❶ sql求時間差，精確到秒分時
多行記錄做這樣的時間差值計算思路：
要將簽入和簽出配對處理，然後才能求出時間差值
或使用隱式游標進行處理，可以求出上一行記錄和下一行記錄的時間差值，但SQL語句極其晦澀難懂。
SQL計算秒的差值為：
selectdatediff(ss,'2019-01-0102:03:04',getdate())
❷ SQL求兩個時間點相減的函數，需求顯示，時、分、秒
select datediff(s,'2012-12-11 8:00:00','2012-12-11 08:31:47')
結果是1907 (秒)
語法
DATEDIFF ( datepart , startdate , enddate )
datepart 縮寫
year yy, yyyy
quarter qq, q
month mm, m
dayofyear dy, y
day dd, d
week wk, ww
hour hh
minute mi, n
second ss, s
millisecond ms
microsecond mcs
nanosecond ns
❸ sql 計算時間差得到時分秒。
declare @day int
declare @hour int
declare @min int
declare @sec int
declare @alls int
set @alls=datediff(s,'2009-11-21 00:00:00','2009-11-24 15:12:24')
set @day=@alls/86400
set @hour=(@alls-@day*86400)/3600
set @min=(@alls-@day*86400-@hour*3600)/60
set @sec=@alls-@day*86400-@hour*3600-@min*60
select CAST(@day as varchar(5))+'天'+CAST(@hour as varchar(2))+'小時'+CAST(@min as varchar(2))+'分'+CAST(@sec as varchar(2))+'秒'
❹ postgresql裡面怎麼得到兩個日期相差多少秒，或者多少分鍾
PostgreSQL中直接用兩個date(或者timestamp)值相減，其返回的是一個interval值，再有該interval值取出天數轉換成分鍾或秒數，再加上interval中分鍾(和秒數)部分的值就可以了。
示例SQL:
selectinterval_value,date_part('day',interval_value)asday_value,date_part('day',interval_value)*24*60+date_part('minute',interval_value)asminutes
from(
select(current_timestamp-to_timestamp('2013-08-:23','yyyy-mm-ddhh24:mi'))asinterval_value
)s;
❺ 求教sql語句兩個日期、時間欄位相減得到天數小時分秒的問題
selectrequestid,userid,workflowid,receivedate,receivetime,operatedate,operatetime,
cast(dayasvarchar)+'天'+cast((hour-day*24)asvarchar)+'小時'+
cast((minute-hour*60)asvarchar)+'分'+
cast((second-minute*60)asvarchar)+'秒'result
from(
selectrequestid,userid,workflowid,receivedate,receivetime,operatedate,operatetime,
datediff(d,CONVERT(datetime,receivedate+''+receivetime,20),
CONVERT(datetime,operatedate+''+operatetime,20))day,
datediff(hh,CONVERT(datetime,receivedate+''+receivetime,20),
CONVERT(datetime,operatedate+''+operatetime,20))hour,
datediff(n,CONVERT(datetime,receivedate+''+receivetime,20),
CONVERT(datetime,operatedate+''+operatetime,20))minute,
datediff(s,CONVERT(datetime,receivedate+''+receivetime,20),
CONVERT(datetime,operatedate+''+operatetime,20))second
fromworkflow_currentoperator
whereworkflowid=297andrequestid=110215
)t
orderbyreceivedate,receivetime
❻ sql~日期格式如何相減
1、簡單介紹一下datediff()函數。
DATEDIFF()函數返回兩個日期之間的天數。
語法：
DATEDIFF(datepart,startdate,enddate)
startdate和enddate參數是合法的日期表達式。
datepart參數可以是下列的值：
