資料庫常用sql語句
Student(S#,Sname,Sage,Ssex) 學生表
Course(C#,Cname,T#) 課程表
SC(S#,C#,score) 成績表
Teacher(T#,Tname) 教師表
問題:
1、查詢「001」課程比「002」課程成績高的所有學生的學號;
select a.S# from (select s#,score from SC where C#='001') a,(select s#,score
from SC where C#='002') b
where a.score>b.score and a.s#=b.s#;
2、查詢平均成績大於60分的同學的學號和平均成績;
select S#,avg(score)
from sc
group by S# having avg(score) >60;
3、查詢所有同學的學號、姓名、選課數、總成績;
select Student.S#,Student.Sname,count(SC.C#),sum(score)
from Student left Outer join SC on Student.S#=SC.S#
group by Student.S#,Sname
4、查詢姓「李」的老師的個數;
select count(distinct(Tname))
from Teacher
where Tname like '李%';
5、查詢沒學過「葉平」老師課的同學的學號、姓名;
select Student.S#,Student.Sname
from Student
where S# not in (select distinct( SC.S#) from SC,Course,Teacher where SC.C#=Course.C# and Teacher.T#=Course.T# and Teacher.Tname='葉平');
6、查詢學過「001」並且也學過編號「002」課程的同學的學號、姓名;
select Student.S#,Student.Sname from Student,SC where Student.S#=SC.S# and SC.C#='001'and exists( Select * from SC as SC_2 where SC_2.S#=SC.S# and SC_2.C#='002');
7、查詢學過「葉平」老師所教的所有課的同學的學號、姓名;
select S#,Sname
from Student
where S# in (select S# from SC ,Course ,Teacher where SC.C#=Course.C# and Teacher.T#=Course.T# and Teacher.Tname='葉平' group by S# having count(SC.C#)=(select count(C#) from Course,Teacher where Teacher.T#=Course.T# and Tname='葉平'));
8、查詢課程編號「002」的成績比課程編號「001」課程低的所有同學的學號、姓名;
Select S#,Sname from (select Student.S#,Student.Sname,score ,(select score from SC SC_2 where SC_2.S#=Student.S# and SC_2.C#='002') score2
from Student,SC where Student.S#=SC.S# and C#='001') S_2 where score2<score;
9、查詢所有課程成績小於60分的同學的學號、姓名;
select S#,Sname
from Student
where S# not in (select Student.S# from Student,SC where S.S#=SC.S# and score>60);
10、查詢沒有學全所有課的同學的學號、姓名;
select Student.S#,Student.Sname
from Student,SC
where Student.S#=SC.S# group by Student.S#,Student.Sname having count(C#) <(select count(C#) from Course);
11、查詢至少有一門課與學號為「1001」的同學所學相同的同學的學號和姓名;
select S#,Sname from Student,SC where Student.S#=SC.S# and C# in select C# from SC where S#='1001';
12、查詢至少學過學號為「001」同學所有一門課的其他同學學號和姓名;
select distinct SC.S#,Sname
from Student,SC
where Student.S#=SC.S# and C# in (select C# from SC where S#='001');
13、把「SC」表中「葉平」老師教的課的成績都更改為此課程的平均成績;
SC set score=(select avg(SC_2.score)
from SC SC_2
where SC_2.C#=SC.C# ) from Course,Teacher where Course.C#=SC.C# and Course.T#=Teacher.T# and Teacher.Tname='葉平');
14、查詢和「1002」號的同學學習的課程完全相同的其他同學學號和姓名;
select S# from SC where C# in (select C# from SC where S#='1002')
group by S# having count(*)=(select count(*) from SC where S#='1002');
15、刪除學習「葉平」老師課的SC表記錄;
Delect SC
from course ,Teacher
where Course.C#=SC.C# and Course.T#= Teacher.T# and Tname='葉平';
16、向SC表中插入一些記錄,這些記錄要求符合以下條件:沒有上過編號「003」課程的同學學號、2、
號課的平均成績;
Insert SC select S#,'002',(Select avg(score)
from SC where C#='002') from Student where S# not in (Select S# from SC where C#='002');
17、按平均成績從高到低顯示所有學生的「資料庫」、「企業管理」、「英語」三門的課程成績,按如下形式顯示: 學生ID,,資料庫,企業管理,英語,有效課程數,有效平均分
SELECT S# as 學生ID
,(SELECT score FROM SC WHERE SC.S#=t.S# AND C#='004') AS 資料庫
,(SELECT score FROM SC WHERE SC.S#=t.S# AND C#='001') AS 企業管理
,(SELECT score FROM SC WHERE SC.S#=t.S# AND C#='006') AS 英語
,COUNT(*) AS 有效課程數, AVG(t.score) AS 平均成績
FROM SC AS t
GROUP BY S#
ORDER BY avg(t.score)
18、查詢各科成績最高和最低的分:以如下形式顯示:課程ID,最高分,最低分
SELECT L.C# As 課程ID,L.score AS 最高分,R.score AS 最低分
FROM SC L ,SC AS R
WHERE L.C# = R.C# and
L.score = (SELECT MAX(IL.score)
FROM SC AS IL,Student AS IM
WHERE L.C# = IL.C# and IM.S#=IL.S#
GROUP BY IL.C#)
AND
R.Score = (SELECT MIN(IR.score)
FROM SC AS IR
WHERE R.C# = IR.C#
GROUP BY IR.C#
);
19、按各科平均成績從低到高和及格率的百分數從高到低順序
SELECT t.C# AS 課程號,max(course.Cname)AS 課程名,isnull(AVG(score),0) AS 平均成績
,100 * SUM(CASE WHEN isnull(score,0)>=60 THEN 1 ELSE 0 END)/COUNT(*) AS 及格百分數
FROM SC T,Course
where t.C#=course.C#
GROUP BY t.C#
ORDER BY 100 * SUM(CASE WHEN isnull(score,0)>=60 THEN 1 ELSE 0 END)/COUNT(*) DESC
20、查詢如下課程平均成績和及格率的百分數(用"1行"顯示): 企業管理(001),馬克思(002),OO&UML (003),資料庫(004)
SELECT SUM(CASE WHEN C# ='001' THEN score ELSE 0 END)/SUM(CASE C# WHEN '001' THEN 1 ELSE 0 END) AS 企業管理平均分
,100 * SUM(CASE WHEN C# = '001' AND score >= 60 THEN 1 ELSE 0 END)/SUM(CASE WHEN C# = '001' THEN 1 ELSE 0 END) AS 企業管理及格百分數
,SUM(CASE WHEN C# = '002' THEN score ELSE 0 END)/SUM(CASE C# WHEN '002' THEN 1 ELSE 0 END) AS 馬克思平均分
,100 * SUM(CASE WHEN C# = '002' AND score >= 60 THEN 1 ELSE 0 END)/SUM(CASE WHEN C# = '002' THEN 1 ELSE 0 END) AS 馬克思及格百分數
,SUM(CASE WHEN C# = '003' THEN score ELSE 0 END)/SUM(CASE C# WHEN '003' THEN 1 ELSE 0 END) AS UML平均分
,100 * SUM(CASE WHEN C# = '003' AND score >= 60 THEN 1 ELSE 0 END)/SUM(CASE WHEN C# = '003' THEN 1 ELSE 0 END) AS UML及格百分數
,SUM(CASE WHEN C# = '004' THEN score ELSE 0 END)/SUM(CASE C# WHEN '004' THEN 1 ELSE 0 END) AS 資料庫平均分
,100 * SUM(CASE WHEN C# = '004' AND score >= 60 THEN 1 ELSE 0 END)/SUM(CASE WHEN C# = '004' THEN 1 ELSE 0 END) AS 資料庫及格百分數
FROM SC
21、查詢不同老師所教不同課程平均分從高到低顯示
SELECT max(Z.T#) AS 教師ID,MAX(Z.Tname) AS 教師姓名,C.C# AS 課程ID,MAX(C.Cname) AS 課程名稱,AVG(Score) AS 平均成績
FROM SC AS T,Course AS C ,Teacher AS Z
where T.C#=C.C# and C.T#=Z.T#
GROUP BY C.C#
ORDER BY AVG(Score) DESC
22、查詢如下課程成績第 3 名到第 6 名的學生成績單:企業管理(001),馬克思(002),UML (003),資料庫(004)
[學生ID],[學生姓名],企業管理,馬克思,UML,資料庫,平均成績
SELECT DISTINCT top 3
SC.S# As 學生學號,
Student.Sname AS 學生姓名 ,
T1.score AS 企業管理,
T2.score AS 馬克思,
T3.score AS UML,
T4.score AS 資料庫,
ISNULL(T1.score,0) + ISNULL(T2.score,0) + ISNULL(T3.score,0) + ISNULL(T4.score,0) as 總分
FROM Student,SC LEFT JOIN SC AS T1
ON SC.S# = T1.S# AND T1.C# = '001'
LEFT JOIN SC AS T2
ON SC.S# = T2.S# AND T2.C# = '002'
LEFT JOIN SC AS T3
ON SC.S# = T3.S# AND T3.C# = '003'
LEFT JOIN SC AS T4
ON SC.S# = T4.S# AND T4.C# = '004'
WHERE student.S#=SC.S# and
ISNULL(T1.score,0) + ISNULL(T2.score,0) + ISNULL(T3.score,0) + ISNULL(T4.score,0)
NOT IN
(SELECT
DISTINCT
TOP 15 WITH TIES
ISNULL(T1.score,0) + ISNULL(T2.score,0) + ISNULL(T3.score,0) + ISNULL(T4.score,0)
FROM sc
LEFT JOIN sc AS T1
ON sc.S# = T1.S# AND T1.C# = 'k1'
LEFT JOIN sc AS T2
ON sc.S# = T2.S# AND T2.C# = 'k2'
LEFT JOIN sc AS T3
ON sc.S# = T3.S# AND T3.C# = 'k3'
LEFT JOIN sc AS T4
ON sc.S# = T4.S# AND T4.C# = 'k4'
ORDER BY ISNULL(T1.score,0) + ISNULL(T2.score,0) + ISNULL(T3.score,0) + ISNULL(T4.score,0) DESC);
23、統計列印各科成績,各分數段人數:課程ID,課程名稱,[100-85],[85-70],[70-60],[<60]
SELECT SC.C# as 課程ID, Cname as 課程名稱
,SUM(CASE WHEN score BETWEEN 85 AND 100 THEN 1 ELSE 0 END) AS [100 - 85]
,SUM(CASE WHEN score BETWEEN 70 AND 85 THEN 1 ELSE 0 END) AS [85 - 70]
,SUM(CASE WHEN score BETWEEN 60 AND 70 THEN 1 ELSE 0 END) AS [70 - 60]
,SUM(CASE WHEN score < 60 THEN 1 ELSE 0 END) AS [60 -]
FROM SC,Course
where SC.C#=Course.C#
GROUP BY SC.C#,Cname;
24、查詢學生平均成績及其名次
SELECT 1+(SELECT COUNT( distinct 平均成績)
FROM (SELECT S#,AVG(score) AS 平均成績
FROM SC
GROUP BY S#
) AS T1
WHERE 平均成績 > T2.平均成績) as 名次,
S# as 學生學號,平均成績
FROM (SELECT S#,AVG(score) 平均成績
FROM SC
GROUP BY S#
) AS T2
ORDER BY 平均成績 desc;
25、查詢各科成績前三名的記錄:(不考慮成績並列情況)
SELECT t1.S# as 學生ID,t1.C# as 課程ID,Score as 分數
FROM SC t1
WHERE score IN (SELECT TOP 3 score
FROM SC
WHERE t1.C#= C#
ORDER BY score DESC
)
ORDER BY t1.C#;
26、查詢每門課程被選修的學生數
select c#,count(S#) from sc group by C#;
27、查詢出只選修了一門課程的全部學生的學號和姓名
select SC.S#,Student.Sname,count(C#) AS 選課數
from SC ,Student
where SC.S#=Student.S# group by SC.S# ,Student.Sname having count(C#)=1;
28、查詢男生、女生人數
Select count(Ssex) as 男生人數 from Student group by Ssex having Ssex='男';
Select count(Ssex) as 女生人數 from Student group by Ssex having Ssex='女';
29、查詢姓「張」的學生名單
SELECT Sname FROM Student WHERE Sname like '張%';
30、查詢同名同性學生名單,並統計同名人數
select Sname,count(*) from Student group by Sname having count(*)>1;;
31、1981年出生的學生名單(註:Student表中Sage列的類型是datetime)
select Sname, CONVERT(char (11),DATEPART(year,Sage)) as age
from student
where CONVERT(11),DATEPART(year,Sage))='1981';
32、查詢每門課程的平均成績,結果按平均成績升序排列,平均成績相同時,按課程號降序排列
Select C#,Avg(score) from SC group by C# order by Avg(score),C# DESC ;
33、查詢平均成績大於85的所有學生的學號、姓名和平均成績
select Sname,SC.S# ,avg(score)
from Student,SC
where Student.S#=SC.S# group by SC.S#,Sname having avg(score)>85;
34、查詢課程名稱為「資料庫」,且分數低於60的學生姓名和分數
Select Sname,isnull(score,0)
from Student,SC,Course
where SC.S#=Student.S# and SC.C#=Course.C# and Course.Cname='資料庫'and score<60;
35、查詢所有學生的選課情況;
SELECT SC.S#,SC.C#,Sname,Cname
FROM SC,Student,Course
where SC.S#=Student.S# and SC.C#=Course.C# ;
36、查詢任何一門課程成績在70分以上的姓名、課程名稱和分數;
SELECT distinct student.S#,student.Sname,SC.C#,SC.score
FROM student,Sc
WHERE SC.score>=70 AND SC.S#=student.S#;
37、查詢不及格的課程,並按課程號從大到小排列
select c# from sc where scor e<60 order by C# ;
38、查詢課程編號為003且課程成績在80分以上的學生的學號和姓名;
select SC.S#,Student.Sname from SC,Student where SC.S#=Student.S# and Score>80 and C#='003';
39、求選了課程的學生人數
select count(*) from sc;
40、查詢選修「葉平」老師所授課程的學生中,成績最高的學生姓名及其成績
select Student.Sname,score
from Student,SC,Course C,Teacher
where Student.S#=SC.S# and SC.C#=C.C# and C.T#=Teacher.T# and Teacher.Tname='葉平' and SC.score=(select max(score)from SC where C#=C.C# );
41、查詢各個課程及相應的選修人數
select count(*) from sc group by C#;
42、查詢不同課程成績相同的學生的學號、課程號、學生成績
select distinct A.S#,B.score from SC A ,SC B where A.Score=B.Score and A.C# <>B.C# ;
43、查詢每門功成績最好的前兩名
SELECT t1.S# as 學生ID,t1.C# as 課程ID,Score as 分數
FROM SC t1
WHERE score IN (SELECT TOP 2 score
FROM SC
WHERE t1.C#= C#
ORDER BY score DESC
)
ORDER BY t1.C#;
44、統計每門課程的學生選修人數(超過10人的課程才統計)。要求輸出課程號和選修人數,查詢結果按人數降序排列,查詢結果按人數降序排列,若人數相同,按課程號升序排列
select C# as 課程號,count(*) as 人數
from sc
group by C#
order by count(*) desc,c#
45、檢索至少選修兩門課程的學生學號
select S#
from sc
group by s#
having count(*) > = 2
46、查詢全部學生都選修的課程的'課程號和課程名
select C#,Cname
from Course
where C# in (select c# from sc group by c#)
47、查詢沒學過「葉平」老師講授的任一門課程的學生姓名
select Sname from Student where S# not in (select S# from Course,Teacher,SC where Course.T#=Teacher.T# and SC.C#=course.C# and Tname='葉平');
48、查詢兩門以上不及格課程的同學的學號及其平均成績
select S#,avg(isnull(score,0)) from SC where S# in (select S# from SC where score<60 group="" by="" having="">2)group by S#;
49、檢索「004」課程分數小於60,按分數降序排列的同學學號
select S# from SC where C#='004'and score<60 order by score desc;
50、刪除「002」同學的「001」課程的成績
from Sc where S#='001'and C#='001';
一、SQL語言簡介
1、SQL語言簡介
SQL是結構化查詢語言(Structured Query Language),是用於訪問和處理資料庫的標準的計算機語言。
SQL語言的功能如下:
A、SQL面向資料庫執行查詢
B、SQL可從資料庫取回數據
C、SQL可在資料庫中插入新的記錄
D、SQL可更新資料庫中的數據
E、SQL可從資料庫刪除記錄
F、SQL可創建新資料庫
G、SQL可在資料庫中創建新表
H、SQL可在資料庫中創建存儲過程
I、SQL可在資料庫中創建視圖
J、SQL可以設置表、存儲過程和視圖的許可權
SQL是一門ANSI的標准計算機語言,用來訪問和操作資料庫系統。SQL語句用於取回和更新資料庫中的數據。SQL可與資料庫程序協同工作,比如MS Access、DB2、Informix、MS SQL Server、Oracle、MySQL、Sybase以及其他資料庫系統。
每一種資料庫有自己版本的SQL語言,但是為了與ANSI標准相兼容,SQL必須以相似的方式共同地來支持一些主要的關鍵詞(比如 SELECT、UPDATE、DELETE、INSERT、WHERE等等)。
除了SQL標准之外,大部分SQL資料庫程序都擁有自己的私有擴展。
2、SQL語言分類
SQL語言分為數據定義語言、數據控制語言、數據操作語言、數據查詢語言,分別實現對資料庫數據操作。
二、SQL語言基礎
1、數據定義語言(DDL)
DDL:Data Definition Language
用於定義和管理數據對象,包括資料庫、數據表、函數、視圖、索引、觸發器等。例如:CREATE、DROP、ALTER等語句。
create table student
(
sid INT,
sname var20)
);
alter table student add age int default 20;
student;
drop database student;
2、數據控制語言(DCL)
DCL:Data Control Language
用來管理資料庫的語言,包含授權用戶訪問、拒絕用戶訪問、撤銷授予的許可權。例如:GRANT、DENY、REVOKE、COMMIT、ROLLBACK等語句。
創建用戶
create user 『wang』@『localhost』 identified by 『a1!』;
許可權設置
grant select on db.student to 『wang』@『localhost』;
撤銷許可權
revoke select on db.student from 『wang』@『localhost』;
3、數據操作語言(DML)
DML:Data Manipulation Language
用於操作資料庫對象中所包含的數據,增、刪、改。例如:INSERT、DELETE、UPDATE語句。
4、數據查詢語言(DQL)
DQL:Data Query Language
用於查詢資料庫對象中所包含的數據,能夠進行單表查詢、連接查詢、嵌套查詢,以及集合查詢等各種復雜程度不同的資料庫查詢,並將數據返回到客戶機中顯示。例如:SELECT語句。
三、常量和變數
1、常量
A、字元常量
字元串常量使用單引號或雙引號,數值常量不用加引號。
如果字元串常量中需要換行、有單引號、雙引號 % _
前面需要加轉義字元
換行
』 一個單引號
」 一個雙引號
一個 如果沒有轉義字元 就認為是一個轉義字元
% 一個% 如果沒有轉義字元就認為這是一個通配符
_ 一個_ 如果沒有轉移字元 就認為是一個通配符
select 『hanli』gang001』
select 『han ligang001』
select 『han ligang001』
select 「han"ligang001」
select 「韓立剛001」
B、數值常量
數值常量不用添加引號,
select 100+100+200
C、布爾常量
布爾型常量取值 true 和 false
在SQL中使用1和0表示
select true,false
在表達式中
select 100>200
select 100<200
2、變數
用戶自定義變數使用@開始,使用set給變數賦值。
set @name=『孫悟空』;
select @name;
select * from student;
into student values (6,『孫悟空』,20);
into student values (8,@name,20);
set @sid=9,@nid=10
into student values (@sid,@name,20);
select @sid+@nid;
set @sid=@sid+1;
select @sid;
set @sname3=(select sname from student where sid=9);
select @sname3;
3、系統變數
系統變數分為全局系統變數和會話系統變數。
全局系統變數:針對所有默認設置
會話系統變數:針對當前用戶生效,用戶登錄MySQL會使用全局系統變數,如果會話中更改了變數值,使用更改後的值,不過只針對當前用戶生效。
show variables 顯示會話系統變數
show global variables 顯示全局系統變數
show session variables 顯示會話系統變數
show global variables like 『sql_select_limit』;使用通配符顯示匹配的變數設置
show session variables like 『sql_select_limit』;系統變數使用@@標識
select @@global.sql_select_limit 查看某個全局系統變數設置
select @@session.sql_select_limit 查看某個會話系統變數設置
set @@session.sql_select_limit=2 設置會話系統變數
全局系統變數需要在/etc/my.cnf配置文件中修改。
❷ 用SQL查詢平均成績高於90分的同學的學號、姓名及其平均成績,並按成績由高到低排序
select 學號,姓名,avg(成績) as '平均成績' from 學生成績表 HAVING avg(成績) > 90 order by avg(成績) desc
❸ sql語句 把成績低於總平均成績的女同學的成績提高5%。
把成績低於總平均成績的女同學的成績提高5%的語句如下:
sql語言的特點:
1、SQL風格統一
SQL可以獨立完成資料庫生命周期中的全部活動,包括定義關系模式、錄入數據、建立資料庫、査詢、更新、維護、資料庫重構、資料庫安全性控制等一系列操作,這就為資料庫應用系統開發提供了良好的環境。
在資料庫投入運行後,還可根據需要隨時逐步修改模式,且不影響資料庫的運行,從而使系統具有良好的可擴充性。
2、高度非過程化
非關系數據模型的數據操縱語言是面向過程的語言,用其完成用戶請求時,必須指定存取路徑。而用SQL進行數據操作,用戶只需提出「做什麼」,而不必指明「怎麼做」。
因此用戶無須了解存取路徑,存取路徑的選擇以及SQL語句的操作過程由系統自動完成。這不但大大減輕了用戶負擔,而且有利於提高數據獨立性。
❹ 資料庫常用sql語句有哪些
資料庫常用sql語句有哪些
SQL語句有哪些?SQL語句無論是種類還是數量都是繁多的,很多語句也是經常要用到的,下文我為大家分享的就是SQL的常用語句,僅供參考!
50個常用的sql語句
Student(S#,Sname,Sage,Ssex) 學生表
Course(C#,Cname,T#) 課程表
SC(S#,C#,score) 成績表
Teacher(T#,Tname) 教師表
問題:
1、查詢“001”課程比“002”課程成績高的所有學生的學號;
select a.S# from (select s#,score from SC where C#='001') a,(select s#,score
from SC where C#='002') b
where a.score>b.score and a.s#=b.s#;
2、查詢平均成績大於60分的同學的學號和平均成績;
select S#,avg(score)
from sc
group by S# having avg(score) >60;
3、查詢所有同學的學號、姓名、選課數、總成績;
select Student.S#,Student.Sname,count(SC.C#),sum(score)
from Student left Outer join SC on Student.S#=SC.S#
group by Student.S#,Sname
4、查詢姓“李”的老師的個數;
select count(distinct(Tname))
from Teacher
where Tname like '李%';
5、查詢沒學過“葉平”老師課的同學的學號、姓名;
select Student.S#,Student.Sname
from Student
where S# not in (select distinct( SC.S#) from SC,Course,Teacher where SC.C#=Course.C# and Teacher.T#=Course.T# and Teacher.Tname='葉平');
6、查詢學過“001”並且也學過編號“002”課程的同學的學號、姓名;
select Student.S#,Student.Sname from Student,SC where Student.S#=SC.S# and SC.C#='001'and exists( Select * from SC as SC_2 where SC_2.S#=SC.S# and SC_2.C#='002');
7、查詢學過“葉平”老師所教的所有課的同學的學號、姓名;
select S#,Sname
from Student
where S# in (select S# from SC ,Course ,Teacher where SC.C#=Course.C# and Teacher.T#=Course.T# and Teacher.Tname='葉平' group by S# having count(SC.C#)=(select count(C#) from Course,Teacher where Teacher.T#=Course.T# and Tname='葉平'));
8、查詢課程編號“002”的成績比課程編號“001”課程低的所有同學的學號、姓名;
Select S#,Sname from (select Student.S#,Student.Sname,score ,(select score from SC SC_2 where SC_2.S#=Student.S# and SC_2.C#='002') score2
from Student,SC where Student.S#=SC.S# and C#='001') S_2 where score2 <score;
9、查詢所有課程成績小於60分的同學的學號、姓名;
select S#,Sname
from Student
where S# not in (select Student.S# from Student,SC where S.S#=SC.S# and score>60);
10、查詢沒有學全所有課的同學的學號、姓名;
select Student.S#,Student.Sname
from Student,SC
where Student.S#=SC.S# group by Student.S#,Student.Sname having count(C#) <(select count(C#) from Course);
11、查詢至少有一門課與學號為“1001”的同學所學相同的同學的學號和姓名;
select S#,Sname from Student,SC where Student.S#=SC.S# and C# in select C# from SC where S#='1001';
12、查詢至少學過學號為“001”同學所有一門課的其他同學學號和姓名;
select distinct SC.S#,Sname
from Student,SC
where Student.S#=SC.S# and C# in (select C# from SC where S#='001');
13、把“SC”表中“葉平”老師教的課的成績都更改為此課程的平均成績;
update SC set score=(select avg(SC_2.score)
from SC SC_2
where SC_2.C#=SC.C# ) from Course,Teacher where Course.C#=SC.C# and Course.T#=Teacher.T# and Teacher.Tname='葉平');
14、查詢和“1002”號的同學學習的課程完全相同的其他同學學號和姓名;
select S# from SC where C# in (select C# from SC where S#='1002')
group by S# having count(*)=(select count(*) from SC where S#='1002');
15、刪除學習“葉平”老師課的SC表記錄;
Delect SC
from course ,Teacher
where Course.C#=SC.C# and Course.T#= Teacher.T# and Tname='葉平';
16、向SC表中插入一些記錄,這些記錄要求符合以下條件:沒有上過編號“003”課程的同學學號、2、
號課的平均成績;
Insert SC select S#,'002',(Select avg(score)
from SC where C#='002') from Student where S# not in (Select S# from SC where C#='002');
17、按平均成績從高到低顯示所有學生的“資料庫”、“企業管理”、“英語”三門的課程成績,按如下形式顯示: 學生ID,,資料庫,企業管理,英語,有效課程數,有效平均分
SELECT S# as 學生ID
,(SELECT score FROM SC WHERE SC.S#=t.S# AND C#='004') AS 資料庫
,(SELECT score FROM SC WHERE SC.S#=t.S# AND C#='001') AS 企業管理
,(SELECT score FROM SC WHERE SC.S#=t.S# AND C#='006') AS 英語
,COUNT(*) AS 有效課程數, AVG(t.score) AS 平均成績
FROM SC AS t
GROUP BY S#
ORDER BY avg(t.score)
18、查詢各科成績最高和最低的分:以如下形式顯示:課程ID,最高分,最低分
SELECT L.C# As 課程ID,L.score AS 最高分,R.score AS 最低分
FROM SC L ,SC AS R
WHERE L.C# = R.C# and
L.score = (SELECT MAX(IL.score)
FROM SC AS IL,Student AS IM
WHERE L.C# = IL.C# and IM.S#=IL.S#
GROUP BY IL.C#)
AND
R.Score = (SELECT MIN(IR.score)
FROM SC AS IR
WHERE R.C# = IR.C#
GROUP BY IR.C#
);
19、按各科平均成績從低到高和及格率的百分數從高到低順序
SELECT t.C# AS 課程號,max(course.Cname)AS 課程名,isnull(AVG(score),0) AS 平均成績
,100 * SUM(CASE WHEN isnull(score,0)>=60 THEN 1 ELSE 0 END)/COUNT(*) AS 及格百分數
FROM SC T,Course
where t.C#=course.C#
GROUP BY t.C#
ORDER BY 100 * SUM(CASE WHEN isnull(score,0)>=60 THEN 1 ELSE 0 END)/COUNT(*) DESC
20、查詢如下課程平均成績和及格率的百分數(用"1行"顯示): 企業管理(001),馬克思(002),OO&UML (003),資料庫(004)
SELECT SUM(CASE WHEN C# ='001' THEN score ELSE 0 END)/SUM(CASE C# WHEN '001' THEN 1 ELSE 0 END) AS 企業管理平均分
,100 * SUM(CASE WHEN C# = '001' AND score >= 60 THEN 1 ELSE 0 END)/SUM(CASE WHEN C# = '001' THEN 1 ELSE 0 END) AS 企業管理及格百分數
,SUM(CASE WHEN C# = '002' THEN score ELSE 0 END)/SUM(CASE C# WHEN '002' THEN 1 ELSE 0 END) AS 馬克思平均分
,100 * SUM(CASE WHEN C# = '002' AND score >= 60 THEN 1 ELSE 0 END)/SUM(CASE WHEN C# = '002' THEN 1 ELSE 0 END) AS 馬克思及格百分數
,SUM(CASE WHEN C# = '003' THEN score ELSE 0 END)/SUM(CASE C# WHEN '003' THEN 1 ELSE 0 END) AS UML平均分
,100 * SUM(CASE WHEN C# = '003' AND score >= 60 THEN 1 ELSE 0 END)/SUM(CASE WHEN C# = '003' THEN 1 ELSE 0 END) AS UML及格百分數
,SUM(CASE WHEN C# = '004' THEN score ELSE 0 END)/SUM(CASE C# WHEN '004' THEN 1 ELSE 0 END) AS 資料庫平均分
,100 * SUM(CASE WHEN C# = '004' AND score >= 60 THEN 1 ELSE 0 END)/SUM(CASE WHEN C# = '004' THEN 1 ELSE 0 END) AS 資料庫及格百分數
FROM SC
21、查詢不同老師所教不同課程平均分從高到低顯示
SELECT max(Z.T#) AS 教師ID,MAX(Z.Tname) AS 教師姓名,C.C# AS 課程ID,MAX(C.Cname) AS 課程名稱,AVG(Score) AS 平均成績
FROM SC AS T,Course AS C ,Teacher AS Z
where T.C#=C.C# and C.T#=Z.T#
GROUP BY C.C#
ORDER BY AVG(Score) DESC
22、查詢如下課程成績第 3 名到第 6 名的學生成績單:企業管理(001),馬克思(002),UML (003),資料庫(004)
[學生ID],[學生姓名],企業管理,馬克思,UML,資料庫,平均成績
SELECT DISTINCT top 3
SC.S# As 學生學號,
Student.Sname AS 學生姓名 ,
T1.score AS 企業管理,
T2.score AS 馬克思,
T3.score AS UML,
T4.score AS 資料庫,
ISNULL(T1.score,0) + ISNULL(T2.score,0) + ISNULL(T3.score,0) + ISNULL(T4.score,0) as 總分
FROM Student,SC LEFT JOIN SC AS T1
ON SC.S# = T1.S# AND T1.C# = '001'
LEFT JOIN SC AS T2
ON SC.S# = T2.S# AND T2.C# = '002'
LEFT JOIN SC AS T3
ON SC.S# = T3.S# AND T3.C# = '003'
LEFT JOIN SC AS T4
ON SC.S# = T4.S# AND T4.C# = '004'
WHERE student.S#=SC.S# and
ISNULL(T1.score,0) + ISNULL(T2.score,0) + ISNULL(T3.score,0) + ISNULL(T4.score,0)
NOT IN
(SELECT
DISTINCT
TOP 15 WITH TIES
ISNULL(T1.score,0) + ISNULL(T2.score,0) + ISNULL(T3.score,0) + ISNULL(T4.score,0)
FROM sc
LEFT JOIN sc AS T1
ON sc.S# = T1.S# AND T1.C# = 'k1'
LEFT JOIN sc AS T2
ON sc.S# = T2.S# AND T2.C# = 'k2'
LEFT JOIN sc AS T3
ON sc.S# = T3.S# AND T3.C# = 'k3'
LEFT JOIN sc AS T4
ON sc.S# = T4.S# AND T4.C# = 'k4'
ORDER BY ISNULL(T1.score,0) + ISNULL(T2.score,0) + ISNULL(T3.score,0) + ISNULL(T4.score,0) DESC);
23、統計列印各科成績,各分數段人數:課程ID,課程名稱,[100-85],[85-70],[70-60],[ <60]
SELECT SC.C# as 課程ID, Cname as 課程名稱
,SUM(CASE WHEN score BETWEEN 85 AND 100 THEN 1 ELSE 0 END) AS [100 - 85]
,SUM(CASE WHEN score BETWEEN 70 AND 85 THEN 1 ELSE 0 END) AS [85 - 70]
,SUM(CASE WHEN score BETWEEN 60 AND 70 THEN 1 ELSE 0 END) AS [70 - 60]
,SUM(CASE WHEN score < 60 THEN 1 ELSE 0 END) AS [60 -]
FROM SC,Course
where SC.C#=Course.C#
GROUP BY SC.C#,Cname;
24、查詢學生平均成績及其名次
SELECT 1+(SELECT COUNT( distinct 平均成績)
FROM (SELECT S#,AVG(score) AS 平均成績
FROM SC
GROUP BY S#
) AS T1
WHERE 平均成績 > T2.平均成績) as 名次,
S# as 學生學號,平均成績
FROM (SELECT S#,AVG(score) 平均成績
FROM SC
GROUP BY S#
) AS T2
ORDER BY 平均成績 desc;
25、查詢各科成績前三名的記錄:(不考慮成績並列情況)
SELECT t1.S# as 學生ID,t1.C# as 課程ID,Score as 分數
FROM SC t1
WHERE score IN (SELECT TOP 3 score
FROM SC
WHERE t1.C#= C#
ORDER BY score DESC
)
ORDER BY t1.C#;
26、查詢每門課程被選修的學生數
select c#,count(S#) from sc group by C#;
27、查詢出只選修了一門課程的全部學生的學號和姓名
select SC.S#,Student.Sname,count(C#) AS 選課數
from SC ,Student
where SC.S#=Student.S# group by SC.S# ,Student.Sname having count(C#)=1;
28、查詢男生、女生人數
Select count(Ssex) as 男生人數 from Student group by Ssex having Ssex='男';
Select count(Ssex) as 女生人數 from Student group by Ssex having Ssex='女';
29、查詢姓“張”的.學生名單
SELECT Sname FROM Student WHERE Sname like '張%';
30、查詢同名同性學生名單,並統計同名人數
select Sname,count(*) from Student group by Sname having count(*)>1;;
31、1981年出生的學生名單(註:Student表中Sage列的類型是datetime)
select Sname, CONVERT(char (11),DATEPART(year,Sage)) as age
from student
where CONVERT(char(11),DATEPART(year,Sage))='1981';
32、查詢每門課程的平均成績,結果按平均成績升序排列,平均成績相同時,按課程號降序排列
Select C#,Avg(score) from SC group by C# order by Avg(score),C# DESC ;
33、查詢平均成績大於85的所有學生的學號、姓名和平均成績
select Sname,SC.S# ,avg(score)
from Student,SC
where Student.S#=SC.S# group by SC.S#,Sname having avg(score)>85;
34、查詢課程名稱為“資料庫”,且分數低於60的學生姓名和分數
Select Sname,isnull(score,0)
from Student,SC,Course
where SC.S#=Student.S# and SC.C#=Course.C# and Course.Cname='資料庫'and score <60;
35、查詢所有學生的選課情況;
SELECT SC.S#,SC.C#,Sname,Cname
FROM SC,Student,Course
where SC.S#=Student.S# and SC.C#=Course.C# ;
36、查詢任何一門課程成績在70分以上的姓名、課程名稱和分數;
SELECT distinct student.S#,student.Sname,SC.C#,SC.score
FROM student,Sc
WHERE SC.score>=70 AND SC.S#=student.S#;
37、查詢不及格的課程,並按課程號從大到小排列
select c# from sc where scor e <60 order by C# ;
38、查詢課程編號為003且課程成績在80分以上的學生的學號和姓名;
select SC.S#,Student.Sname from SC,Student where SC.S#=Student.S# and Score>80 and C#='003';
39、求選了課程的學生人數
select count(*) from sc;
40、查詢選修“葉平”老師所授課程的學生中,成績最高的學生姓名及其成績
select Student.Sname,score
from Student,SC,Course C,Teacher
where Student.S#=SC.S# and SC.C#=C.C# and C.T#=Teacher.T# and Teacher.Tname='葉平' and SC.score=(select max(score)from SC where C#=C.C# );
41、查詢各個課程及相應的選修人數
select count(*) from sc group by C#;
42、查詢不同課程成績相同的學生的學號、課程號、學生成績
select distinct A.S#,B.score from SC A ,SC B where A.Score=B.Score and A.C# <>B.C# ;
43、查詢每門功成績最好的前兩名
SELECT t1.S# as 學生ID,t1.C# as 課程ID,Score as 分數
FROM SC t1
WHERE score IN (SELECT TOP 2 score
FROM SC
WHERE t1.C#= C#
ORDER BY score DESC
)
ORDER BY t1.C#;
44、統計每門課程的學生選修人數(超過10人的課程才統計)。要求輸出課程號和選修人數,查詢結果按人數降序排列,查詢結果按人數降序排列,若人數相同,按課程號升序排列
select C# as 課程號,count(*) as 人數
from sc
group by C#
order by count(*) desc,c#
45、檢索至少選修兩門課程的學生學號
select S#
from sc
group by s#
having count(*) > = 2
46、查詢全部學生都選修的課程的課程號和課程名
select C#,Cname
from Course
where C# in (select c# from sc group by c#)
47、查詢沒學過“葉平”老師講授的任一門課程的學生姓名
select Sname from Student where S# not in (select S# from Course,Teacher,SC where Course.T#=Teacher.T# and SC.C#=course.C# and Tname='葉平');
48、查詢兩門以上不及格課程的同學的學號及其平均成績
select S#,avg(isnull(score,0)) from SC where S# in (select S# from SC where score <60 group by S# having count(*)>2)group by S#;
49、檢索“004”課程分數小於60,按分數降序排列的同學學號
select S# from SC where C#='004'and score <60 order by score desc;
50、刪除“002”同學的“001”課程的成績
delete from Sc where S#='001'and C#='001';
;❺ sql問題,查找每門課程選課學生,平均分,最高分,最低分 。怎麼解答啊
你好,很高興回答你的問題。
解決這個問題需要用到分組查詢和聚合函數。
sql大致如下:
select 課程,avg(分數),max(分數),min(分數) from 表 group by 課程。
其中avg是算平均分。
max是算最大分。
min是算最小分。
如果有幫助到你,請點擊採納。
我解答的大部分是軟體開發新人遇到的問題,如果有興趣可以關注我。
❻ SQL查詢面試題與答案
SQL查詢面試題與答案
SQL語言是一種資料庫查詢和程序設計語言,用於存取數據以及查詢、更新和管理關系資料庫系統;同時也是資料庫腳本文件的擴展名。下面是我搜集的SQL查詢面試題與答案,歡迎大家閱讀。
SQL查詢面試題與答案一
1.一道SQL語句面試題,關於group by表內容:
2005-05-09 勝
2005-05-09 勝
2005-05-09 負
2005-05-09 負
2005-05-10 勝
2005-05-10 負
2005-05-10 負
如果要生成下列結果, 該如何寫sql語句?
勝 負
2005-05-09 2 2
2005-05-10 1 2
------------------------------------------
create table #tmp(rq varchar(10),shengfu nchar(1))
insert into #tmp values('2005-05-09','勝')
insert into #tmp values('2005-05-09','勝')
insert into #tmp values('2005-05-09','負')
insert into #tmp values('2005-05-09','負')
insert into #tmp values('2005-05-10','勝')
insert into #tmp values('2005-05-10','負')
insert into #tmp values('2005-05-10','負')
1)select rq, sum(case when shengfu='勝' then 1 else 0 end)'勝',sum(case when shengfu='負' then 1 else 0 end)'負' from #tmp group by rq
2) select N.rq,N.勝,M.負 from (
select rq,勝=count(*) from #tmp where shengfu='勝'group by rq)N inner join
(select rq,負=count(*) from #tmp where shengfu='負'group by rq)M on N.rq=M.rq
3)select a.col001,a.a1 勝,b.b1 負 from
(select col001,count(col001) a1 from temp1 where col002='勝' group by col001) a,
(select col001,count(col001) b1 from temp1 where col002='負' group by col001) b
where a.col001=b.col001
2.請教一個面試中遇到的SQL語句的查詢問題
表中有A B C三列,用SQL語句實現:當A列大於B列時選擇A列否則選擇B列,當B列大於C列時選擇B列否則選擇C列。
------------------------------------------
select (case when a>b then a else b end ),
(case when b>c then b esle c end)
from table_name
3.面試題:一個日期判斷的sql語句?
請取出tb_send表中日期(SendTime欄位)為當天的所有記錄?(SendTime欄位為datetime型,包含日期與時間)
------------------------------------------
select * from tb where datediff(dd,SendTime,getdate())=0
4.有一張表,裡面有3個欄位:語文,數學,英語。其中有3條記錄分別表示語文70分,數學80分,英語58分,請用一條sql語句查詢出這三條記錄並按以下條件顯示出來(並寫出您的思路):
大於或等於80表示優秀,大於或等於60表示及格,小於60分表示不及格。
顯示格式:
語文 數學 英語
及格 優秀 不及格
------------------------------------------
select
(case when 語文>=80 then '優秀'
when 語文>=60 then '及格'
else '不及格') as 語文,
(case when 數學>=80 then '優秀'
when 數學>=60 then '及格'
else '不及格') as 數學,
(case when 英語>=80 then '優秀'
when 英語>=60 then '及格'
else '不及格') as 英語,
from table
5.在sqlserver2000中請用sql創建一張用戶臨時表和系統臨時表,裡麵包含兩個欄位ID和IDValues,類型都是int型,並解釋下兩者的區別?
------------------------------------------
用戶臨時表:create table #xx(ID int, IDValues int)
系統臨時表:create table ##xx(ID int, IDValues int)
區別:
用戶臨時表只對創建這個表的用戶的Session可見,對其他進程是不可見的.
當創建它的進程消失時這個臨時表就自動刪除.
全局臨時表對整個SQL Server實例都可見,但是所有訪問它的Session都消失的時候,它也自動刪除.
6.sqlserver2000是一種大型資料庫,他的`存儲容量只受存儲介質的限制,請問它是通過什麼方式實現這種無限容量機制的。
------------------------------------------
它的所有數據都存儲在數據文件中(*.dbf),所以只要文件夠大,SQL Server的存儲容量是可以擴大的.
SQL Server 2000 資料庫有三種類型的文件:
主要數據文件
主要數據文件是資料庫的起點,指向資料庫中文件的其它部分。每個資料庫都有一個主要數據文件。主要數據文件的推薦文件擴展名是 .mdf。
次要數據文件
次要數據文件包含除主要數據文件外的所有數據文件。有些資料庫可能沒有次要數據文件,而有些資料庫則有多個次要數據文件。次要數據文件的推薦文件擴展名是 .ndf。
日誌文件
日誌文件包含恢復資料庫所需的所有日誌信息。每個資料庫必須至少有一個日誌文件,但可以不止一個。日誌文件的推薦文件擴展名是 .ldf。
7.請用一個sql語句得出結果
從table1,table2中取出如table3所列格式數據,注意提供的數據及結果不準確,只是作為一個格式向大家請教。
如使用存儲過程也可以。
table1
月份mon 部門dep 業績yj
-------------------------------
一月份 01 10
一月份 02 10
一月份 03 5
二月份 02 8
二月份 04 9
三月份 03 8
table2
部門dep 部門名稱dname
--------------------------------
01 國內業務一部
02 國內業務二部
03 國內業務三部
04 國際業務部
table3 (result)
部門dep 一月份 二月份 三月份
--------------------------------------
01 10 null null
02 10 8 null
03 null 5 8
04 null null 9
------------------------------------------
1)
select a.部門名稱dname,b.業績yj as '一月份',c.業績yj as '二月份',d.業績yj as '三月份'
from table1 a,table2 b,table2 c,table2 d
where a.部門dep = b.部門dep and b.月份mon = '一月份' and
a.部門dep = c.部門dep and c.月份mon = '二月份' and
a.部門dep = d.部門dep and d.月份mon = '三月份' and
2)
select a.dep,
sum(case when b.mon=1 then b.yj else 0 end) as '一月份',
sum(case when b.mon=2 then b.yj else 0 end) as '二月份',
sum(case when b.mon=3 then b.yj else 0 end) as '三月份',
sum(case when b.mon=4 then b.yj else 0 end) as '四月份',
sum(case when b.mon=5 then b.yj else 0 end) as '五月份',
sum(case when b.mon=6 then b.yj else 0 end) as '六月份',
sum(case when b.mon=7 then b.yj else 0 end) as '七月份',
sum(case when b.mon=8 then b.yj else 0 end) as '八月份',
sum(case when b.mon=9 then b.yj else 0 end) as '九月份',
sum(case when b.mon=10 then b.yj else 0 end) as '十月份',
sum(case when b.mon=11 then b.yj else 0 end) as '十一月份',
sum(case when b.mon=12 then b.yj else 0 end) as '十二月份',
from table2 a left join table1 b on a.dep=b.dep
8.華為一道面試題
一個表中的Id有多個記錄,把所有這個id的記錄查出來,並顯示共有多少條記錄數。
------------------------------------------
select id, Count(*) from tb group by id having count(*)>1
select * from(select count(ID) as count from table group by ID)T where T.count>1
SQL查詢面試題與答案二
1、查詢不同老師所教不同課程平均分從高到低顯示
SELECT max(Z.T#) AS 教師ID,MAX(Z.Tname) AS 教師姓名,C.C# AS 課程ID,MAX(C.Cname) AS 課程名稱,AVG(Score) AS 平均成績
FROM SC AS T,Course AS C ,Teacher AS Z
where T.C#=C.C# and C.T#=Z.T#
GROUP BY C.C#
ORDER BY AVG(Score) DESC
2、查詢如下課程成績第 3 名到第 6 名的學生成績單:企業管理(001),馬克思(002),UML (003),資料庫(004)
[學生ID],[學生姓名],企業管理,馬克思,UML,資料庫,平均成績
SELECT DISTINCT top 3
SC.S# As 學生學號,
Student.Sname AS 學生姓名 ,
T1.score AS 企業管理,
T2.score AS 馬克思,
T3.score AS UML,
T4.score AS 資料庫,
ISNULL(T1.score,0) + ISNULL(T2.score,0) + ISNULL(T3.score,0) + ISNULL(T4.score,0) as 總分
FROM Student,SC LEFT JOIN SC AS T1
ON SC.S# = T1.S# AND T1.C# = '001'
LEFT JOIN SC AS T2
ON SC.S# = T2.S# AND T2.C# = '002'
LEFT JOIN SC AS T3
ON SC.S# = T3.S# AND T3.C# = '003'
LEFT JOIN SC AS T4
ON SC.S# = T4.S# AND T4.C# = '004'
WHERE student.S#=SC.S# and
ISNULL(T1.score,0) + ISNULL(T2.score,0) + ISNULL(T3.score,0) + ISNULL(T4.score,0)
NOT IN
(SELECT
DISTINCT
TOP 15 WITH TIES
ISNULL(T1.score,0) + ISNULL(T2.score,0) + ISNULL(T3.score,0) + ISNULL(T4.score,0)
FROM sc
LEFT JOIN sc AS T1
ON sc.S# = T1.S# AND T1.C# = 'k1'
LEFT JOIN sc AS T2
ON sc.S# = T2.S# AND T2.C# = 'k2'
LEFT JOIN sc AS T3
ON sc.S# = T3.S# AND T3.C# = 'k3'
LEFT JOIN sc AS T4
ON sc.S# = T4.S# AND T4.C# = 'k4'
ORDER BY ISNULL(T1.score,0) + ISNULL(T2.score,0) + ISNULL(T3.score,0) + ISNULL(T4.score,0) DESC);
3、統計列印各科成績,各分數段人數:課程ID,課程名稱,[100-85],[85-70],[70-60],[ <60]
SELECT SC.C# as 課程ID, Cname as 課程名稱
,SUM(CASE WHEN score BETWEEN 85 AND 100 THEN 1 ELSE 0 END) AS [100 - 85]
,SUM(CASE WHEN score BETWEEN 70 AND 85 THEN 1 ELSE 0 END) AS [85 - 70]
,SUM(CASE WHEN score BETWEEN 60 AND 70 THEN 1 ELSE 0 END) AS [70 - 60]
,SUM(CASE WHEN score < 60 THEN 1 ELSE 0 END) AS [60 -]
FROM SC,Course
where SC.C#=Course.C#
GROUP BY SC.C#,Cname;
4、查詢學生平均成績及其名次
SELECT 1+(SELECT COUNT( distinct 平均成績)
FROM (SELECT S#,AVG(score) AS 平均成績
FROM SC
GROUP BY S#
) AS T1
WHERE 平均成績 > T2.平均成績) as 名次,
S# as 學生學號,平均成績
FROM (SELECT S#,AVG(score) 平均成績
FROM SC
GROUP BY S#
) AS T2
ORDER BY 平均成績 desc;
5、查詢各科成績前三名的記錄:(不考慮成績並列情況)
SELECT t1.S# as 學生ID,t1.C# as 課程ID,Score as 分數
FROM SC t1
WHERE score IN (SELECT TOP 3 score
FROM SC
WHERE t1.C#= C#
ORDER BY score DESC
)
ORDER BY t1.C#;
6、查詢每門課程被選修的學生數
select c#,count(S#) from sc group by C#;
7、查詢出只選修了一門課程的全部學生的學號和姓名
select SC.S#,Student.Sname,count(C#) AS 選課數
from SC ,Student
where SC.S#=Student.S# group by SC.S# ,Student.Sname having count(C#)=1;
8、查詢課程編號“002”的成績比課程編號“001”課程低的所有同學的學號、姓名;
Select S#,Sname from (select Student.S#,Student.Sname,score ,(select score from SC SC_2 where SC_2.S#=Student.S# and SC_2.C#='002') score2
from Student,SC where Student.S#=SC.S# and C#='001') S_2 where score2
9、查詢所有課程成績小於60分的同學的學號、姓名;
select S#,Sname
from Student
where S# not in (select Student.S# from Student,SC where S.S#=SC.S# and score>60);
10、查詢沒有學全所有課的同學的學號、姓名;
select Student.S#,Student.Sname
from Student,SC
where Student.S#=SC.S# group by Student.S#,Student.Sname having count(C#) <(select count(C#) from Course);
11、查詢至少有一門課與學號為“1001”的同學所學相同的同學的學號和姓名;
select S#,Sname from Student,SC where Student.S#=SC.S# and C# in select C# from SC where S#='1001';
12、查詢至少學過學號為“001”同學所有一門課的其他同學學號和姓名;
select distinct SC.S#,Sname
from Student,SC
where Student.S#=SC.S# and C# in (select C# from SC where S#='001');
13、把“SC”表中“葉平”老師教的課的成績都更改為此課程的平均成績;
update SC set score=(select avg(SC_2.score)
from SC SC_2
where SC_2.C#=SC.C# ) from Course,Teacher where Course.C#=SC.C# and Course.T#=Teacher.T# and Teacher.Tname='葉平');
14、查詢和“1002”號的同學學習的課程完全相同的其他同學學號和姓名;
select S# from SC where C# in (select C# from SC where S#='1002')
group by S# having count(*)=(select count(*) from SC where S#='1002');
15、刪除學習“葉平”老師課的SC表記錄;
Delect SC
from course ,Teacher
where Course.C#=SC.C# and Course.T#= Teacher.T# and Tname='葉平';
16、向SC表中插入一些記錄,這些記錄要求符合以下條件:沒有上過編號“003”課程的同學學號、2、
號課的平均成績;
Insert SC select S#,'002',(Select avg(score)
from SC where C#='002') from Student where S# not in (Select S# from SC where C#='002');
17、按平均成績從高到低顯示所有學生的“資料庫”、“企業管理”、“英語”三門的課程成績,按如下形式顯示: 學生ID,,資料庫,企業管理,英語,有效課程數,有效平均分
SELECT S# as 學生ID
,(SELECT score FROM SC WHERE SC.S#=t.S# AND C#='004') AS 資料庫
,(SELECT score FROM SC WHERE SC.S#=t.S# AND C#='001') AS 企業管理
,(SELECT score FROM SC WHERE SC.S#=t.S# AND C#='006') AS 英語
,COUNT(*) AS 有效課程數, AVG(t.score) AS 平均成績
FROM SC AS t
GROUP BY S#
ORDER BY avg(t.score)
18、查詢各科成績最高和最低的分:以如下形式顯示:課程ID,最高分,最低分
SELECT L.C# As 課程ID,L.score AS 最高分,R.score AS 最低分
FROM SC L ,SC AS R
WHERE L.C# = R.C# and
L.score = (SELECT MAX(IL.score)
FROM SC AS IL,Student AS IM
WHERE L.C# = IL.C# and IM.S#=IL.S#
GROUP BY IL.C#)
AND
R.Score = (SELECT MIN(IR.score)
FROM SC AS IR
WHERE R.C# = IR.C#
GROUP BY IR.C#
);
19、按各科平均成績從低到高和及格率的百分數從高到低順序
SELECT t.C# AS 課程號,max(course.Cname)AS 課程名,isnull(AVG(score),0) AS 平均成績
,100 * SUM(CASE WHEN isnull(score,0)>=60 THEN 1 ELSE 0 END)/COUNT(*) AS 及格百分數
FROM SC T,Course
where t.C#=course.C#
GROUP BY t.C#
ORDER BY 100 * SUM(CASE WHEN isnull(score,0)>=60 THEN 1 ELSE 0 END)/COUNT(*) DESC
20、查詢如下課程平均成績和及格率的百分數(用"1行"顯示): 企業管理(001),馬克思(002),OO&UML (003),資料庫(004)
SELECT SUM(CASE WHEN C# ='001' THEN score ELSE 0 END)/SUM(CASE C# WHEN '001' THEN 1 ELSE 0 END) AS 企業管理平均分
,100 * SUM(CASE WHEN C# = '001' AND score >= 60 THEN 1 ELSE 0 END)/SUM(CASE WHEN C# = '001' THEN 1 ELSE 0 END) AS 企業管理及格百分數
,SUM(CASE WHEN C# = '002' THEN score ELSE 0 END)/SUM(CASE C# WHEN '002' THEN 1 ELSE 0 END) AS 馬克思平均分
,100 * SUM(CASE WHEN C# = '002' AND score >= 60 THEN 1 ELSE 0 END)/SUM(CASE WHEN C# = '002' THEN 1 ELSE 0 END) AS 馬克思及格百分數
,SUM(CASE WHEN C# = '003' THEN score ELSE 0 END)/SUM(CASE C# WHEN '003' THEN 1 ELSE 0 END) AS UML平均分
,100 * SUM(CASE WHEN C# = '003' AND score >= 60 THEN 1 ELSE 0 END)/SUM(CASE WHEN C# = '003' THEN 1 ELSE 0 END) AS UML及格百分數
,SUM(CASE WHEN C# = '004' THEN score ELSE 0 END)/SUM(CASE C# WHEN '004' THEN 1 ELSE 0 END) AS 資料庫平均分
,100 * SUM(CASE WHEN C# = '004' AND score >= 60 THEN 1 ELSE 0 END)/SUM(CASE WHEN C# = '004' THEN 1 ELSE 0 END) AS 資料庫及格百分數
FROM SC
;❼ 怎麼用SQL的查詢語句列出某同學所有課程的課程名和成績啊,並按成績從低到高排序啊
1、打開Microsoft SQL Server 2012,選中需要查詢所有表的資料庫。
❽ SQL計算並顯示班上每位同學成績的總分和平均分,並按總分從高到低排序
----統計函數----
AVG
--求平均值
COUNT
--統計數目
MAX
--求最大值
MIN
--求最小值
SUM
--求和
order
by
stockid
desc(asc)
---------
排序,desc-降序,asc-升序