1. sql 查找連續出現重復記錄。。。是連續的哦
給你說說思想已經很好了
還要人給你代碼。
sql:sleect 機台ID,物料ID,結論ID from table where 結論='不合格' group 機台ID,物料ID having
sum(結論)>=3
2. SQL語句如何選擇3條連續的記錄
如果ID值都是連續的話WHERE ID>=X AND ID<X+3
3. sqlserver中如何查詢出連續日期記錄的代碼
你這個需要藉助一個流水表，然後通過指定日期對流水表，進行數據疊加操作，
類似流水日期生成方法
---生成4月份所有的天數
selectdateadd(day,number,'2018-4-1')asdfrommaster..spt_values
wheretype='p'
andnumber>=0
anddateadd(day,number,'2018-4-1')between'2018-4-1'anddateadd(day,-1,'2018-5-1')
請試一試，如有疑問，及時溝通！
4. SQL篩選日期連續的記錄
select empid as 員工編號,workdate as 曠工日期一,dateadd(day,1,workdate) as 曠工日期二 from table t1
where
exists
(select * from table where empid=t1.empid and datediff(day,t1.workdate,workdate)=1)
and not exists
(select * from table where empid=t1.empid and datediff(day,t1.workdate,workdate)=2)
and not exists
(select * from table where empid=t1.empid and datediff(day,t1.workdate,workdate)=-1)
存在大一天的數，但不存在大兩天的數，也不存在小一天的數，就是正確結果了
5. sqlserver中如何查詢出連續日期記錄的代碼
你這個需要藉助一個流水表，然後通過指定日期對流水表，進行數據疊加操作，
類似流水日期生成方法
---生成4月份所有的天數
select dateadd(day,number,'2018-4-1') as d from master..spt_values
where type='p'
and number >=0
and dateadd(day,number,'2018-4-1') between '2018-4-1' and dateadd(day,-1,'2018-5-1')
請試一試，如有疑問，及時溝通！
6. SQL資料庫中查詢連續編號的的數據。
DECLARE@T1table(UserIDint,[name]nvarchar(50),numint);
insertinto@T1(UserID,[name],num)values(1001,'a',8)
insertinto@T1(UserID,[name],num)values(1002,'b',6)
insertinto@T1(UserID,[name],num)values(1003,'c',8)
insertinto@T1(UserID,[name],num)values(1004,'a',8)
insertinto@T1(UserID,[name],num)values(1005,'b',8)
select*from@t1
selecta.*from
(selectUserID,[name],[num]from@t1)ajoin
(selectUserID,[name],[num]from@t1)bona.UserID<b.UserIDanda.UserID+1=b.UserID
anda.num=b.num
groupbya.userid,a.[name],a.[num]
得到結果:1003c8
1004a8
7. sql server表中 怎麼查詢某些連續的記錄，比如：查詢第100到150行，表是無序排列的。
select top 150 * from 表的名字
except
select top 100 * from 表的名字
8. sql查詢連續出勤記錄
--用的好給加點分哦 特意幫你寫的 sql2000 通過
declare @tab table (dt datetime , ur varchar(12))
insert into @tab
select '2007-01-02','2014' union all
select '2007-01-04','2014' union all
select '2007-01-08','2014' union all
select '2007-01-09','2014' union all
select '2007-01-10','2014' union all
select '2007-01-11','2014' union all
select '2007-01-13','2014' union all
select '2007-01-14','2014' union all
select '2007-01-15','2014' union all
select '2007-01-17','2014' union all
select '2007-01-18','2014' union all
select '2007-01-20','2014' union all
select '2007-01-21','2014' union all
select '2007-01-22','2014' union all
select '2007-01-23','2014' union all
select '2007-01-25','2014' union all
select '2007-01-29','2014'
select * from @tab --顯示模擬數據
declare @tabOut table ([id] int,dtBegin datetime , dtEnd datetime)
declare @begin datetime,@end datetime,@n int
set @begin='1900-01-01'
set @n=0
declare my_cursor cursor for
select dt from @tab order by dt
Open my_cursor
Fetch Next From my_cursor into @end
while @@fetch_status=0
begin
if(datediff(day,@begin,@end)<>1)
begin
update @tabOut set dtEnd=@begin where [id]=@n
set @n=@n+1
insert into @tabOut([id],dtBegin)values(@n,@end)
end
set @begin=@end
Fetch Next From my_cursor into @end
end
update @tabOut set dtEnd=@begin where [id]=@n
close my_cursor
deallocate my_cursor
select * from @tabOut --結果
9. sql查詢連續出勤記錄
樓主的筆誤很多啊，看看是不是這個效果。
declare @tab table (dt datetime , ur varchar(12))
insert into @tab
select '2007-01-02','2014' union all
select '2007-01-04','2014' union all
select '2007-01-08','2014' union all
select '2007-01-09','2014' union all
select '2007-01-10','2014' union all
select '2007-01-11','2014' union all
select '2007-01-13','2014' union all
select '2007-01-14','2014' union all
select '2007-01-15','2014' union all
select '2007-01-17','2014' union all
select '2007-01-18','2014' union all
select '2007-01-20','2014' union all
select '2007-01-21','2014' union all
select '2007-01-22','2014' union all
select '2007-01-23','2014' union all
select '2007-01-25','2014' union all
select '2007-01-29','2014'
select *
from @tab a
where exists(select * from @tab where datediff(dd,dt,a.dt) in (1,-1))
order by 1
10. 如何寫連續三個月有記錄的sql
SQL> select org_id , person_id
2 from
3 (
4 select org_id , person_id ,
5 count(*) over ( partition by org_id , person_id order by month_num range 2 preceding ) ttt
6 from test)
7 /
select org_id , person_id
*
ERROR at line 1:
ORA-03113: end-of-file on communication channel