NOTIFYICONDATA);
tnd.hWnd = hWnd;
tnd.uID = IDI_ICON1;
tnd.uFlags = NIF_MESSAGE|NIF_ICON|NIF_TIP;
tnd.uCallbackMessage = WM_MY_TRAY_NOTIFICATION;
tnd.hIcon = hIcon;
lstrcpyn(tnd.szTip, pszTip, sizeof(tnd.szTip));
res = Shell_NotifyIcon(dwMessage, &tnd); dwMessage為NIM_ADD從工作列中新增圖示、NIM_DELETE從工作列中刪除圖示、NIM_MODIFY改變工作列中圖示
if (hIcon)
DestroyIcon(hIcon);
return res;
}
定義一個回撥訊息：WM_MY_TRAY_NOTIFICATION
在DLG的CPP檔案中，
#define WM_MY_TRAY_NOTIFICATION WM_USER+100
為對話方塊新增訊息對映ON_MESSAGE(WM_MY_TRAY_NOTIFICATION,OnTrayNotification)
在DLG的標頭檔案中應該有
public:
long m_Nub1;
float m_Nub3;
CBitmapButton Button;
afx_msg void OnBnClickedButton1();
long m_Nub2;
afx_msg void OnBnClickedButton2();
afx_msg void OnBnClickedButton4();
afx_msg void OnBnClickedButton5();
afx_msg void OnBnClickedButton3();
afx_msg void OnBnClickedButton6();
afx_msg void OnBnClickedButton7();
afx_msg LRESULT OnTrayNotification(WPARAM wparam, LPARAM lparam);
在DLG的CPP檔案中應該有
BEGIN_MESSAGE_MAP(CMailCheckDlg, CDialog)
……
ON_MESSAGE(WM_MY_TRAY_NOTIFICATION,OnTrayNotification)
……
END_MESSAGE_MAP()
並定義一個回撥訊息函式
LRESULT CMailCheckDlg::OnTrayNotification(WPARAM wparam, LPARAM lparam)
{
switch (lparam )
{
case WM_RBUTTONUP:
case WM_LBUTTONDBLCLK:修改不同的按鈕處理事件，以觀察圖示退出效果。
ShowWindow(SW_SHOW);
TrayMessage(m_hWnd, NIM_DELETE, NULL, "");從工作列中刪除圖示
}
return 0;
}
在對話方塊視窗上新增「駐留」按鈕，雙擊按鈕新增程式碼
void CMailCheckDlg::OnBnClickedButton1()
{
TODO：在此新增控制元件通知處理程式程式碼
下面程式向工作列新增圖示
TrayMessage(m_hWnd, NIM_ADD, NULL, "計算器程式");
TrayMessage(m_hWnd, NIM_MODIFY, m_hIcon, "計算器程式");
ShowWindow(SW_HIDE);
用MFC編寫一個簡單的加減乘除計算器
我有程式，加31782771群
c語言計算器程式設計包含加減乘除簡單的函式運算
實用計算器之程式設計
[摘 要]多用計算器的構思及設計程式碼
[關鍵詞]多用計算器；設計
數值計算可以說是日常最頻繁的工作了，WIN98提供了「計算器」軟體供使用者使用，該軟體可以處理一般的一步四則運算，例如：3+2、5/3等等，但在日常中使用者經常遇到多步四則運算問題，例如：3+4*5-4/2，45*34/2+18*7等等，那麼該個計算器就無法勝任了，作者製作了一個實用的計算器，該計算器新增不少功能：（程式介面如圖）
1．可以實現連續的四則運算
2．可以實現輸入式子的顯示
3．可以方便計算個人所得稅
4．滑鼠、鍵盤均可輸入資料
5．操作介面友好
6．擊鍵可發聲
構建該個計算器所需研究及解決的核心問題有如下幾個：1、連乘求值?2、字元顯示 3、鍵盤輸入?4、擊鍵發聲?5、個人所得稅法規，為了使大家對程式有更一步認識，現將程式碼提供給讀者參考：
*定義陣列及窗體變數
Dim number2(0 To 50) As Double
Dim number(0 To 50) As Double
Dim z As Integer
Dim k As Integer, r As Integer
Dim j As Integer
Dim str As String
*呼叫名為「playsound」的API函式
Private Declare Function PlaySound Lib "winmm.dll" Alias "PlaySoundA" (ByVal lpszName As String, ByVal hMole As Long, ByVal dwFlags As Long) As Long
Private Const SND_FILENAME = &H20000?
Private Const SND_ASYNC = &H1?
Private Const SND_SYNC = &H0
*判斷通用過程
Sub pianan(p As String)
r = 0
Dim i As Integer, l As Integer, h As Integer
h = 0
i = 1
If InStr(Trim$(p), "*") <> 0 Then
k = k + 1
End If
If InStr(Trim$(p), "/") <> 0 Then
r = r + 1
End If
End Sub
*連乘通用過程(略)
*各按鈕事件過程
Private sub Command1_Click(Index As Integer)
PlaySound App.Path & "\start.wav", 0, SND_SYNC
Text1.Text = Text1.Text + Command1(Index).Caption
Text2.Text = Text2.Text + Command1(Index).Caption
Text1.SetFocus
End Sub
rivate sub Command10_Click()
PlaySound App.Path & "\start.wav", 0, SND_SYNC
str = Text3.Text
End Sub
Private sub Command11_Click()
PlaySound App.Path & "\start.wav", 0, SND_SYNC
Text3.Text = str
End Sub
rivate sub Command2_Click()
PlaySound App.Path & "\start.wav", 0, SND_SYNC
Dim totle As Double
Dim n As Integer
Call pianan(Text1.Text)
If k >= 1 Or r >= 1 Then
Call liancheng(totle)
number2(z) = totle
If Mid$(Trim$(Text1.Text), 1, 1) = "-" Then
number2(z) = -totle
End If
k = 0: r = 0
Else
number2(z) = Val(Text1.Text)
End If
Text1.Text = ""
Text2.Text = Text2 + "+"
z = z + 1
Text1.SetFocus
End Sub
rivate sub Command3_Click()
PlaySound App.Path & "\start.wav", 0, SND_SYNC
Dim totle As Double
Dim n As Integer
Call pianan(Text1.Text)
If k >= 1 Or r >= 1 Then
Call liancheng(totle)
number2(z) = totle
If Mid$(Trim$(Text1.Text), 1, 1) = "-" Then
number2(z) = -totle
End If
k = 0: r = 0
Else
number2(z) = Val(Text1.Text)
End If
Text1.Text = ""
Text2.Text = Text2 + "-"
Text1.Text = Text1.Text & "-"
z = z + 1
Text1.SetFocus
End Sub
Private sub Command4_Click()
PlaySound App.Path & "\start.wav", 0, SND_SYNC
Text2.Text = Text2.Text + "*"
Text1.Text = Text1.Text + "*"
Text1.SetFocus
End Sub
rivate sub Command5_Click()
PlaySound App.Path & "\start.wav", 0, SND_SYNC
Text2.Text = Text2 + "/"
Text1.Text = Text1 + "/"
Text1.SetFocus
End Sub
Private sub Command6_Click()
PlaySound App.Path & "\sound.wav", 0, SND_SYNC
Dim totle As Double
Dim n As Integer
Call pianan(Text1.Text)
If k >= 1 Or r >= 1 Then
Call liancheng(totle)
number2(z) = totle
If Mid$(Trim$(Text1.Text), 1, 1) = "-" Then
number2(z) = -totle
End If
k = 0: r = 0
Else
number2(z) = Val(Text1.Text)
End If
Text1.Text = ""
z = z + 1
Dim dengyu As Double
Dim v As Integer
For v = 0 To 50
dengyu = dengyu + number2(v)
Next v
If dengyu < 0 Then
Text3.ForeColor = &HFF&
Else
Text3.ForeColor = &HFF0000
End If
Text3.Text = dengyu
Text1.SetFocus
If Len(Text3.Text) >= 14 Then
calcresult.Show
End If
End Sub
rivate sub Command7_Click()
PlaySound App.Path & "\start.wav", 0, SND_SYNC
z = 0: k = 0: r = 0: j = 0
Dim i As Integer
For i = 0 To 50
number(i) = 0
number2(i) = 0
Next i
Text1.Text = ""
Text2.Text = ""
Text3.Text = ""
Text1.SetFocus
End Sub
rivate sub Command8_Click()
PlaySound App.Path & "\start.wav", 0, SND_SYNC
If Val(Text3.Text) = 0 Then
MsgBox "除數不能為0！"
Exit Sub
End If
Text3.Text = 1 / Val(Text3.Text)
End Sub
Private sub Command9_Click()
PlaySound App.Path & "\start.wav", 0, SND_SYNC
Text3.ForeColor = &HFF0000
Text3.Text = Val(Text3.Text) * Val(Text3.Text)
End Sub
rivate sub muninter_Click()
Dim i
i = Shell("C:\Program Files\InterExplorer\iexplore.exe", vbMaximizedFocus)
End Sub
rivate sub munmp3_Click()
Dim i
i = Shell("C:\Program Files\Windows Media Player\mplayer2", vbNormalNoFocus)
End Sub
Private sub mun *** _Click()
Dialog.Show
End Sub
rivate sub muntax_Click()
tax.Show
End Sub
rivate sub munver_Click()
ver.Show
End Sub
rivate sub notepad_Click()
Dim i
i = Shell("c:\windows\notepad", vbNormalFocus)
End Sub
Private sub Text1_KeyPress(KeyAscii As Integer)
PlaySound App.Path & "\start.wav", 0, SND_SYNC
Dim num As Integer
num = Val(KeyAscii)
If num > 47 And num < 58 Then
Text1.Text = Text1.Text + CStr(num - 48)
Text2.Text = Text2.Text + CStr(num - 48)
End If
If num = 46 Then
Text1.Text = Text1.Text + "."
Text2.Text = Text2.Text + "."
End If
If KeyAscii = 43 Then
Dim totle As Double
Dim n As Integer
Call pianan(Text1.Text)
If k >= 1 Or r >= 1 Then
Call liancheng(totle)
number2(z) = totle
If Mid$(Trim$(Text1.Text), 1, 1) = "-" Then
number2(z) = -totle
End If
k = 0: r = 0
Else
number2(z) = Val(Text1.Text)
End If
Text1.Text = ""
Text2.Text = Text2 + "+"
z = z + 1
End If
If KeyAscii = 45 Then
Call pianan(Text1.Text)
If k >= 1 Or r >= 1 Then
Call liancheng(totle)
number2(z) = totle
If Mid$(Trim$(Text1.Text), 1, 1) = "-" Then
number2(z) = -totle
End If
k = 0: r = 0
Else
number2(z) = Val(Text1.Text)
End If
Text1.Text = ""
Text2.Text = Text2 + "-"
Text1.Text = Text1.Text & "-"
z = z + 1
End If
If KeyAscii = 42 Then
Text2.Text = Text2.Text + "*"
Text1.Text = Text1.Text + "*"
End If
If KeyAscii = 47 Then
Text2.Text = Text2.Text + "/"
Text1.Text = Text1.Text + "/"
End If
If KeyAscii = vbKeyReturn Then
PlaySound App.Path & "\sound.wav", 0, SND_SYNC
Call pianan(Text1.Text)
If k >= 1 Or r >= 1 Then
Call liancheng(totle)
number2(z) = totle
If Mid$(Trim$(Text1.Text), 1, 1) = "-" Then
number2(z) = -totle
End If
k = 0: r = 0
Else
number2(z) = Val(Text1.Text)
End If
Text1.Text = ""
z = z + 1
Dim dengyu As Double
Dim v As Integer
For v = 0 To 50
dengyu = dengyu + number2(v)
Next v
If dengyu < 0 Then
Text3.ForeColor = &HFF&
Else
Text3.ForeColor = &HFF0000
End If
Text3.Text = dengyu
End If
If KeyAscii = vbKeyEscape Then
z = 0: k = 0: r = 0: j = 0
Dim i As Integer
For i = 0 To 50
number(i) = 0
number2(i) = 0
Next i
Text1.Text = ""
Text2.Text = ""
Text3.Text = ""
Text1.SetFocus
End If
If Len(Text3.Text) >= 14 Then
calcresult.Show
End If
End Sub
rivate sub Text3_Change()
tax2.Text1 = Text3.Text
End Sub
用c語言編寫能運算加減乘除的計算器程式，用到棧
#include "stdio.h"
#include "string.h"
#include "ctype.h"
#include "math.h"
expression evaluate
#define iMUL 0
#define iDIV 1
#define iADD 2
#define iSUB 3
#define iCap 4
#define LtKH 5
#define RtKH 6
#define MaxSize 100
void iPush(float);
float iPop();
float StaOperand[MaxSize];
int iTop=-1;

char Srcexp[MaxSize];
char Capaexp[MaxSize];
char RevPolishexp[MaxSize];
float NumCapaTab[26];
char validexp[]="*/+-()";
char NumSets[]="0123456789";
char StackSymb[MaxSize];
int operands;

void NumsToCapas(char [], int , char [], float []);
int CheckExpress(char);
int PriorChar(char,char);
int GetOperator(char [], char);
void counterPolishexp(char INexp[], int slen, char Outexp[]);
float CalcRevPolishexp(char [], float [], char [], int);
void main()
{
int ilen;
float iResult=0.0;
printf("enter a valid number string:\n");
memset(StackSymb,0,MaxSize);
memset(NumCapaTab,0,26); A--NO.1, B--NO.2, etc.
gets(Srcexp);
ilen=strlen(Srcexp);
printf("source expression:%s\n",Srcexp);
NumsToCapas(Srcexp,ilen,Capaexp,NumCapaTab);
printf("Numbers listed as follows:\n");
int i;
for (i=0; i<operands; ++i)
printf("%.2f ",NumCapaTab[i]);
printf("\nCapaexp listed in the following:\n");
printf("%s\n",Capaexp);
ilen=strlen(Capaexp);
counterPolishexp(Capaexp,ilen,RevPolishexp);
printf("RevPolishexp:\n%s\n",RevPolishexp);
ilen=strlen(RevPolishexp);
iResult=CalcRevPolishexp(validexp, NumCapaTab, RevPolishexp,ilen);
printf("\ncounterPolish expression:\n%s%.6f\n",Srcexp,iResult);
}
void iPush(float value)
{
if(iTop<MaxSize) StaOperand[++iTop]=value;
}
float iPop()
{
if(iTop>-1)
return StaOperand[iTop--];
return -1.0;
}
void NumsToCapas(char Srcexp[], int slen, char Capaexp[], float NumCapaTab[])
{
char ch;
int i, j, k, flg=0;
int sign;
float val=0.0,power=10.0;
i=0; j=0; k=0;
while (i<slen)
{
ch=Srcexp[i];
if (i==0)
{
sign=(ch=='-')?-1:1;
if(ch=='+'||ch=='-')
{
ch=Srcexp[++i];
flg=1;
}
}
if (isdigit(ch))
{
val=ch-'0';
while (isdigit(ch=Srcexp[++i]))
{
val=val*10.0+ch-'0';
}
if (ch=='.')
{
while(isdigit(ch=Srcexp[++i]))
{
val=val+(ch-'0')/power;
power*=10;
}
} end if
if(flg)
{
val*=sign;
flg=0;
}
} end if
write Capaexp array
write NO.j to array
if(val)
{
Capaexp[k++]='A'+j;
Capaexp[k++]=ch;
NumCapaTab[j++]=val; A--0, B--1,and C, etc.
}
else
{
Capaexp[k++]=ch;
}
val=0.0;
power=10.0;

i++;
}
Capaexp[k]='\0';
operands=j;
}
float CalcRevPolishexp(char validexp[], float NumCapaTab[], char RevPolishexp[], int slen)
{
float sval=0.0, op1,op2;
int i, rt;
char ch;
recursive stack
i=0;
while((ch=RevPolishexp[i]) && i<slen)
{
switch(rt=GetOperator(validexp, ch))
{
case iMUL: op2=iPop(); op1=iPop();
sval=op1*op2;
iPush(sval);
break;
case iDIV: op2=iPop(); op1=iPop();
if(!fabs(op2))
{
printf("overflow\n");
iPush(0);
break;
}
sval=op1/op2;
iPush(sval);
break;
case iADD: op2=iPop(); op1=iPop();
sval=op1+op2;
iPush(sval);
break;
case iSUB: op2=iPop(); op1=iPop();
sval=op1-op2;
iPush(sval);
break;
case iCap: iPush(NumCapaTab[ch-'A']);
break;
default: ;
}
++i;
}
while(iTop>-1)
{
sval=iPop();
}
return sval;
}
int GetOperator(char validexp[],char oper)
{
int oplen,i=0;
oplen=strlen(validexp);
if (!oplen) return -1;
if(isalpha(oper)) return 4;
while(i<oplen && validexp[i]!=oper) ++i;
if(i==oplen || i>=4) return -1;
return i;
}
int CheckExpress(char ch)
{
int i=0;
char ;
while((=validexp[i]) && ch!=) ++i;
if (!)
return 0;
return 1;
}
int PriorChar(char curch, char stach)
{
棧外優先順序高於(>)棧頂優先順序時，才入棧
否則(<=)，一律出棧
if (curch==stach) return 0; 等於時應該出棧
else if (curch=='*' || curch=='/')
{
if(stach!='*' && stach!='/')
return 1;
}
else if (curch=='+' || curch=='-')
{
if (stach=='(' || stach==')')
return 1;
}
else if (curch=='(')
{
if (stach==')')
return 1;
}
return 0;
}
void counterPolishexp(char INexp[], int slen, char Outexp[])
{
int i, j, k,pr;
char t;
i=0;
j=k=0;
while (INexp[i]!='=' && i<slen)
{
if (INexp[i]=='(')
StackSymb[k++]=INexp[i];
iPush(*(INexp+i));
else if(INexp[i]==')')
{
if((t=iPop())!=-1)
while((t=StackSymb[k-1])!='(')
{
Outexp[j++]=t;
k--;
}
k--;
}
else if (CheckExpress(INexp[i])) is oparator
{
printf("operator %c k=%d\n",INexp[i],k);
while (k)
{
iPush(*(INexp+i));
if(pr=PriorChar(INexp[i],StackSymb[k-1]))
break;
else
{
if ((t=iPop())!=-1)
t=StackSymb[k-1]; k--;
Outexp[j++]=t;
}
} end while
StackSymb[k++]=INexp[i]; mon process
}
else if() 變數名
{
printf("operand %c k=%d\n",INexp[i],k);
Outexp[j++]=INexp[i];
}
i++;
}
while (k)
{
t=StackSymb[k-1]; k--;
Outexp[j++]=t;
}
Outexp[j]='\0';
}
註：程式源於「網路知道」

用verilog編寫一個最簡單的加減乘除的計算器的程式
verilog是有加法器乘法器的。也直接識別 + - * / 符號。
mole kjasdja(a,option,b,result);
input option,a,b;
output result;
always @(a,b,option)
begin
result_r=0; 結果暫存器清零
case(option)
+:result_r=a+b;
-:result_r=a-b;
*:result_r=a*b;
/:result_r=a/b;
assign result =result_r;
endmole
大概演演算法就這樣。寫的倉促，語法可能有誤。另外除法reg型別只能儲存整數部分，小數通過移位操作實現，比較麻煩。比如3/5=0.6
做的時候先3=30，然後30/5=6,然後對6在數碼管的顯示進行調整就好。把6顯示在小數點後面1位就好
用vb編寫一個計算器程式，實現加減乘除，
Dim v As Boolean
Dim s As Integer
Dim X As Double
Dim Y As Double
Private Sub Command1_Click(Index As Integer)
If Form1.Tag = "T" Then
If Index = 10 Then
Text1.Text = "0"
Else
Text1.Text = Command1(Index).Caption
End If
Form1.Tag = ""
Else
Text1.Text = Text1.Text & Command1(Index).Caption
End If
End Sub
Private Sub Command2_Click(Index As Integer)
Form1.Tag = "T"
If v Then
X = Val(Text1.Text)
v = Not v
Else
Y = Val(Text1.Text)
Select Case s
Case 0
Text1.Text = X + Y
Case 1
Text1.Text = X - Y
Case 2
Text1.Text = X * Y
Case 3
If Y <> 0 Then
Text1.Text = X / Y
Else
MsgBox ("不能以0為除數")
Text1.Text = X
v = False
End If
Case 4
Y = 0
v = False
End Select
X = Val(Text1.Text)
End If
s = Index
End Sub
Private Sub Frame1_DragDrop(Source As Control, X As Single, Y As Single)
End Sub
控制元件自己新增吧，空間名要和程式碼名一致
求一簡單的加減乘除計算器c++程式
#include<stdio.h>
#include<math.h>
void main()
{
float a,b;
char C;
while(1)
{
scanf("%f%c%f",&a,&C,&b);
if((C!='+')&&(C!='-')&&(C!='*')&&(C!='/'))
break;
switch(C)
{
case '+': printf("%f+%f=%f",a,b,a+b);
break;
case '-': printf("%f-%f=%f",a,b,a-b);
break;
case '*': printf("%f*%f=%f",a,b,a*b);
break;
case '/': printf("%f/%f=%f",a,b,a/b);
break;
}
}
}
想改成按1 2 3 4分別為加減乘除，只需要將程式中的+ - * / 改成1 2 3 4即可。按除了+ - * / 以外的鍵就會退出。
用c++語言編寫一個簡單的計算器程式，會加減乘除就行，本人初學不太會，特訓求幫助
這個是最簡單，簡陋的計算器。很多情況沒考慮進去，例如除數不能為0之類的，真要寫完整的話程式碼還要更多。
程式碼如下： #include <iostream>using namespace std;int main(){ float a, b, result; char operation; cout << "請輸入算式，如1+2並回車：" << endl; cin >> a >> operation >> b; switch(operation) { case '+': result = a + b; break; case '-': result = a - b; break; case '*': result = a * b; break; case '/': result = a / b; break; default: cout << "輸入非法，程式退出！" << endl; return -1; } cout << endl << "結果為：" << endl << a << operation << b << "=" << result << endl; return 0;}

知道switch函式 嗎 用這個就行
建倆個int型變數 一個字元型變數

『貳』 C語言 隨機生成10個加法算式，輸入每個算式的計算結果，判斷計算是否正確，輸出成績

除法沒有校驗，有餘數，輸出整除即可；

#include "stdafx.h"
#include <stdlib.h>
#include <time.h>
int ChoiceFunc(int a, int b,int Suanfa)
{
int result = 0;
switch (Suanfa)
{
case 0:
result = a + b;
break;
case 1:
result = a - b;
break;
case 2:
result = a * b;
break;
case 3:
if (b!=0)
{
result = a / b;
}

break;
default:
break;
}
return result;

}


int main()
{
int a1, b1, c1,jieguo,shuru;
int jishu = 0;
int secore=0;
srand((unsigned)time(NULL));
for (int i = 0; i < 3000; i++)
{
a1 = rand() % 100;
b1 = rand() % 100;
c1 = rand() % 4;
jieguo = ChoiceFunc(a1, b1, c1);
if (jishu<10&&b1!=0)
{

if (jieguo > 0 && jieguo < 100)
{
jishu++;
switch (c1)
{
case 0:
printf("%d+%d= ", a1, b1 );
printf("請輸入結果：");
scanf("%d", &shuru);
if (shuru==jieguo)
{
secore++;
printf("正確 ");
}
break;
case 1:
printf("%d-%d= ", a1, b1);
printf("請輸入結果：");
scanf("%d", &shuru);
if (shuru == jieguo)
{
secore++;
printf("正確 ");
}
break;
case 2:
printf("%d*%d= ", a1, b1);
printf("請輸入結果：");
scanf("%d", &shuru);
if (shuru == jieguo)
{
secore++;
printf("正確 ");
}
break;
case 3:
printf("%d/%d= ", a1, b1);
printf("請輸入結果：");
scanf("%d", &shuru);
if (shuru == jieguo)
{
secore++;
printf("正確 ");
}
break;
default:
break;
}
}


}
else
{
//jishu = 0;
//printf("結束 ");
}
}
printf("結束,分數為%d ", secore);
getchar();
getchar();
return 0;
}

『叄』 c語言簡單加法

正確的代碼如下:
#include<stdio.h>
void main()
{
int a,b,c;
a=6;
b=7;
c=a+b;
printf("c=%d」,c);
}

在你的代碼中最後的輸出是錯誤的，從哪裡來的d，而且你要輸出的是c吧，就算是d你也沒有定義d，C語言的代碼一定要先定義再使用，把最後輸出的d改為c就可以了，還有就是標點符號要注意，不要寫錯，一定要注意，要仔細。

資料擴展

相應的可以寫出求加減乘除的代碼如下:

#include<stdio.h>

void main()

{

int a,b;

scanf("%d%d"&a,&b);

printf("%d ",a+b);

printf("%d ",a-b);

printf("%d ",a*b);

printf("%d ",a/b);

return 0;

}

『肆』 c語言 從鍵盤上隨意輸入一個算術運算式（可能是加、減、乘、除中

#include<stdio.h>
intadd()
{
inta,b,c;
scanf("%d+%d=%d",&a,&b,&c);
if(c==a+b)
returnprintf("yes");
else
returnprintf("no");
}

intsub()
{
inta,b,c;
scanf("%d-%d=%d",&a,&b,&c);
if(c==a-b)
returnprintf("yes");
else
returnprintf("no");
}

intchu()
{
floata,b,c;
scanf("%f/%f=%f",&a,&b,&c);
if(c==a/b)
returnprintf("yes");
else
returnprintf("no");
}

intcheng()
{
inta,b,c;
scanf("%d*%d=%d",&a,&b,&c);
if(c==a*b)
returnprintf("yes");
else
returnprintf("no");
}

intmain()
{
intnum;
printf("1.加法2.減法3.乘法4.除法0.退出
");
printf("selecttype:");
scanf("%d",&num);
switch(num)
{
case1:
add();
break;
case2:
sub();
break;
case3:
cheng();
break;
case4:
chu();
break;
case0:
break;
default:
printf("error");
break;
}
}

『伍』 用c語言實現超長整數的加法運算

#include "stdio.h"
int sum(int a[],int b[],int c[])
{
int i=0,j=0,f=0;
for(;i<21;i++)
{
j=a[i]+b[i]+j;
if(j!=0) f=i;
c[i]=j%10000;
j=j/10000;
}
c[i]=j;
return f;
}
void get(int a[])
{
int n,i,j;
scanf("%d",&n);
j=(n-1)/4;
switch (n%4)
{
case 3:scanf("%3d",&a[j]);break;
case 2:scanf("%2d",&a[j]);break;
case 1:scanf("%1d",&a[j]);break;
case 0:scanf("%4d",&a[j]);break;
}

for(i=j-1;i>=0;i--)
scanf("%4d",&a[i]);
}
void main()
{
static int a[20],b[20],c[21],i,n,f;
char d[80];
get(a);
get(b);
f=sum(a,b,c);
for(i=f;i>=0;i--)
printf("%4d",c[i]);
}

『陸』 C語言怎麼進行加法計算

#include"stdio.h"
voidmain()
{
inta,b,c;
scanf("%d%d",&a,&b);
c=a+b;
printf("%d
",c);
getch();
}

『柒』 c語言加減乘除運算代碼

方法如下：

設備：華為筆記本。

系統：win7。

軟體：Code Blocks。

版本：8.0.11。

1、首先打開Code Blocks軟體，新建一個C語言文件，如下圖所示。

『捌』 c語言程序設計題目 輸出整數加法算式

你這個是什麼網站啊？看到好多在網上提交答案
#include <stdio.h>
void main()
{
int op1, op2, result;
char ch;
scanf("%d%c%d", &op1, &ch, &op2);
result = op1 + op2;
printf("%d%c%d=%d\n", op1, ch, op2, result);
}