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用c語言編寫小紅花

發布時間: 2022-09-23 22:40:50

A. 用c語言編寫一個程序,輸出下列雪花圖案!

#include"stdio.h"
#defineROW14
#defineCOL12
intmain()
{
charch[ROW][COL]; //多定義一行一列,0行和0列不用
inti,j;
for(i=0;i<ROW;i++)
for(j=0;j<COL;j++)
ch[i][j]=''; //初始化為空格

ch[1][4]=ch[13][4]='*';

for(i=2;i<=8;i+=2)
{
ch[3][i]='*';
ch[11][i]='*';
}
for(i=3;i<=7;i+=2)
{
ch[5][i]='*';
ch[9][i]='*';
}
for(i=1;i<=11;i+=2)
{
ch[7][i]='*';
}

printf("");
for(i=1;i<COL;i++)
printf("%d",i);
printf(" ");
for(i=1;i<ROW;i++)
{
printf("%-2d",i);
for(j=1;j<COL;j++)
{
printf("%c",ch[i][j]);
}
printf(" ");
}
return0;
}

B. 用c語言編寫心形圖案

用C語言編寫心形的方法:

#include<stdio.h>
intn;
voiddraw(intn)
{
inti,j;
for(i=1-(n>>1);i<=n;i++)
if(i>=0)
{
for(j=0;j<i;j++)printf("");
for(j=1;j<=2*(n-i)+1;j++)printf("*");
printf(" ");
}
else
{
for(j=i;j<0;j++)printf("");
for(j=1;j<=n+2*i+1;j++)printf("*");
for(j=1;j<=-1-2*i;j++)printf("");
for(j=1;j<=n+2*i+1;j++)printf("*");
printf(" ");
}
}
intmain()
{
printf("Pleaseinputthesize(n>=4):");
scanf("%d",&n);
draw(n);
return0;
}

(2)用c語言編寫小紅花擴展閱讀

C程序是由一組變數或是函數的外部對象組成的。 函數是一個自我包含的完成一定相關功能的執行代碼段。我們可以把函數看成一個「黑盒子」,你只要將數據送進去就能得到結果,而函數內部究竟是如何工作的,外部程序是不知道的。

外部程序所知道的僅限於輸入給函數什麼以及函數輸出什麼。函數提供了編製程序的手段,使之容易讀、寫、理解、排除錯誤、修改和維護。

C. 用C++編玫瑰花

看了效果自己可以調節#include <stdio.h>
#include <dos.h>
#include <graphics.h>
#include <math.h>#define FNX(x) (int)(xo+(x)*1.0)
#define FNY(y) (int)(getmaxy()-(yo+(y)*1.0))
#define FNX2(phi) cos(phi)*ac-sin(phi)*bs
#define FNY2(phi) cos(phi)*as+sin(phi)*bc/*畫旋轉的橢圓*/
void elli(int xo,int yo,int a,int b,double theta)
{
int i;
double da,c,s,ac,as,bc,bs,xf,yf,phi,x,y;
theta=theta*0.01745;
da=3*0.1745;
c=cos(theta);s=sin(theta);
ac=a*c;as=a*s;bc=b*c;bs=b*s;
x=FNX2(0);y=FNY2(0);
moveto(FNX(x),FNY(y));
for(i=1;i<=360;i++)
{
phi=i*da;xf=x*cos(phi)*0.1;yf=b*sin(phi)*0.1;
x=FNX2(phi);y=FNY2(phi);
lineto(FNX(x),FNY(y));
}
}/*花*/
void hua(int x,int y)
{
register i;
/*畫粉紅色玫瑰*/
setcolor(12);
arc(x+65,y-60,150,350,8);
arc(x+66,y-54,300,470,8);
arc(x+65,y-56,30,230,10);
arc(x+64,y-57,300,490,17);
ellipse(x+73,y-30,250,450,27,40);
ellipse(x+59,y-30,100,290,27,40);
ellipse(x+65,y-40,140,270,20,30);
setfillstyle(SOLID_FILL,5);
floodfill(x+65,y-20,12);
/*畫紅色玫瑰*/
arc(x,y,150,350,12);
arc(x+1,y+8,280,470,12);
arc(x,y+2,30,230,16);
arc(x,y+3,80,240,28);
arc(x+2,y+8,180,330,22);
arc(x-2,y+2,310,460,25);
ellipse(x-12,y+30,120,300,30,40);
ellipse(x+10,y+28,250,423,30,42);
ellipse(x-4,y+10,290,393,30,40);
setfillstyle(SOLID_FILL,4);
floodfill(x+5,y+31,12);
/*畫紫色花骨朵*/
ellipse(x+120,y+5,0,360,15,25);
setfillstyle(SOLID_FILL,1);
floodfill(x+120,y,12);
/*畫黃色花骨朵*/
ellipse(x-70,y+10,0,360,14,20);
setfillstyle(SOLID_FILL,14);
floodfill(x-70,y+10,12);
setcolor(10);
/*畫紅花花萼*/
ellipse(x-15,y+32,190,310,30,35);
ellipse(x+16,y+32,235,355,26,35);
ellipse(x,y+35,190,350,43,50);
arc(x,y+82,190,350,6);
setfillstyle(SOLID_FILL,2);
floodfill(x,y+75,10);
/*畫粉花花萼*/
ellipse(x+50,y-48,190,320,22,50);
ellipse(x+80,y-48,220,350,22,50);
ellipse(x+65,y-28,180,360,36,50);
floodfill(x+65,y+18,10);
/*畫主枝*/
for(i=0;i<3;i++)
{
ellipse(x-98,y+100+i,255,371,100,80);
ellipse(x-20,y+30+i,260,358,140,140);
ellipse(x+224,y+20+i,180,218,160,140);
}
/*畫側枝*/
ellipse(x+70,y+34,180,233,140,140);
ellipse(x,y+40,205,255,100,120);
ellipse(x+135,y-30,209,249,72,120);
ellipse(x,y+20,263,301,100,120);
ellipse(x+85,y-10,278,305,100,120);
ellipse(x+100,y-62,282,308,90,120);
ellipse(x-50,y-10,277,314,30,120);
ellipse(x+70,y+80,222,266,52,120);
ellipse(x-60,y-45,229,266,52,120);
ellipse(x+79,y-45,229,266,52,120);
ellipse(x+84,y,224,273,52,120);
ellipse(x+110,y+40,240,282,100,120);
/*畫紫花骨朵花萼*/
ellipse(x+120,y-6,200,340,17,25);
ellipse(x+120,y+7,160,380,17,27);
floodfill(x+122,y+30,10);
/*畫黃花骨朵花萼*/
ellipse(x-70,y+15,140,390,17,20);
ellipse(x-75,y-10,205,340,10,30);
ellipse(x-60,y-10,195,340,5,30);
floodfill(x-70,y+32,10);
/*畫葉*/
/*畫右邊的葉子*/
elli(x+168,y+282,10,20,-40);
elli(x+160,y+252,8,16,260);
elli(x+145,y+270,8,16,-15);
elli(x+156,y+224,10,20,-45);
elli(x+150,y+200,8,16,270);
elli(x+135,y+220,8,16,-10);
elli(x+146,y+144,8,16,-80);
elli(x+130,y+130,6,12,235);
elli(x+125,y+154,7,14,-10);
elli(x+78,y+98,6,12,-90);
elli(x+60,y+90,5,10,180);
elli(x+70,y+109,5,10,-45);
/*畫左邊的葉子*/
elli(x-125,y+270,12,24,60);
elli(x-95,y+270,10,20,10);
elli(x-110,y+245,10,20,90);
elli(x-105,y+220,10,20,45);
elli(x-100,y+190,8,16,135);
elli(x-75,y+210,8,16,-45);
/*畫中間的葉子*/
elli(x+65,y+190,10,20,-45);
elli(x+40,y+185,8,16,0);
elli(x+55,y+165,8,16,90);
}/*主程序*/
main()
{
int driver=VGA,mode=VGAHI;
initgraph(&driver,&mode,"C:\TC");
cleardevice();
hua(450,90);
setcolor(10);
rectangle(0,0,639,479);
getch();
closegraph();
}

D. 水仙花數的c語言編程。

C語言具體實現水仙花過程如下:

一、問題描述:

輸出所有的「水仙花數」,所謂的「水仙花數」是指一個三位數其各位數字的立方和等於該數本身,例如153是「水仙花數」,因為:153 = 13 + 53 + 33。

二、問題分析:

根據「水仙花數」的定義,判斷一個數是否為「水仙花數」,最重要的是要把給出的三位數的個位、十位、百位分別拆分,並求其立方和(設為s),若s與給出的三位數相等, 三位數為「水仙花數」,反之,則不是。

三、演算法設計:

「水仙花數」是指滿足某一條件的三位數,根據這一信息可以確定整數的取值范圍是 100〜999。對應的循環條件如下:

for(n=10; n<1000; n++) { //...... }

四、完整的代碼:

E. 如何用C語言中的while語句編寫水仙花數程序

在DEV-C++通過檢測,有問題歡迎追問#include <math.h>
int main()
{
int i=100,a,b,c;
printf("3位數中的水仙花數為:");
while(i<999)
{
i++;
a=i/100;
b=(i/10)%10;
c=i%10;
if(pow(a,3)+pow(b,3)+pow(c,3)==i)
printf("%d\t",i);
} system("PAUSE");
return ;
}

F. 請問一下這道C語言編程題怎麼做

按照題目要求編寫的用凱撒密碼加密的C語言程序如下

#include<stdio.h>

int main(){

char s[80];

int offset,i;

fgets(s,80,stdin);

scanf("%d",&offset);

for(i=0;s[i]!='';i++){

if('A'<=s[i] && s[i]<='Z')

if(offset>=0)

s[i]='A'+(s[i]-'A'+offset)%26;

else

s[i]='A'+(s[i]-'A'+26+offset%26)%26;

else if('a'<=s[i] && s[i]<='z')

if(offset>=0)

s[i]='a'+(s[i]-'a'+offset)%26;

else

s[i]='a'+(s[i]-'a'+26+offset%26)%26;

}

printf("%s ", s);

return 0;

}

G. 怎樣用C語言編寫一個程序輸出一個紅色的旗子

#include<stdio.h>
#include<windows.h>
#defineN5//N>=2,旗子大小

voidprintFlag();
voidprintSpace(intn);
voidcolor(constunsignedshortcolor1);

intmain()
{
printFlag();//不清楚你的旗子形狀,僅供參考
return0;
}

voidprintFlag()
{
inti=0;

color(12);//字體變成紅色
for(i=0;i<N;++i)//旗幟
{
putchar('*');
printSpace(i);
putchar(' ');
}

for(i=0;i<(N/2)+2;++i)//旗幟底部
{
printf("*");
}

putchar(' ');
for(i=0;i<=N/4;++i)//旗桿
{
printf("* ");
}
color(7);//字體變成白色
}

voidprintSpace(intn)
{
if(n<=0)
return;

while(n--)
putchar('');
putchar('*');
}

voidcolor(constunsignedshortcolor1)
{
/*僅限改變0-15的顏色;如果在0-15那麼實現他的顏色因為如果超過15後面的改變的是文本背景色。*/
if(color1>=0&&color1<=15)
SetConsoleTextAttribute(GetStdHandle(STD_OUTPUT_HANDLE),color1);
/*如果不在0-15的范圍顏色,那麼改為默認的顏色白色;*/
else
SetConsoleTextAttribute(GetStdHandle(STD_OUTPUT_HANDLE),7);
}

H. 請問這道c語言編程題怎麼做

#include<stdio.h>

#defineN6

voidmain(){inta[N],i,k;

for(i=0;i<N;i++)scanf("%d",&a[i]);

k=0;for(i=1;i<N;i++)if(a[i]>a[k])k=i;

i=a[k];a[k]=a[N-1];a[N-1]=i;

for(i=0;i<N;i++)printf("%d ",a[i]);

}

I. 你是不是有999玫瑰C語言版源代碼能給我嗎

#include <dos.h>
#include <graphics.h>
#include <math.h>
/*玫瑰花*/
#define FNX(x) (int)(xo+(x)*1.0)
#define FNY(y) (int)(getmaxy()-(yo+(y)*1.0))
#define FNX2(phi) cos(phi)*ac-sin(phi)*bs
#define FNY2(phi) cos(phi)*as+sin(phi)*bc

/*畫旋轉的橢圓*/
void elli(int xo,int yo,int a,int b,double theta)
{
int i;
double da,c,s,ac,as,bc,bs,xf,yf,phi,x,y;
theta=theta*0.01745;
da=3*0.1745;
c=cos(theta);
s=sin(theta);
ac=a*c;as=a*s;
bc=b*c;bs=b*s;
x=FNX2(0);
y=FNY2(0);
moveto(FNX(x),FNY(y));
for(i=1;i<=360;i++)
{
phi=i*da;
xf=x*cos(phi)*0.1;
yf=b*sin(phi)*0.1;
x=FNX2(phi);
y=FNY2(phi);
lineto(FNX(x),FNY(y));
}
}

/*花*/
void hua(int x,int y)
{
register i;
/*畫粉紅色玫瑰*/
setcolor(12);
arc(x+65,y-60,150,350,8);
arc(x+66,y-54,300,470,8);
arc(x+65,y-56,30,230,10);
arc(x+64,y-57,300,490,17);
ellipse(x+73,y-30,250,450,27,40);
ellipse(x+59,y-30,100,290,27,40);
ellipse(x+65,y-40,140,270,20,30);
setfillstyle(SOLID_FILL,5);
floodfill(x+65,y-20,12);
/*畫紅色玫瑰*/
arc(x,y,150,350,12);
arc(x+1,y+8,280,470,12);
arc(x,y+2,30,230,16);
arc(x,y+3,80,240,28);
arc(x+2,y+8,180,330,22);
arc(x-2,y+2,310,460,25);
ellipse(x-12,y+30,120,300,30,40);
ellipse(x+10,y+28,250,423,30,42);
ellipse(x-4,y+10,290,393,30,40);
setfillstyle(SOLID_FILL,4);
floodfill(x+5,y+31,12);
/*畫紫色花骨朵*/
ellipse(x+120,y+5,0,360,15,25);
setfillstyle(SOLID_FILL,1);
floodfill(x+120,y,12);
/*畫黃色花骨朵*/
ellipse(x-70,y+10,0,360,14,20);
setfillstyle(SOLID_FILL,14);
floodfill(x-70,y+10,12);
setcolor(10);
/*畫紅花花萼*/
ellipse(x-15,y+32,190,310,30,35);
ellipse(x+16,y+32,235,355,26,35);
ellipse(x,y+35,190,350,43,50);
arc(x,y+82,190,350,6);
setfillstyle(SOLID_FILL,2);
floodfill(x,y+75,10);
/*畫粉花花萼*/
ellipse(x+50,y-48,190,320,22,50);
ellipse(x+80,y-48,220,350,22,50);
ellipse(x+65,y-28,180,360,36,50);
floodfill(x+65,y+18,10);
/*畫主枝*/
for(i=0;i<3;i++ )
{
ellipse(x-98,y+100+i,255,371,100,80);
ellipse(x-20,y+30+i,260,358,140,140);
ellipse(x+224,y+20+i,180,218,160,140);
}
/*畫側枝*/
ellipse(x+70,y+34,180,233,140,140);
ellipse(x,y+40,205,255,100,120);
ellipse(x+135,y-30,209,249,72,120);
ellipse(x,y+20,263,301,100,120);
ellipse(x+85,y-10,278,305,100,120);
ellipse(x+100,y-62,282,308,90,120);
ellipse(x-50,y-10,277,314,30,120);
ellipse(x+70,y+80,222,266,52,120);
ellipse(x-60,y-45,229,266,52,120);
ellipse(x+79,y-45,229,266,52,120);
ellipse(x+84,y,224,273,52,120);
ellipse(x+110,y+40,240,282,100,120);
/*畫紫花骨朵花萼*/
ellipse(x+120,y-6,200,340,17,25);
ellipse(x+120,y+7,160,380,17,27);
floodfill(x+122,y+30,10);
/*畫黃花骨朵花萼*/
ellipse(x-70,y+15,140,390,17,20);
ellipse(x-75,y-10,205,340,10,30);
ellipse(x-60,y-10,195,340,5,30);
floodfill(x-70,y+32,10);
/*畫葉*/
/*畫右邊的葉子*/
elli(x+168,y+282,10,20,-40);
elli(x+160,y+252,8,16,260);
elli(x+145,y+270,8,16,-15);
elli(x+156,y+224,10,20,-45);
elli(x+150,y+200,8,16,270);
elli(x+135,y+220,8,16,-10);
elli(x+146,y+144,8,16,-80);
elli(x+130,y+130,6,12,235);
elli(x+125,y+154,7,14,-10);
elli(x+78,y+98,6,12,-90);
elli(x+60,y+90,5,10,180);
elli(x+70,y+109,5,10,-45);
/*畫左邊的葉子*/
elli(x-125,y+270,12,24,60);
elli(x-95,y+270,10,20,10);
elli(x-110,y+245,10,20,90);
elli(x-105,y+220,10,20,45);
elli(x-100,y+190,8,16,135);
elli(x-75,y+210,8,16,-45);
/*畫中間的葉子*/
elli(x+65,y+190,10,20,-45);
elli(x+40,y+185,8,16,0);
elli(x+55,y+165,8,16,90);
}

/*主程序*/
main()
{
int driver=VGA,mode=VGAHI;
registerbgidriver(EGAVGA_driver);
initgraph(&driver,&mode,"C:\TC");
cleardevice();
hua(450,90);
setcolor(2);
rectangle(0,0,639,479);
getch();
closegraph();
}

J. c語言擊鼓傳花問題

#include<stdio.h>
#include<malloc.h>
#include<stdbool.h>//truefalse
#defineMAXN20

//以下代碼以循環雙鏈表編寫

typedefstructnode
{
intvalue;//存儲該節點的值
structnode*next;//該節點的後一個節點地址
structnode*prior;//該節點的前一個節點地址
}Neo;//把structnode{...}重命名為Neo

///在堆中分配內存
Neo*InitNewNode(void)
{
Neo*newnode=(Neo*)malloc(sizeof(Neo));
newnode->value=0;
newnode->next=newnode;
newnode->prior=newnode;//該節點存儲的前後節點默認為自己
returnnewnode;
}

///得到一個長度為count的Neo雙鏈表
voidInitNeoList(Neo*head,intcount)
{
Neo*p=head;//p初始化指向頭節點
inti;
for(i=0;i<count;++i)
{
Neo*node=InitNewNode();
node->value=i+2;
//把該節點添加到雙鏈表中
p->next=node;
node->prior=p;
node->next=head;
head->prior=node;
//p指向新添加的節點
p=node;
}
return;
}

voidOutput(Neo*head,inttimes)
{
Neo*p=head->next;
intcot=0;
intdel=0;
while(true)
{
cot++;
if(cot==times)
{
printf("%d ",p->value);//輸出該點的值
//把該點移除該雙鏈表
p->prior->next=p->next;
p->next->prior=p->prior;

Neo*q=p;//存儲要刪除的節點
free(p);//標記為可釋放
p=q->next;//把花給下一個人

cot=0;
del++;
}
p=p->next;
if(del==MAXN)break;
}
return;
}

intmain(intargc,charconst*argv[])
{
Neo*head=InitNewNode();
head->value=1;//頭節點存儲第一個同學的編號
InitNeoList(head,MAXN-1);//再添加19個節點
inttimes;
scanf("%d",&times);
Output(head,times);
return0;
}