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md5c語言實現

發布時間: 2022-11-15 03:15:19

❶ 國密演算法

國密即國家密碼局認定的國產密碼演算法。主要有SM1,SM2,SM3,SM4。密鑰長度和分組長度均為128位。
SM1 為對稱加密。其加密強度與AES相當。該演算法不公開,調用該演算法時,需要通過加密晶元的介面進行調用。
SM2為非對稱加密,基於ECC。該演算法已公開。由於該演算法基於ECC,故其簽名速度與秘鑰生成速度都快於RSA。ECC 256位(SM2採用的就是ECC 256位的一種)安全強度比RSA 2048位高,但運算速度快於RSA。
國家密碼管理局公布的公鑰演算法,其加密強度為256位
SM3 消息摘要。可以用MD5作為對比理解。該演算法已公開。校驗結果為256位。
SM4 無線區域網標準的分組數據演算法。對稱加密,密鑰長度和分組長度均為128位。

由於SM1、SM4加解密的分組大小為128bit,故對消息進行加解密時,若消息長度過長,需要進行分組,要消息長度不足,則要進行填充。

分組密碼演算法(DES和SM4)、將明文數據按固定長度進行分組,然後在同一密鑰控制下逐組進行加密,
公鑰密碼演算法(RSA和SM2)、公開加密演算法本身和公開公鑰,保存私鑰

摘要演算法(SM3 md5) 這個都比較熟悉,用於數字簽名,消息認證,數據完整性,但是sm3安全度比md5高

總得來說國密演算法的安全度比較高,2010年12月推出,也是國家安全戰略,現在銀行都要要求國際演算法改造,要把國際演算法都給去掉

C 語言實現
https://github.com/guan/GmSSL/

Go 語言
https://github.com/tjfoc/gmsm
https://github.com/ZZMarquis/gm

Java 語言
https://github.com/PopezLotado/SM2Java

Go語言實現,調用 gmsm

❷ 求生成MD5碼的c或c++代碼

自己用c語言寫的簡單的MD5演算法實現。

#include <stdio.h>
#include <stdlib.h>
#include <memory.h>
#include <math.h>

typedef unsigned char BYTE;
typedef unsigned int UINT;
typedef UINT MD5_SUB_ARRAY[16];
typedef UINT MD5_TRANSORM_FUNC(UINT,UINT,UINT);
typedef struct
{
UINT a;
UINT b;
UINT c;
UINT d;
MD5_SUB_ARRAY sub_array;
}MD5_TRANSFORM_PARAM;

const double MAX_INT = (double)0xFFFFFFFF + 1.0;

const UINT MD5_TRANSFORM_MATRIX[4][16][3] =
{

{
{ 0, 7, 1}, { 1,12, 2}, { 2,17, 3}, { 3,22, 4},
{ 4, 7, 5}, { 5,12, 6}, { 6,17, 7}, { 7,22, 8},
{ 8, 7, 9}, { 9,12,10}, {10,17,11}, {11,22,12},
{12, 7,13}, {13,12,14}, {14,17,15}, {15,22,16},
},

{
{ 1, 5,17}, { 6, 9,18}, {11,14,19}, { 0,20,20},
{ 5, 5,21}, {10, 9,22}, {15,14,23}, { 4,20,24},
{ 9, 5,25}, {14, 9,26}, { 3,14,27}, { 8,20,28},
{13, 5,29}, { 2, 9,30}, { 7,14,31}, {12,20,32},
},

{
{5, 4, 33}, { 8,11,34}, {11,16,35},{14, 23,36},
{1, 4, 37}, { 4,11,38}, { 7,16,39},{10, 23,40},
{13,4, 41}, { 0,11,42}, { 3,16,43},{ 6, 23,44},
{9, 4, 45}, {12,11,46}, {15,16,47},{ 2, 23,48},
},

{
{ 0,6,49}, { 7,10,50}, {14,15,51},{ 5, 21,52},
{12,6,53}, { 3,10,54}, {10,15,55},{ 1, 21,56},
{ 8,6,57}, {15,10,58}, { 6,15,59},{13, 21,60},
{ 4,6,61}, {11,10,62}, { 2,15,63},{ 9, 21,64},
},
};

static UINT MD5_TRANSFORM_ARRAY[65];

void MD5_Init()
{
int x;
for(x = 1; x <= 64; x++)
{
MD5_TRANSFORM_ARRAY[x] = (UINT)(MAX_INT * fabs(sin(x)));
}
}

UINT F(UINT x,UINT y,UINT z)
{
return ((x & y) | ((~x) & z));
}

UINT G(UINT x,UINT y,UINT z)
{
return ((x & z) | (y & (~z)));
}

UINT H(UINT x,UINT y,UINT z)
{
return (x ^ y ^ z);
}

UINT I(UINT x,UINT y,UINT z)
{
return (y ^ (x | (~z)));
}

BYTE* MD5_prepare_data(const BYTE* data,int len,int* new_len)
{
int rest,fill,size;
BYTE* new_data;
UINT bit_len;

// (1) 位元組補齊
rest = len % 56;
if (rest <= 56) fill = 56 - rest;
else fill = (64 - rest) + 56;

new_data = (BYTE*)malloc(len + fill + 8);
if (NULL == new_data) return NULL;

if (len > 0) memcpy(new_data,data,len);
if (fill > 0) memset(new_data + len,0x80,1);
if (fill > 1) memset(new_data + len + 1,0,fill - 1);

size = fill + len;

// (2) 附加數據的比特長度
bit_len = len * 8;
// (64位二進制數表示的)比特長度的低32位
memset(new_data + size + 0,(bit_len & 0x000000FF), 1);
memset(new_data + size + 1,(bit_len & 0x0000FF00) >> 8, 1);
memset(new_data + size + 2,(bit_len & 0x00FF0000) >> 16,1);
memset(new_data + size + 3,(bit_len & 0xFF000000) >> 24,1);
// 不考慮比特長度超出32位無符號數表示範圍,所以高32位總是0
memset(new_data + size + 4,0,4);

*new_len = size + 8;

return new_data;
}

void MD5_transform(MD5_TRANSFORM_PARAM* param,int ring,MD5_TRANSORM_FUNC func)
{
UINT a,b,c,d,s,k,i;
UINT abcd[4];
UINT *X,*T;
int index;

abcd[0] = param->a;
abcd[1] = param->b;
abcd[2] = param->c;
abcd[3] = param->d;
X = param->sub_array;
T = MD5_TRANSFORM_ARRAY;

for(index = 0; index < 16; index++)
{
a = abcd[(3 * index + 0) % 4];
b = abcd[(3 * index + 1) % 4];
c = abcd[(3 * index + 2) % 4];
d = abcd[(3 * index + 3) % 4];

k = MD5_TRANSFORM_MATRIX[ring][index][0];
s = MD5_TRANSFORM_MATRIX[ring][index][1];
i = MD5_TRANSFORM_MATRIX[ring][index][2];

a = a + func(b,c,d) + X[k] + T[i];
a = ( a << s) | ( a >> (32 - s)); // 循環左移
a = a + b;

abcd[(3 * index + 0) % 4] = a;
}

param->a = abcd[0];
param->b = abcd[1];
param->c = abcd[2];
param->d = abcd[3];
}

int MD5(const BYTE* data,int len)
{
int x,y,new_len;
MD5_TRANSFORM_PARAM param;
UINT AA,BB,CC,DD;
BYTE* buf;

MD5_Init();

buf = MD5_prepare_data(data,len,&new_len);
if (buf == NULL) return -1;

AA = 0x67452301;
BB = 0xefcdab89;
CC = 0x98badcfe;
DD = 0x10325476;

for(x = 0; x < new_len / 64; x++)
{
param.a = AA;
param.b = BB;
param.c = CC;
param.d = DD;

for(y = 0; y < 16; y++)
{
param.sub_array[y] = buf[64 * x + 4 * y + 0];
param.sub_array[y] += buf[64 * x + 4 * y + 1] << 8;
param.sub_array[y] += buf[64 * x + 4 * y + 2] << 16;
param.sub_array[y] += buf[64 * x + 4 * y + 3] << 24;
}
MD5_transform(¶m,0,F);
MD5_transform(¶m,1,G);
MD5_transform(¶m,2,H);
MD5_transform(¶m,3,I);

AA += param.a;
BB += param.b;
CC += param.c;
DD += param.d;
}

printf("MD5(\"%s\")=",data);

printf("%02X%02X%02X%02X",
(AA & 0x000000FF),
(AA & 0x0000FF00) >> 8,
(AA & 0x00FF0000) >> 16,
(AA & 0xFF000000) >> 24);

printf("%02X%02X%02X%02X",
(BB & 0x000000FF),
(BB & 0x0000FF00) >> 8,
(BB & 0x00FF0000) >> 16,
(BB & 0xFF000000) >> 24);

printf("%02X%02X%02X%02X",
(CC & 0x000000FF),
(CC & 0x0000FF00) >> 8,
(CC & 0x00FF0000) >> 16,
(CC & 0xFF000000) >> 24);

printf("%02X%02X%02X%02X",
(DD & 0x000000FF),
(DD & 0x0000FF00) >> 8,
(DD & 0x00FF0000) >> 16,
(DD & 0xFF000000) >> 24);

printf("\n");

return 0;
}

int main()
{
MD5("",0);
MD5("a",1);
MD5("abc",3);
MD5("message digest",14);
MD5("abcdefghijklmnopqrstuvwxyz",26);

return 0;
}

❸ 用c語言實現python的md5功能

題中所示代碼中,python實現了計算空字元串的MD5值,並對MD5的值的十六進制的字元串所表示的位元組進行BASE64處理。

不像Python內部有實現md5功能,根據ANSI C標准,C語言的標准庫里是沒有md5功能的;

但是RFC1231規定了MD5功能的C實現並提供了附件,可以直接用,也可以直接獲取現成的實現,在編譯鏈接時指定正確的.h頭文件和.lib靜態鏈接庫文件;

這里我採取前者的做法(電腦上沒有裝VC,有VC就簡單很多,使用的是minGW)大概六七百行代碼左右。

然後這里展示不完,給個實現效果圖

BASE64的編碼原理

❹ C語言求文件MD5的函數用法

C語言沒有內置的MD5函數,可以在以下頁面找到C語言實現程序和MD5的演算法介紹:

http://tools.ietf.org/html/rfc1321

❺ md5是什麼 如何計算MD5

MD5即Message-Digest Algorithm 5(信息-摘要演算法5),用於確保信息傳輸完整一致。是計算機廣泛使用的雜湊演算法之一(又譯摘要演算法、哈希演算法),主流編程語言普遍已有MD5實現。

MD5演算法具有以下特點:

1、壓縮性:任意長度的數據,算出的MD5值長度都是固定的。

2、容易計算:從原數據計算出MD5值很容易。

3、抗修改性:對原數據進行任何改動,哪怕只修改1個位元組,所得到的MD5值都有很大區別。

4、強抗碰撞:已知原數據和其MD5值,想找到一個具有相同MD5值的數據(即偽造數據)是非常困難的。

MD5的作用是讓大容量信息在用數字簽名軟體簽署私人密鑰前被"壓縮"成一種保密的格式(就是把一個任意長度的位元組串變換成一定長的16進制數字串)。

大家都知道,地球上任何人都有自己獨一無二的指紋,這常常成為司法機關鑒別罪犯身份最值得信賴的方法;與之類似,MD5就可以為任何文件(不管其大小、格式、數量)產生一個同樣獨一無二的MD5「數字指紋」,如果任何人對文件做了任何改動,其MD5也就是對應的「數字指紋」都會發生變化。

❻ ubuntu下鏈接c語言實現md5出錯

你的命令寫得有問題:
gcc -o main.o md5.o
-o參數用來指定輸出文件名,你這里把main.o傳給它了,試試:
gcc -o app main.o md5.o
其實你可以直接一步完成:
gcc md5.c main.c -o main

❼ C語言怎麼實現對一長串字元進行MD5加密

#include<stdio.h>
#include<stdlib.h>

#defineARR_LEN100

#defineF(x,y,z)((x&y)|(~x&z))
#defineG(x,y,z)((x&z)|(y&~z))
#defineH(x,y,z)(x^y^z)
#defineI(x,y,z)(y^(x|~z))
#defineROTATE_LEFT(x,n)((x<<n)|(x>>(32-n)))
#defineFF(a,b,c,d,x,s,ac)
{
a+=F(b,c,d)+x+ac;
a=ROTATE_LEFT(a,s);
a+=b;
}
#defineGG(a,b,c,d,x,s,ac)
{
a+=G(b,c,d)+x+ac;
a=ROTATE_LEFT(a,s);
a+=b;
}
#defineHH(a,b,c,d,x,s,ac)
{
a+=H(b,c,d)+x+ac;
a=ROTATE_LEFT(a,s);
a+=b;
}
#defineII(a,b,c,d,x,s,ac)
{
a+=I(b,c,d)+x+ac;
a=ROTATE_LEFT(a,s);
a+=b;
}

typedefstruct{
unsignedintcount[2];
unsignedintstate[4];
unsignedcharbuffer[64];
}MD5_CTX;

voidMD5Init(MD5_CTX*context);
voidMD5Update(MD5_CTX*context,unsignedchar*input,unsignedintinputlen);
voidMD5Final(MD5_CTX*context,unsignedchardigest[16]);
voidMD5Transform(unsignedintstate[4],unsignedcharblock[64]);
voidMD5Encode(unsignedchar*output,unsignedint*input,unsignedintlen);
voidMD5Decode(unsignedint*output,unsignedchar*input,unsignedintlen);

unsignedcharPADDING[]={
0x80,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,
0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,
0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,
0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0
};

voidMD5Init(MD5_CTX*context){
context->count[0]=0;
context->count[1]=0;
context->state[0]=0x67452301;
context->state[1]=0xEFCDAB89;
context->state[2]=0x98BADCFE;
context->state[3]=0x10325476;
}

voidMD5Update(MD5_CTX*context,unsignedchar*input,unsignedintinputlen){
unsignedinti=0,index=0,partlen=0;
index=(context->count[0]>>3)&0x3F;
partlen=64-index;
context->count[0]+=inputlen<<3;
if(context->count[0]<(inputlen<<3))
context->count[1]++;
context->count[1]+=inputlen>>29;

if(inputlen>=partlen){
memcpy(&context->buffer[index],input,partlen);
MD5Transform(context->state,context->buffer);
for(i=partlen;i+64<=inputlen;i+=64)
MD5Transform(context->state,&input[i]);
index=0;
}
else{
i=0;
}
memcpy(&context->buffer[index],&input[i],inputlen-i);
}

voidMD5Final(MD5_CTX*context,unsignedchardigest[16]){
unsignedintindex=0,padlen=0;
unsignedcharbits[8];
index=(context->count[0]>>3)&0x3F;
padlen=(index<56)?(56-index):(120-index);
MD5Encode(bits,context->count,8);
MD5Update(context,PADDING,padlen);
MD5Update(context,bits,8);
MD5Encode(digest,context->state,16);
}

voidMD5Encode(unsignedchar*output,unsignedint*input,unsignedintlen){
unsignedinti=0,j=0;
while(j<len){
output[j]=input[i]&0xFF;
output[j+1]=(input[i]>>8)&0xFF;
output[j+2]=(input[i]>>16)&0xFF;
output[j+3]=(input[i]>>24)&0xFF;
i++;
j+=4;
}
}

voidMD5Decode(unsignedint*output,unsignedchar*input,unsignedintlen){
unsignedinti=0,j=0;
while(j<len){
output[i]=(input[j])|
(input[j+1]<<8)|
(input[j+2]<<16)|
(input[j+3]<<24);
i++;
j+=4;
}
}

voidMD5Transform(unsignedintstate[4],unsignedcharblock[64]){
unsignedinta=state[0];
unsignedintb=state[1];
unsignedintc=state[2];
unsignedintd=state[3];
unsignedintx[64];
MD5Decode(x,block,64);
FF(a,b,c,d,x[0],7,0xd76aa478);/*1*/
FF(d,a,b,c,x[1],12,0xe8c7b756);/*2*/
FF(c,d,a,b,x[2],17,0x242070db);/*3*/
FF(b,c,d,a,x[3],22,0xc1bdceee);/*4*/
FF(a,b,c,d,x[4],7,0xf57c0faf);/*5*/
FF(d,a,b,c,x[5],12,0x4787c62a);/*6*/
FF(c,d,a,b,x[6],17,0xa8304613);/*7*/
FF(b,c,d,a,x[7],22,0xfd469501);/*8*/
FF(a,b,c,d,x[8],7,0x698098d8);/*9*/
FF(d,a,b,c,x[9],12,0x8b44f7af);/*10*/
FF(c,d,a,b,x[10],17,0xffff5bb1);/*11*/
FF(b,c,d,a,x[11],22,0x895cd7be);/*12*/
FF(a,b,c,d,x[12],7,0x6b901122);/*13*/
FF(d,a,b,c,x[13],12,0xfd987193);/*14*/
FF(c,d,a,b,x[14],17,0xa679438e);/*15*/
FF(b,c,d,a,x[15],22,0x49b40821);/*16*/

/*Round2*/
GG(a,b,c,d,x[1],5,0xf61e2562);/*17*/
GG(d,a,b,c,x[6],9,0xc040b340);/*18*/
GG(c,d,a,b,x[11],14,0x265e5a51);/*19*/
GG(b,c,d,a,x[0],20,0xe9b6c7aa);/*20*/
GG(a,b,c,d,x[5],5,0xd62f105d);/*21*/
GG(d,a,b,c,x[10],9,0x2441453);/*22*/
GG(c,d,a,b,x[15],14,0xd8a1e681);/*23*/
GG(b,c,d,a,x[4],20,0xe7d3fbc8);/*24*/
GG(a,b,c,d,x[9],5,0x21e1cde6);/*25*/
GG(d,a,b,c,x[14],9,0xc33707d6);/*26*/
GG(c,d,a,b,x[3],14,0xf4d50d87);/*27*/
GG(b,c,d,a,x[8],20,0x455a14ed);/*28*/
GG(a,b,c,d,x[13],5,0xa9e3e905);/*29*/
GG(d,a,b,c,x[2],9,0xfcefa3f8);/*30*/
GG(c,d,a,b,x[7],14,0x676f02d9);/*31*/
GG(b,c,d,a,x[12],20,0x8d2a4c8a);/*32*/

/*Round3*/
HH(a,b,c,d,x[5],4,0xfffa3942);/*33*/
HH(d,a,b,c,x[8],11,0x8771f681);/*34*/
HH(c,d,a,b,x[11],16,0x6d9d6122);/*35*/
HH(b,c,d,a,x[14],23,0xfde5380c);/*36*/
HH(a,b,c,d,x[1],4,0xa4beea44);/*37*/
HH(d,a,b,c,x[4],11,0x4bdecfa9);/*38*/
HH(c,d,a,b,x[7],16,0xf6bb4b60);/*39*/
HH(b,c,d,a,x[10],23,0xbebfbc70);/*40*/
HH(a,b,c,d,x[13],4,0x289b7ec6);/*41*/
HH(d,a,b,c,x[0],11,0xeaa127fa);/*42*/
HH(c,d,a,b,x[3],16,0xd4ef3085);/*43*/
HH(b,c,d,a,x[6],23,0x4881d05);/*44*/
HH(a,b,c,d,x[9],4,0xd9d4d039);/*45*/
HH(d,a,b,c,x[12],11,0xe6db99e5);/*46*/
HH(c,d,a,b,x[15],16,0x1fa27cf8);/*47*/
HH(b,c,d,a,x[2],23,0xc4ac5665);/*48*/

/*Round4*/
II(a,b,c,d,x[0],6,0xf4292244);/*49*/
II(d,a,b,c,x[7],10,0x432aff97);/*50*/
II(c,d,a,b,x[14],15,0xab9423a7);/*51*/
II(b,c,d,a,x[5],21,0xfc93a039);/*52*/
II(a,b,c,d,x[12],6,0x655b59c3);/*53*/
II(d,a,b,c,x[3],10,0x8f0ccc92);/*54*/
II(c,d,a,b,x[10],15,0xffeff47d);/*55*/
II(b,c,d,a,x[1],21,0x85845dd1);/*56*/
II(a,b,c,d,x[8],6,0x6fa87e4f);/*57*/
II(d,a,b,c,x[15],10,0xfe2ce6e0);/*58*/
II(c,d,a,b,x[6],15,0xa3014314);/*59*/
II(b,c,d,a,x[13],21,0x4e0811a1);/*60*/
II(a,b,c,d,x[4],6,0xf7537e82);/*61*/
II(d,a,b,c,x[11],10,0xbd3af235);/*62*/
II(c,d,a,b,x[2],15,0x2ad7d2bb);/*63*/
II(b,c,d,a,x[9],21,0xeb86d391);/*64*/
state[0]+=a;
state[1]+=b;
state[2]+=c;
state[3]+=d;
}

intmain(intargc,char*argv[]){
inti;
unsignedcharencrypt[ARR_LEN];
unsignedchardecrypt[16];
MD5_CTXmd5;

printf("【測試1】 ");
printf("加密前:Bai ");
printf("加密後: ");
printf(" ");
printf("【測試2】 ");
printf("加密前:Bihaifeng ");
printf("加密後: ");
printf(" ");
printf("====================================================== ");

printf("請輸入需MD5加密的字元串: ");
gets(encrypt);
printf(" ");
printf("====================================================== ");

MD5Init(&md5);
MD5Update(&md5,encrypt,strlen((char*)encrypt));
MD5Final(&md5,decrypt);

printf("加密前:%s 加密後:",encrypt);
for(i=0;i<16;i++){
printf("%02x",decrypt[i]);
}
printf(" ");

getch();
return0;
}

運行結果

以上源代碼非原創~~

❽ 請教MD5演算法 用C語言實現

#include<stdio.h>
#include<stdlib.h>
#include<string.h>
#ifdefined(__APPLE__)
#defineCOMMON_DIGEST_FOR_OPENSSL
#include<CommonCrypto/CommonDigest.h>
#defineSHA1CC_SHA1
#else
#include<openssl/md5.h>
#endif

//這是我自己寫的函數,用於計算MD5
//參數str:要轉換的字元串
//參數lengthL:字元串的長度可以用strlen(str)直接獲取參數str的長度
//返回值:MD5字元串
char*str2md5(constchar*str,intlength){
intn;
MD5_CTXc;
unsignedchardigest[16];
char*out=(char*)malloc(33);

MD5_Init(&c);

while(length>0){
if(length>512){
MD5_Update(&c,str,512);
}else{
MD5_Update(&c,str,length);
}
length-=512;
str+=512;
}

MD5_Final(digest,&c);

for(n=0;n<16;++n){
snprintf(&(out[n*2]),16*2,"%02x",(unsignedint)digest[n]);
}

returnout;
}

intmain(intargc,char**argv){
char*output=str2md5("hello",strlen("hello"));

printf("%s ",output);
//上面會輸出hello的MD5字元串:
//
free(output);
return0;
}

❾ 高分求解c語言的簡單文件加解密

用C語言實現MD5演算法用C語言實現MD5演算法,這個夠復雜。。。

""用C語言實現MD5演算法.
1)global.h 頭文件
#ifndef PROTOTYPES
#define PROTOTYPES 0
#endif
/* POINTER defines a generic pointer type */
typedef unsigned char *POINTER;
/* UINT4 defines a four byte word */
typedef unsigned long int UINT4;
/* PROTO_LIST is defined depending on how PROTOTYPES is defined
above.If using PROTOTYPES, then PROTO_LIST returns the list, otherwise
it returns an empty list. */
#if PROTOTYPES
#define PROTO_LIST(list) list
#else
#define PROTO_LIST(list) ()
#endif
2)md5.h 頭文件
/* MD5 context. */
typedef struct {
UINT4 state[4]; /* state (ABCD) */
UINT4 count[2]; /* number of bits, molo 2^64 (lsb first) */
unsigned char buffer[64]; /* input buffer */
} MD5_CTX;
void MD5Init PROTO_LIST ((MD5_CTX *));
void MD5Update PROTO_LIST
((MD5_CTX *, unsigned char *, unsigned int));
void MD5Final PROTO_LIST ((unsigned char [16], MD5_CTX *));
3)md5c.c 演算法的核心部分
/* 參考 RSA Data Security, Inc., MD5 message-digest algorithm 的C源程

*/
#include "global.h"
#include "md5.h"
/* MD5的主循環的輪主要操作為a=b+((a+f(b,c,d)+M+t)<<值如下:
*/
#define S11 7
#define S12 12
#define S13 17
#define S14 22
#define S21 5
#define S22 9
#define S23 14
#define S24 20
#define S31 4
#define S32 11
#define S33 16
#define S34 23
#define S41 6
#define S42 10
#define S43 15
#define S44 21
/*函數調用說明*/
static void MD5Transform PROTO_LIST ((UINT4 [4], unsigned char [64]));
static void Encode PROTO_LIST
((unsigned char *, UINT4 *, unsigned int));
static void Decode PROTO_LIST
((UINT4 *, unsigned char *, unsigned int));
static void MD5_memcpy PROTO_LIST ((POINTER, POINTER, unsigned
int));
static void MD5_memset PROTO_LIST ((POINTER, int, unsigned int));
static unsigned char PADDING[64] = {
0x80, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0,
0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0,
0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0
};
/* F, G, H and I 是MD5的基本函數.
*/
#define F(x, y, z) (((x) & (y)) | ((~x) & (z)))
#define G(x, y, z) (((x) & (z)) | ((y) & (~z)))
#define H(x, y, z) ((x) ^ (y) ^ (z))
#define I(x, y, z) ((y) ^ ((x) | (~z)))
/* ROTATE_LEFT將 x 循環左移n bits. */
#define ROTATE_LEFT(x, n) (((x) <> (32-(n))))
/* FF, GG, HH, and II 代表1,2,3,4輪計算,先宏定義以便於後面引用.
*/
#define FF(a, b, c, d, x, s, ac) { \
(a) += F ((b), (c), (d)) + (x) + (UINT4)(ac); \
(a) = ROTATE_LEFT ((a), (s)); \
(a) += (b); \
}
#define GG(a, b, c, d, x, s, ac) { \
(a) += G ((b), (c), (d)) + (x) + (UINT4)(ac); \
(a) = ROTATE_LEFT ((a), (s)); \
(a) += (b); \
}
#define HH(a, b, c, d, x, s, ac) { \
(a) += H ((b), (c), (d)) + (x) + (UINT4)(ac); \
(a) = ROTATE_LEFT ((a), (s)); \
(a) += (b); \
}
#define II(a, b, c, d, x, s, ac) { \
(a) += I ((b), (c), (d)) + (x) + (UINT4)(ac); \
(a) = ROTATE_LEFT ((a), (s)); \
(a) += (b); \
}
/* MD5 的初始化, MD5 操作的開始. */
void MD5Init (context)
MD5_CTX *context; /* context */
{
context->count[0] = context->count[1] = 0;
/* 給出4個32比特的初始向量.*/
context->state[0] = 0x67452301;
context->state[1] = 0xefcdab89;
context->state[2] = 0x98badcfe;
context->state[3] = 0x10325476;
}
/* MD5 塊更新操作.不斷地對消息塊進行MD5 消息-摘要操作,並更新
context.
*/
void MD5Update (context, input, inputLen)
MD5_CTX *context; /* context */
unsigned char *input; /* input block */
unsigned int inputLen; /* length of input block */
{
unsigned int i, index, partLen;
/* Compute number of bytes mod 64 */
index = (unsigned int)((context->count[0] >> 3) & 0x3F);
/* Update number of bits */
if ((context->count[0] += ((UINT4)inputLen << 3))
< ((UINT4)inputLen context->count[1] += ((UINT4)inputLen >> 29);
partLen = 64 - index;
/* Transform as many times as possible.
*/
if (inputLen >= partLen) {
MD5_memcpy
((POINTER)&context->buffer[index], (POINTER)input, partLen);
MD5Transform (context->state, context->buffer);
for (i = partLen; i + 63 state, &input);
index = 0;
}
else
i = 0;
/* Buffer remaining input */
MD5_memcpy
((POINTER)&context->buffer[index], (POINTER)&input,
inputLen-i);
}
/* MD5 的結束操作. 輸出128比特的散列值並對context歸零.
*/
void MD5Final (digest, context)
unsigned char digest[16]; /* message digest */
MD5_CTX *context; /*
context */
{
unsigned char bits[8];
unsigned int index, padLen;
/* Save number of bits */
Encode (bits, context->count, 8);
/* Pad out to 56 mod 64.
*/
index = (unsigned int)((context->count[0] >> 3) & 0x3f);
padLen = (index state, 16);
/* Zeroize sensitive information.
*/
MD5_memset ((POINTER)context, 0, sizeof (*context));
}
/* 對一個消息塊的16個子塊進行MD5 基本計算.
*/
static void MD5Transform (state, block)
UINT4 state[4];
unsigned char block[64];
{
UINT4 a = state[0], b = state[1], c = state[2], d = state[3], x[16];
Decode (x, block, 64);
/* Round 1 */
FF (a, b, c, d, x[ 0], S11, 0xd76aa478); /* 1 */
FF (d, a, b, c, x[ 1], S12, 0xe8c7b756); /* 2 */
FF (c, d, a, b, x[ 2], S13, 0x242070db); /* 3 */
FF (b, c, d, a, x[ 3], S14, 0xc1bdceee); /* 4 */
FF (a, b, c, d, x[ 4], S11, 0xf57c0faf); /* 5 */
FF (d, a, b, c, x[ 5], S12, 0x4787c62a); /* 6 */
FF (c, d, a, b, x[ 6], S13, 0xa8304613); /* 7 */
FF (b, c, d, a, x[ 7], S14, 0xfd469501); /* 8 */
FF (a, b, c, d, x[ 8], S11, 0x698098d8); /* 9 */
FF (d, a, b, c, x[ 9], S12, 0x8b44f7af); /* 10 */
FF (c, d, a, b, x[10], S13, 0xffff5bb1); /* 11 */
FF (b, c, d, a, x[11], S14, 0x895cd7be); /* 12 */
FF (a, b, c, d, x[12], S11, 0x6b901122); /* 13 */
FF (d, a, b, c, x[13], S12, 0xfd987193); /* 14 */
FF (c, d, a, b, x[14], S13, 0xa679438e); /* 15 */
FF (b, c, d, a, x[15], S14, 0x49b40821); /* 16 */
/* Round 2 */
GG (a, b, c, d, x[ 1], S21, 0xf61e2562); /* 17 */
GG (d, a, b, c, x[ 6], S22, 0xc040b340); /* 18 */
GG (c, d, a, b, x[11], S23, 0x265e5a51); /* 19 */
GG (b, c, d, a, x[ 0], S24, 0xe9b6c7aa); /* 20 */
GG (a, b, c, d, x[ 5], S21, 0xd62f105d); /* 21 */
GG (d, a, b, c, x[10], S22, 0x2441453); /* 22 */
GG (c, d, a, b, x[15], S23, 0xd8a1e681); /* 23 */
GG (b, c, d, a, x[ 4], S24, 0xe7d3fbc8); /* 24 */
GG (a, b, c, d, x[ 9], S21, 0x21e1cde6); /* 25 */
GG (d, a, b, c, x[14], S22, 0xc33707d6); /* 26 */
GG (c, d, a, b, x[ 3], S23, 0xf4d50d87); /* 27 */
GG (b, c, d, a, x[ 8], S24, 0x455a14ed); /* 28 */
GG (a, b, c, d, x[13], S21, 0xa9e3e905); /* 29 */
GG (d, a, b, c, x[ 2], S22, 0xfcefa3f8); /* 30 */
GG (c, d, a, b, x[ 7], S23, 0x676f02d9); /* 31 */
GG (b, c, d, a, x[12], S24, 0x8d2a4c8a); /* 32 */
/* Round 3 */
HH (a, b, c, d, x[ 5], S31, 0xfffa3942); /* 33 */
HH (d, a, b, c, x[ 8], S32, 0x8771f681); /* 34 */
HH (c, d, a, b, x[11], S33, 0x6d9d6122); /* 35 */
HH (b, c, d, a, x[14], S34, 0xfde5380c); /* 36 */
HH (a, b, c, d, x[ 1], S31, 0xa4beea44); /* 37 */
HH (d, a, b, c, x[ 4], S32, 0x4bdecfa9); /* 38 */
HH (c, d, a, b, x[ 7], S33, 0xf6bb4b60); /* 39 */
HH (b, c, d, a, x[10], S34, 0xbebfbc70); /* 40 */
HH (a, b, c, d, x[13], S31, 0x289b7ec6); /* 41 */
HH (d, a, b, c, x[ 0], S32, 0xeaa127fa); /* 42 */
HH (c, d, a, b, x[ 3], S33, 0xd4ef3085); /* 43 */
HH (b, c, d, a, x[ 6], S34, 0x4881d05); /* 44 */
HH (a, b, c, d, x[ 9], S31, 0xd9d4d039); /* 45 */
HH (d, a, b, c, x[12], S32, 0xe6db99e5); /* 46 */
HH (c, d, a, b, x[15], S33, 0x1fa27cf8); /* 47 */
HH (b, c, d, a, x[ 2], S34, 0xc4ac5665); /* 48 */
/* Round 4 */
II (a, b, c, d, x[ 0], S41, 0xf4292244); /* 49 */
II (d, a, b, c, x[ 7], S42, 0x432aff97); /* 50 */
II (c, d, a, b, x[14], S43, 0xab9423a7); /* 51 */
II (b, c, d, a, x[ 5], S44, 0xfc93a039); /* 52 */
II (a, b, c, d, x[12], S41, 0x655b59c3); /* 53 */
II (d, a, b, c, x[ 3], S42, 0x8f0ccc92); /* 54 */
II (c, d, a, b, x[10], S43, 0xffeff47d); /* 55 */
II (b, c, d, a, x[ 1], S44, 0x85845dd1); /* 56 */
II (a, b, c, d, x[ 8], S41, 0x6fa87e4f); /* 57 */
II (d, a, b, c, x[15], S42, 0xfe2ce6e0); /* 58 */
II (c, d, a, b, x[ 6], S43, 0xa3014314); /* 59 */
II (b, c, d, a, x[13], S44, 0x4e0811a1); /* 60 */
II (a, b, c, d, x[ 4], S41, 0xf7537e82); /* 61 */
II (d, a, b, c, x[11], S42, 0xbd3af235); /* 62 */
II (c, d, a, b, x[ 2], S43, 0x2ad7d2bb); /* 63 */
II (b, c, d, a, x[ 9], S44, 0xeb86d391); /* 64 */
state[0] += a;
state[1] += b;
state[2] += c;
state[3] += d;
/* Zeroize sensitive information.
*/
MD5_memset ((POINTER)x, 0, sizeof (x));
}
/* Encodes input (UINT4) into output (unsigned char). Assumes len is
a multiple of 4. */
static void Encode (output, input, len)
unsigned char *output;
UINT4 *input;
unsigned int len;
{ unsigned int i, j;
for (i = 0, j = 0; j > 8) & 0xff);
output[j+2] = (unsigned char)((input >> 16) & 0xff);
output[j+3] = (unsigned char)((input >> 24) & 0xff);
}
}
/* Decodes input (unsigned char) into output (UINT4). Assumes len is a
multiple of 4. */
static void Decode (output, input, len)
UINT4 *output;
unsigned char *input;
unsigned int len;
{
unsigned int i, j;
for (i = 0, j = 0; j < len; i++, j += 4)
output = ((UINT4)input[j]) | (((UINT4)input[j+1]) << 8) |
(((UINT4)input[j+2]) << 16) | (((UINT4)input[j+3]) << 24);
}
/* Note: Replace "for loop" with standard memcpy if possible. */
static void MD5_memcpy (output, input, len)
POINTER output;
POINTER input;
unsigned int len;
{ unsigned int i;
for (i = 0; i < len; i++)
output = input;
}
/* Note: Replace "for loop" with standard memset if possible. */
static void MD5_memset (output, value, len)
POINTER output;
int value;
unsigned int len;
{ unsigned int i;
for (i = 0; i < len; i++)
((char *)output) = (char)value;
}
4)md5test.c 主測試程序
/* MD5測試程序 */
#include
#include
#include "global.h"
#include "md5.h"
/* Length of test block, number of test blocks. */
static void MDString PROTO_LIST ((char *));
static void MDFilter PROTO_LIST ((void));
static void MDPrint PROTO_LIST ((unsigned char [16]));
/* Prints a message digest in hexadecimal.(十六進制) */
static void MDPrint (digest)
unsigned char digest[16];
{
unsigned int i;
printf("\n");
for (i = 0; i < 16; i++)
printf ("%02x", digest);
}
/* Digests the standard input and prints the result. */
static void MDFilter ()
{
MD5_CTX context;
int len;
unsigned char buffer[16], digest[16];
MD5Init (&context);
while (len = fread (buffer, 1, 16, stdin))
MD5Update (&context, buffer, len);
MD5Final (digest, &context);
MDPrint (digest);
printf ("\n");
}
/* Digests a string and prints the result. */
static void MDString (string)
char *string;
{
MD5_CTX context;
unsigned char digest[16];
unsigned int len = strlen (string);
MD5Init (&context);
MD5Update (&context, string, len);
MD5Final (digest, &context);
printf ("%s = ", string);
MDPrint (digest);
printf ("\n");
}
void main ()
{
printf ("MD5演算法測試:\n");
printf ("原文=\n");
printf ("MD5消息摘要\n");
MDString ("\n趙濤");
MDString ("\n合肥電大站 學號:01230100015");
MDString
("\
123456789");
}

❿ 求一個簡單的md5加密程序C或C++代碼

C語言實現MD5演算法
#include<stdio.h>

#define F(x, y, z) (((x) & (y)) | ((~x) & (z)))
#define G(x, y, z) (((x) & (z)) | ((y) & (~z)))
#define H(x, y, z) ((x) ^ (y) ^ (z))
#define I(x, y, z) ((y) ^ ((x) | (~z)))

#define RL(x, y) (((x) << (y)) | ((x) >> (32 - (y)))) //x向左循環移y位

#define PP(x) (x<<24)|((x<<8)&0xff0000)|((x>>8)&0xff00)|(x>>24) //將x高低位互換,例如PP(aabbccdd)=ddccbbaa

#define FF(a, b, c, d, x, s, ac) a = b + (RL((a + F(b,c,d) + x + ac),s))
#define GG(a, b, c, d, x, s, ac) a = b + (RL((a + G(b,c,d) + x + ac),s))
#define HH(a, b, c, d, x, s, ac) a = b + (RL((a + H(b,c,d) + x + ac),s))
#define II(a, b, c, d, x, s, ac) a = b + (RL((a + I(b,c,d) + x + ac),s))

unsigned A,B,C,D,a,b,c,d,i,len,flen[2],x[16]; //i臨時變數,len文件長,flen[2]為64位二進製表示的文件初始長度
char filename[200]; //文件名
FILE *fp;

void md5(){ //MD5核心演算法,供64輪

a=A,b=B,c=C,d=D;
/**//* Round 1 */
FF (a, b, c, d, x[ 0], 7, 0xd76aa478); /**//* 1 */
FF (d, a, b, c, x[ 1], 12, 0xe8c7b756); /**//* 2 */
FF (c, d, a, b, x[ 2], 17, 0x242070db); /**//* 3 */
FF (b, c, d, a, x[ 3], 22, 0xc1bdceee); /**//* 4 */
FF (a, b, c, d, x[ 4], 7, 0xf57c0faf); /**//* 5 */
FF (d, a, b, c, x[ 5], 12, 0x4787c62a); /**//* 6 */
FF (c, d, a, b, x[ 6], 17, 0xa8304613); /**//* 7 */
FF (b, c, d, a, x[ 7], 22, 0xfd469501); /**//* 8 */
FF (a, b, c, d, x[ 8], 7, 0x698098d8); /**//* 9 */
FF (d, a, b, c, x[ 9], 12, 0x8b44f7af); /**//* 10 */
FF (c, d, a, b, x[10], 17, 0xffff5bb1); /**//* 11 */
FF (b, c, d, a, x[11], 22, 0x895cd7be); /**//* 12 */
FF (a, b, c, d, x[12], 7, 0x6b901122); /**//* 13 */
FF (d, a, b, c, x[13], 12, 0xfd987193); /**//* 14 */
FF (c, d, a, b, x[14], 17, 0xa679438e); /**//* 15 */
FF (b, c, d, a, x[15], 22, 0x49b40821); /**//* 16 */

/**//* Round 2 */
GG (a, b, c, d, x[ 1], 5, 0xf61e2562); /**//* 17 */
GG (d, a, b, c, x[ 6], 9, 0xc040b340); /**//* 18 */
GG (c, d, a, b, x[11], 14, 0x265e5a51); /**//* 19 */
GG (b, c, d, a, x[ 0], 20, 0xe9b6c7aa); /**//* 20 */
GG (a, b, c, d, x[ 5], 5, 0xd62f105d); /**//* 21 */
GG (d, a, b, c, x[10], 9, 0x02441453); /**//* 22 */
GG (c, d, a, b, x[15], 14, 0xd8a1e681); /**//* 23 */
GG (b, c, d, a, x[ 4], 20, 0xe7d3fbc8); /**//* 24 */
GG (a, b, c, d, x[ 9], 5, 0x21e1cde6); /**//* 25 */
GG (d, a, b, c, x[14], 9, 0xc33707d6); /**//* 26 */
GG (c, d, a, b, x[ 3], 14, 0xf4d50d87); /**//* 27 */
GG (b, c, d, a, x[ 8], 20, 0x455a14ed); /**//* 28 */
GG (a, b, c, d, x[13], 5, 0xa9e3e905); /**//* 29 */
GG (d, a, b, c, x[ 2], 9, 0xfcefa3f8); /**//* 30 */
GG (c, d, a, b, x[ 7], 14, 0x676f02d9); /**//* 31 */
GG (b, c, d, a, x[12], 20, 0x8d2a4c8a); /**//* 32 */

/**//* Round 3 */
HH (a, b, c, d, x[ 5], 4, 0xfffa3942); /**//* 33 */
HH (d, a, b, c, x[ 8], 11, 0x8771f681); /**//* 34 */
HH (c, d, a, b, x[11], 16, 0x6d9d6122); /**//* 35 */
HH (b, c, d, a, x[14], 23, 0xfde5380c); /**//* 36 */
HH (a, b, c, d, x[ 1], 4, 0xa4beea44); /**//* 37 */
HH (d, a, b, c, x[ 4], 11, 0x4bdecfa9); /**//* 38 */
HH (c, d, a, b, x[ 7], 16, 0xf6bb4b60); /**//* 39 */
HH (b, c, d, a, x[10], 23, 0xbebfbc70); /**//* 40 */
HH (a, b, c, d, x[13], 4, 0x289b7ec6); /**//* 41 */
HH (d, a, b, c, x[ 0], 11, 0xeaa127fa); /**//* 42 */
HH (c, d, a, b, x[ 3], 16, 0xd4ef3085); /**//* 43 */
HH (b, c, d, a, x[ 6], 23, 0x04881d05); /**//* 44 */
HH (a, b, c, d, x[ 9], 4, 0xd9d4d039); /**//* 45 */
HH (d, a, b, c, x[12], 11, 0xe6db99e5); /**//* 46 */
HH (c, d, a, b, x[15], 16, 0x1fa27cf8); /**//* 47 */
HH (b, c, d, a, x[ 2], 23, 0xc4ac5665); /**//* 48 */

/**//* Round 4 */
II (a, b, c, d, x[ 0], 6, 0xf4292244); /**//* 49 */
II (d, a, b, c, x[ 7], 10, 0x432aff97); /**//* 50 */
II (c, d, a, b, x[14], 15, 0xab9423a7); /**//* 51 */
II (b, c, d, a, x[ 5], 21, 0xfc93a039); /**//* 52 */
II (a, b, c, d, x[12], 6, 0x655b59c3); /**//* 53 */
II (d, a, b, c, x[ 3], 10, 0x8f0ccc92); /**//* 54 */
II (c, d, a, b, x[10], 15, 0xffeff47d); /**//* 55 */
II (b, c, d, a, x[ 1], 21, 0x85845dd1); /**//* 56 */
II (a, b, c, d, x[ 8], 6, 0x6fa87e4f); /**//* 57 */
II (d, a, b, c, x[15], 10, 0xfe2ce6e0); /**//* 58 */
II (c, d, a, b, x[ 6], 15, 0xa3014314); /**//* 59 */
II (b, c, d, a, x[13], 21, 0x4e0811a1); /**//* 60 */
II (a, b, c, d, x[ 4], 6, 0xf7537e82); /**//* 61 */
II (d, a, b, c, x[11], 10, 0xbd3af235); /**//* 62 */
II (c, d, a, b, x[ 2], 15, 0x2ad7d2bb); /**//* 63 */
II (b, c, d, a, x[ 9], 21, 0xeb86d391); /**//* 64 */

A += a;
B += b;
C += c;
D += d;

}

main(){
while(1){
printf("Input file:");
gets(filename); //用get函數,避免scanf以空格分割數據,
if (filename[0]==34) filename[strlen(filename)-1]=0,strcpy(filename,filename+1); //支持文件拖曳,但會多出雙引號,這里是處理多餘的雙引號
if (!strcmp(filename,"exit")) exit(0); //輸入exit退出
if (!(fp=fopen(filename,"rb"))) {printf("Can not open this file!\n");continue;} //以二進制打開文件
fseek(fp, 0, SEEK_END); //文件指針轉到文件末尾
if((len=ftell(fp))==-1) {printf("Sorry! Can not calculate files which larger than 2 GB!\n");fclose(fp);continue;} //ftell函數返回long,最大為2GB,超出返回-1
rewind(fp); //文件指針復位到文件頭
A=0x67452301,B=0xefcdab89,C=0x98badcfe,D=0x10325476; //初始化鏈接變數
flen[1]=len/0x20000000; //flen單位是bit
flen[0]=(len%0x20000000)*8;
memset(x,0,64); //初始化x數組為0
fread(&x,4,16,fp); //以4位元組為一組,讀取16組數據
for(i=0;i<len/64;i++){ //循環運算直至文件結束
md5();
memset(x,0,64);
fread(&x,4,16,fp);
}
((char*)x)[len%64]=128; //文件結束補1,補0操作,128二進制即10000000
if(len%64>55) md5(),memset(x,0,64);
memcpy(x+14,flen,8); //文件末尾加入原文件的bit長度
md5();
fclose(fp);
printf("MD5 Code:%08x%08x%08x%08x\n",PP(A),PP(B),PP(C),PP(D)); //高低位逆反輸出
}
}