當前位置:首頁 » 編程語言 » sql按各科平均成績從低到高
擴展閱讀
webinf下怎麼引入js 2023-08-31 21:54:13
堡壘機怎麼打開web 2023-08-31 21:54:11

sql按各科平均成績從低到高

發布時間: 2022-09-21 10:08:03

資料庫常用sql語句有哪些

資料庫常用sql語句

Student(S#,Sname,Sage,Ssex) 學生表

Course(C#,Cname,T#) 課程表

SC(S#,C#,score) 成績表

Teacher(T#,Tname) 教師表

問題:

1、查詢「001」課程比「002」課程成績高的所有學生的學號;

select a.S# from (select s#,score from SC where C#='001') a,(select s#,score

from SC where C#='002') b

where a.score>b.score and a.s#=b.s#;

2、查詢平均成績大於60分的同學的學號和平均成績;

select S#,avg(score)

from sc

group by S# having avg(score) >60;

3、查詢所有同學的學號、姓名、選課數、總成績;

select Student.S#,Student.Sname,count(SC.C#),sum(score)

from Student left Outer join SC on Student.S#=SC.S#

group by Student.S#,Sname

4、查詢姓「李」的老師的個數;

select count(distinct(Tname))

from Teacher

where Tname like '李%';

5、查詢沒學過「葉平」老師課的同學的學號、姓名;

select Student.S#,Student.Sname

from Student

where S# not in (select distinct( SC.S#) from SC,Course,Teacher where SC.C#=Course.C# and Teacher.T#=Course.T# and Teacher.Tname='葉平');

6、查詢學過「001」並且也學過編號「002」課程的同學的學號、姓名;

select Student.S#,Student.Sname from Student,SC where Student.S#=SC.S# and SC.C#='001'and exists( Select * from SC as SC_2 where SC_2.S#=SC.S# and SC_2.C#='002');

7、查詢學過「葉平」老師所教的所有課的同學的學號、姓名;

select S#,Sname

from Student

where S# in (select S# from SC ,Course ,Teacher where SC.C#=Course.C# and Teacher.T#=Course.T# and Teacher.Tname='葉平' group by S# having count(SC.C#)=(select count(C#) from Course,Teacher where Teacher.T#=Course.T# and Tname='葉平'));

8、查詢課程編號「002」的成績比課程編號「001」課程低的所有同學的學號、姓名;

Select S#,Sname from (select Student.S#,Student.Sname,score ,(select score from SC SC_2 where SC_2.S#=Student.S# and SC_2.C#='002') score2

from Student,SC where Student.S#=SC.S# and C#='001') S_2 where score2<score;

9、查詢所有課程成績小於60分的同學的學號、姓名;

select S#,Sname

from Student

where S# not in (select Student.S# from Student,SC where S.S#=SC.S# and score>60);

10、查詢沒有學全所有課的同學的學號、姓名;

select Student.S#,Student.Sname

from Student,SC

where Student.S#=SC.S# group by Student.S#,Student.Sname having count(C#) <(select count(C#) from Course);

11、查詢至少有一門課與學號為「1001」的同學所學相同的同學的學號和姓名;

select S#,Sname from Student,SC where Student.S#=SC.S# and C# in select C# from SC where S#='1001';

12、查詢至少學過學號為「001」同學所有一門課的其他同學學號和姓名;

select distinct SC.S#,Sname

from Student,SC

where Student.S#=SC.S# and C# in (select C# from SC where S#='001');

13、把「SC」表中「葉平」老師教的課的成績都更改為此課程的平均成績;

SC set score=(select avg(SC_2.score)

from SC SC_2

where SC_2.C#=SC.C# ) from Course,Teacher where Course.C#=SC.C# and Course.T#=Teacher.T# and Teacher.Tname='葉平');

14、查詢和「1002」號的同學學習的課程完全相同的其他同學學號和姓名;

select S# from SC where C# in (select C# from SC where S#='1002')

group by S# having count(*)=(select count(*) from SC where S#='1002');

15、刪除學習「葉平」老師課的SC表記錄;

Delect SC

from course ,Teacher

where Course.C#=SC.C# and Course.T#= Teacher.T# and Tname='葉平';

16、向SC表中插入一些記錄,這些記錄要求符合以下條件:沒有上過編號「003」課程的同學學號、2、

號課的平均成績;

Insert SC select S#,'002',(Select avg(score)

from SC where C#='002') from Student where S# not in (Select S# from SC where C#='002');

17、按平均成績從高到低顯示所有學生的「資料庫」、「企業管理」、「英語」三門的課程成績,按如下形式顯示: 學生ID,,資料庫,企業管理,英語,有效課程數,有效平均分

SELECT S# as 學生ID

,(SELECT score FROM SC WHERE SC.S#=t.S# AND C#='004') AS 資料庫

,(SELECT score FROM SC WHERE SC.S#=t.S# AND C#='001') AS 企業管理

,(SELECT score FROM SC WHERE SC.S#=t.S# AND C#='006') AS 英語

,COUNT(*) AS 有效課程數, AVG(t.score) AS 平均成績

FROM SC AS t

GROUP BY S#

ORDER BY avg(t.score)

18、查詢各科成績最高和最低的分:以如下形式顯示:課程ID,最高分,最低分

SELECT L.C# As 課程ID,L.score AS 最高分,R.score AS 最低分

FROM SC L ,SC AS R

WHERE L.C# = R.C# and

L.score = (SELECT MAX(IL.score)

FROM SC AS IL,Student AS IM

WHERE L.C# = IL.C# and IM.S#=IL.S#

GROUP BY IL.C#)

AND

R.Score = (SELECT MIN(IR.score)

FROM SC AS IR

WHERE R.C# = IR.C#

GROUP BY IR.C#

);

19、按各科平均成績從低到高和及格率的百分數從高到低順序

SELECT t.C# AS 課程號,max(course.Cname)AS 課程名,isnull(AVG(score),0) AS 平均成績

,100 * SUM(CASE WHEN isnull(score,0)>=60 THEN 1 ELSE 0 END)/COUNT(*) AS 及格百分數

FROM SC T,Course

where t.C#=course.C#

GROUP BY t.C#

ORDER BY 100 * SUM(CASE WHEN isnull(score,0)>=60 THEN 1 ELSE 0 END)/COUNT(*) DESC

20、查詢如下課程平均成績和及格率的百分數(用"1行"顯示): 企業管理(001),馬克思(002),OO&UML (003),資料庫(004)

SELECT SUM(CASE WHEN C# ='001' THEN score ELSE 0 END)/SUM(CASE C# WHEN '001' THEN 1 ELSE 0 END) AS 企業管理平均分

,100 * SUM(CASE WHEN C# = '001' AND score >= 60 THEN 1 ELSE 0 END)/SUM(CASE WHEN C# = '001' THEN 1 ELSE 0 END) AS 企業管理及格百分數

,SUM(CASE WHEN C# = '002' THEN score ELSE 0 END)/SUM(CASE C# WHEN '002' THEN 1 ELSE 0 END) AS 馬克思平均分

,100 * SUM(CASE WHEN C# = '002' AND score >= 60 THEN 1 ELSE 0 END)/SUM(CASE WHEN C# = '002' THEN 1 ELSE 0 END) AS 馬克思及格百分數

,SUM(CASE WHEN C# = '003' THEN score ELSE 0 END)/SUM(CASE C# WHEN '003' THEN 1 ELSE 0 END) AS UML平均分

,100 * SUM(CASE WHEN C# = '003' AND score >= 60 THEN 1 ELSE 0 END)/SUM(CASE WHEN C# = '003' THEN 1 ELSE 0 END) AS UML及格百分數

,SUM(CASE WHEN C# = '004' THEN score ELSE 0 END)/SUM(CASE C# WHEN '004' THEN 1 ELSE 0 END) AS 資料庫平均分

,100 * SUM(CASE WHEN C# = '004' AND score >= 60 THEN 1 ELSE 0 END)/SUM(CASE WHEN C# = '004' THEN 1 ELSE 0 END) AS 資料庫及格百分數

FROM SC

21、查詢不同老師所教不同課程平均分從高到低顯示

SELECT max(Z.T#) AS 教師ID,MAX(Z.Tname) AS 教師姓名,C.C# AS 課程ID,MAX(C.Cname) AS 課程名稱,AVG(Score) AS 平均成績

FROM SC AS T,Course AS C ,Teacher AS Z

where T.C#=C.C# and C.T#=Z.T#

GROUP BY C.C#

ORDER BY AVG(Score) DESC

22、查詢如下課程成績第 3 名到第 6 名的學生成績單:企業管理(001),馬克思(002),UML (003),資料庫(004)

[學生ID],[學生姓名],企業管理,馬克思,UML,資料庫,平均成績

SELECT DISTINCT top 3

SC.S# As 學生學號,

Student.Sname AS 學生姓名 ,

T1.score AS 企業管理,

T2.score AS 馬克思,

T3.score AS UML,

T4.score AS 資料庫,

ISNULL(T1.score,0) + ISNULL(T2.score,0) + ISNULL(T3.score,0) + ISNULL(T4.score,0) as 總分

FROM Student,SC LEFT JOIN SC AS T1

ON SC.S# = T1.S# AND T1.C# = '001'

LEFT JOIN SC AS T2

ON SC.S# = T2.S# AND T2.C# = '002'

LEFT JOIN SC AS T3

ON SC.S# = T3.S# AND T3.C# = '003'

LEFT JOIN SC AS T4

ON SC.S# = T4.S# AND T4.C# = '004'

WHERE student.S#=SC.S# and

ISNULL(T1.score,0) + ISNULL(T2.score,0) + ISNULL(T3.score,0) + ISNULL(T4.score,0)

NOT IN

(SELECT

DISTINCT

TOP 15 WITH TIES

ISNULL(T1.score,0) + ISNULL(T2.score,0) + ISNULL(T3.score,0) + ISNULL(T4.score,0)

FROM sc

LEFT JOIN sc AS T1

ON sc.S# = T1.S# AND T1.C# = 'k1'

LEFT JOIN sc AS T2

ON sc.S# = T2.S# AND T2.C# = 'k2'

LEFT JOIN sc AS T3

ON sc.S# = T3.S# AND T3.C# = 'k3'

LEFT JOIN sc AS T4

ON sc.S# = T4.S# AND T4.C# = 'k4'

ORDER BY ISNULL(T1.score,0) + ISNULL(T2.score,0) + ISNULL(T3.score,0) + ISNULL(T4.score,0) DESC);

23、統計列印各科成績,各分數段人數:課程ID,課程名稱,[100-85],[85-70],[70-60],[<60]

SELECT SC.C# as 課程ID, Cname as 課程名稱

,SUM(CASE WHEN score BETWEEN 85 AND 100 THEN 1 ELSE 0 END) AS [100 - 85]

,SUM(CASE WHEN score BETWEEN 70 AND 85 THEN 1 ELSE 0 END) AS [85 - 70]

,SUM(CASE WHEN score BETWEEN 60 AND 70 THEN 1 ELSE 0 END) AS [70 - 60]

,SUM(CASE WHEN score < 60 THEN 1 ELSE 0 END) AS [60 -]

FROM SC,Course

where SC.C#=Course.C#

GROUP BY SC.C#,Cname;

24、查詢學生平均成績及其名次

SELECT 1+(SELECT COUNT( distinct 平均成績)

FROM (SELECT S#,AVG(score) AS 平均成績

FROM SC

GROUP BY S#

) AS T1

WHERE 平均成績 > T2.平均成績) as 名次,

S# as 學生學號,平均成績

FROM (SELECT S#,AVG(score) 平均成績

FROM SC

GROUP BY S#

) AS T2

ORDER BY 平均成績 desc;

25、查詢各科成績前三名的記錄:(不考慮成績並列情況)

SELECT t1.S# as 學生ID,t1.C# as 課程ID,Score as 分數

FROM SC t1

WHERE score IN (SELECT TOP 3 score

FROM SC

WHERE t1.C#= C#

ORDER BY score DESC

)

ORDER BY t1.C#;

26、查詢每門課程被選修的學生數

select c#,count(S#) from sc group by C#;

27、查詢出只選修了一門課程的全部學生的學號和姓名

select SC.S#,Student.Sname,count(C#) AS 選課數

from SC ,Student

where SC.S#=Student.S# group by SC.S# ,Student.Sname having count(C#)=1;

28、查詢男生、女生人數

Select count(Ssex) as 男生人數 from Student group by Ssex having Ssex='男';

Select count(Ssex) as 女生人數 from Student group by Ssex having Ssex='女';

29、查詢姓「張」的學生名單

SELECT Sname FROM Student WHERE Sname like '張%';

30、查詢同名同性學生名單,並統計同名人數

select Sname,count(*) from Student group by Sname having count(*)>1;;

31、1981年出生的學生名單(註:Student表中Sage列的類型是datetime)

select Sname, CONVERT(char (11),DATEPART(year,Sage)) as age

from student

where CONVERT(11),DATEPART(year,Sage))='1981';

32、查詢每門課程的平均成績,結果按平均成績升序排列,平均成績相同時,按課程號降序排列

Select C#,Avg(score) from SC group by C# order by Avg(score),C# DESC ;

33、查詢平均成績大於85的所有學生的學號、姓名和平均成績

select Sname,SC.S# ,avg(score)

from Student,SC

where Student.S#=SC.S# group by SC.S#,Sname having avg(score)>85;

34、查詢課程名稱為「資料庫」,且分數低於60的學生姓名和分數

Select Sname,isnull(score,0)

from Student,SC,Course

where SC.S#=Student.S# and SC.C#=Course.C# and Course.Cname='資料庫'and score<60;

35、查詢所有學生的選課情況;

SELECT SC.S#,SC.C#,Sname,Cname

FROM SC,Student,Course

where SC.S#=Student.S# and SC.C#=Course.C# ;

36、查詢任何一門課程成績在70分以上的姓名、課程名稱和分數;

SELECT distinct student.S#,student.Sname,SC.C#,SC.score

FROM student,Sc

WHERE SC.score>=70 AND SC.S#=student.S#;

37、查詢不及格的課程,並按課程號從大到小排列

select c# from sc where scor e<60 order by C# ;

38、查詢課程編號為003且課程成績在80分以上的學生的學號和姓名;

select SC.S#,Student.Sname from SC,Student where SC.S#=Student.S# and Score>80 and C#='003';

39、求選了課程的學生人數

select count(*) from sc;

40、查詢選修「葉平」老師所授課程的學生中,成績最高的學生姓名及其成績

select Student.Sname,score

from Student,SC,Course C,Teacher

where Student.S#=SC.S# and SC.C#=C.C# and C.T#=Teacher.T# and Teacher.Tname='葉平' and SC.score=(select max(score)from SC where C#=C.C# );

41、查詢各個課程及相應的選修人數

select count(*) from sc group by C#;

42、查詢不同課程成績相同的學生的學號、課程號、學生成績

select distinct A.S#,B.score from SC A ,SC B where A.Score=B.Score and A.C# <>B.C# ;

43、查詢每門功成績最好的前兩名

SELECT t1.S# as 學生ID,t1.C# as 課程ID,Score as 分數

FROM SC t1

WHERE score IN (SELECT TOP 2 score

FROM SC

WHERE t1.C#= C#

ORDER BY score DESC

)

ORDER BY t1.C#;

44、統計每門課程的學生選修人數(超過10人的課程才統計)。要求輸出課程號和選修人數,查詢結果按人數降序排列,查詢結果按人數降序排列,若人數相同,按課程號升序排列

select C# as 課程號,count(*) as 人數

from sc

group by C#

order by count(*) desc,c#

45、檢索至少選修兩門課程的學生學號

select S#

from sc

group by s#

having count(*) > = 2

46、查詢全部學生都選修的課程的'課程號和課程名

select C#,Cname

from Course

where C# in (select c# from sc group by c#)

47、查詢沒學過「葉平」老師講授的任一門課程的學生姓名

select Sname from Student where S# not in (select S# from Course,Teacher,SC where Course.T#=Teacher.T# and SC.C#=course.C# and Tname='葉平');

48、查詢兩門以上不及格課程的同學的學號及其平均成績

select S#,avg(isnull(score,0)) from SC where S# in (select S# from SC where score<60 group="" by="" having="">2)group by S#;

49、檢索「004」課程分數小於60,按分數降序排列的同學學號

select S# from SC where C#='004'and score<60 order by score desc;

50、刪除「002」同學的「001」課程的成績

from Sc where S#='001'and C#='001';

一、SQL語言簡介

1、SQL語言簡介

SQL是結構化查詢語言(Structured Query Language),是用於訪問和處理資料庫的標準的計算機語言。

SQL語言的功能如下:

A、SQL面向資料庫執行查詢

B、SQL可從資料庫取回數據

C、SQL可在資料庫中插入新的記錄

D、SQL可更新資料庫中的數據

E、SQL可從資料庫刪除記錄

F、SQL可創建新資料庫

G、SQL可在資料庫中創建新表

H、SQL可在資料庫中創建存儲過程

I、SQL可在資料庫中創建視圖

J、SQL可以設置表、存儲過程和視圖的許可權

SQL是一門ANSI的標准計算機語言,用來訪問和操作資料庫系統。SQL語句用於取回和更新資料庫中的數據。SQL可與資料庫程序協同工作,比如MS Access、DB2、Informix、MS SQL Server、Oracle、MySQL、Sybase以及其他資料庫系統。

每一種資料庫有自己版本的SQL語言,但是為了與ANSI標准相兼容,SQL必須以相似的方式共同地來支持一些主要的關鍵詞(比如 SELECT、UPDATE、DELETE、INSERT、WHERE等等)。

除了SQL標准之外,大部分SQL資料庫程序都擁有自己的私有擴展。

2、SQL語言分類

SQL語言分為數據定義語言、數據控制語言、數據操作語言、數據查詢語言,分別實現對資料庫數據操作。

二、SQL語言基礎

1、數據定義語言(DDL)

DDL:Data Definition Language

用於定義和管理數據對象,包括資料庫、數據表、函數、視圖、索引、觸發器等。例如:CREATE、DROP、ALTER等語句。

create table student

(

sid INT,

sname var20)

);

alter table student add age int default 20;

student;

drop database student;

2、數據控制語言(DCL)

DCL:Data Control Language

用來管理資料庫的語言,包含授權用戶訪問、拒絕用戶訪問、撤銷授予的許可權。例如:GRANT、DENY、REVOKE、COMMIT、ROLLBACK等語句。

創建用戶

create user 『wang』@『localhost』 identified by 『a1!』;

許可權設置

grant select on db.student to 『wang』@『localhost』;

撤銷許可權

revoke select on db.student from 『wang』@『localhost』;

3、數據操作語言(DML)

DML:Data Manipulation Language

用於操作資料庫對象中所包含的數據,增、刪、改。例如:INSERT、DELETE、UPDATE語句。

4、數據查詢語言(DQL)

DQL:Data Query Language

用於查詢資料庫對象中所包含的數據,能夠進行單表查詢、連接查詢、嵌套查詢,以及集合查詢等各種復雜程度不同的資料庫查詢,並將數據返回到客戶機中顯示。例如:SELECT語句。

三、常量和變數

1、常量

A、字元常量

字元串常量使用單引號或雙引號,數值常量不用加引號。

如果字元串常量中需要換行、有單引號、雙引號 % _

前面需要加轉義字元

換行

』 一個單引號

」 一個雙引號

一個 如果沒有轉義字元 就認為是一個轉義字元

% 一個% 如果沒有轉義字元就認為這是一個通配符

_ 一個_ 如果沒有轉移字元 就認為是一個通配符

select 『hanli』gang001』

select 『han ligang001』

select 『han ligang001』

select 「han"ligang001」

select 「韓立剛001」

B、數值常量

數值常量不用添加引號,

select 100+100+200

C、布爾常量

布爾型常量取值 true 和 false

在SQL中使用1和0表示

select true,false

在表達式中

select 100>200

select 100<200

2、變數

用戶自定義變數使用@開始,使用set給變數賦值。

set @name=『孫悟空』;

select @name;

select * from student;

into student values (6,『孫悟空』,20);

into student values (8,@name,20);

set @sid=9,@nid=10

into student values (@sid,@name,20);

select @sid+@nid;

set @sid=@sid+1;

select @sid;

set @sname3=(select sname from student where sid=9);

select @sname3;

3、系統變數

系統變數分為全局系統變數和會話系統變數。

全局系統變數:針對所有默認設置

會話系統變數:針對當前用戶生效,用戶登錄MySQL會使用全局系統變數,如果會話中更改了變數值,使用更改後的值,不過只針對當前用戶生效。

show variables 顯示會話系統變數

show global variables 顯示全局系統變數

show session variables 顯示會話系統變數

show global variables like 『sql_select_limit』;使用通配符顯示匹配的變數設置

show session variables like 『sql_select_limit』;系統變數使用@@標識

select @@global.sql_select_limit 查看某個全局系統變數設置

select @@session.sql_select_limit 查看某個會話系統變數設置

set @@session.sql_select_limit=2 設置會話系統變數

全局系統變數需要在/etc/my.cnf配置文件中修改。

❷ 用SQL查詢平均成績高於90分的同學的學號、姓名及其平均成績,並按成績由高到低排序

select 學號,姓名,avg(成績) as '平均成績' from 學生成績表 HAVING avg(成績) > 90 order by avg(成績) desc

❸ sql語句 把成績低於總平均成績的女同學的成績提高5%。

把成績低於總平均成績的女同學的成績提高5%的語句如下:

sql語言的特點:

1、SQL風格統一

SQL可以獨立完成資料庫生命周期中的全部活動,包括定義關系模式、錄入數據、建立資料庫、査詢、更新、維護、資料庫重構、資料庫安全性控制等一系列操作,這就為資料庫應用系統開發提供了良好的環境。

在資料庫投入運行後,還可根據需要隨時逐步修改模式,且不影響資料庫的運行,從而使系統具有良好的可擴充性。

2、高度非過程化

非關系數據模型的數據操縱語言是面向過程的語言,用其完成用戶請求時,必須指定存取路徑。而用SQL進行數據操作,用戶只需提出「做什麼」,而不必指明「怎麼做」。

因此用戶無須了解存取路徑,存取路徑的選擇以及SQL語句的操作過程由系統自動完成。這不但大大減輕了用戶負擔,而且有利於提高數據獨立性。

❹ 資料庫常用sql語句有哪些

資料庫常用sql語句有哪些

SQL語句有哪些?SQL語句無論是種類還是數量都是繁多的,很多語句也是經常要用到的,下文我為大家分享的就是SQL的常用語句,僅供參考!

50個常用的sql語句

Student(S#,Sname,Sage,Ssex) 學生表

Course(C#,Cname,T#) 課程表

SC(S#,C#,score) 成績表

Teacher(T#,Tname) 教師表

問題:

1、查詢“001”課程比“002”課程成績高的所有學生的學號;

select a.S# from (select s#,score from SC where C#='001') a,(select s#,score

from SC where C#='002') b

where a.score>b.score and a.s#=b.s#;

2、查詢平均成績大於60分的同學的學號和平均成績;

select S#,avg(score)

from sc

group by S# having avg(score) >60;

3、查詢所有同學的學號、姓名、選課數、總成績;

select Student.S#,Student.Sname,count(SC.C#),sum(score)

from Student left Outer join SC on Student.S#=SC.S#

group by Student.S#,Sname

4、查詢姓“李”的老師的個數;

select count(distinct(Tname))

from Teacher

where Tname like '李%';

5、查詢沒學過“葉平”老師課的同學的學號、姓名;

select Student.S#,Student.Sname

from Student

where S# not in (select distinct( SC.S#) from SC,Course,Teacher where SC.C#=Course.C# and Teacher.T#=Course.T# and Teacher.Tname='葉平');

6、查詢學過“001”並且也學過編號“002”課程的同學的學號、姓名;

select Student.S#,Student.Sname from Student,SC where Student.S#=SC.S# and SC.C#='001'and exists( Select * from SC as SC_2 where SC_2.S#=SC.S# and SC_2.C#='002');

7、查詢學過“葉平”老師所教的所有課的同學的學號、姓名;

select S#,Sname

from Student

where S# in (select S# from SC ,Course ,Teacher where SC.C#=Course.C# and Teacher.T#=Course.T# and Teacher.Tname='葉平' group by S# having count(SC.C#)=(select count(C#) from Course,Teacher where Teacher.T#=Course.T# and Tname='葉平'));

8、查詢課程編號“002”的成績比課程編號“001”課程低的所有同學的學號、姓名;

Select S#,Sname from (select Student.S#,Student.Sname,score ,(select score from SC SC_2 where SC_2.S#=Student.S# and SC_2.C#='002') score2

from Student,SC where Student.S#=SC.S# and C#='001') S_2 where score2 <score;

9、查詢所有課程成績小於60分的同學的學號、姓名;

select S#,Sname

from Student

where S# not in (select Student.S# from Student,SC where S.S#=SC.S# and score>60);

10、查詢沒有學全所有課的同學的學號、姓名;

select Student.S#,Student.Sname

from Student,SC

where Student.S#=SC.S# group by Student.S#,Student.Sname having count(C#) <(select count(C#) from Course);

11、查詢至少有一門課與學號為“1001”的同學所學相同的同學的學號和姓名;

select S#,Sname from Student,SC where Student.S#=SC.S# and C# in select C# from SC where S#='1001';

12、查詢至少學過學號為“001”同學所有一門課的其他同學學號和姓名;

select distinct SC.S#,Sname

from Student,SC

where Student.S#=SC.S# and C# in (select C# from SC where S#='001');

13、把“SC”表中“葉平”老師教的課的成績都更改為此課程的平均成績;

update SC set score=(select avg(SC_2.score)

from SC SC_2

where SC_2.C#=SC.C# ) from Course,Teacher where Course.C#=SC.C# and Course.T#=Teacher.T# and Teacher.Tname='葉平');

14、查詢和“1002”號的同學學習的課程完全相同的其他同學學號和姓名;

select S# from SC where C# in (select C# from SC where S#='1002')

group by S# having count(*)=(select count(*) from SC where S#='1002');

15、刪除學習“葉平”老師課的SC表記錄;

Delect SC

from course ,Teacher

where Course.C#=SC.C# and Course.T#= Teacher.T# and Tname='葉平';

16、向SC表中插入一些記錄,這些記錄要求符合以下條件:沒有上過編號“003”課程的同學學號、2、

號課的平均成績;

Insert SC select S#,'002',(Select avg(score)

from SC where C#='002') from Student where S# not in (Select S# from SC where C#='002');

17、按平均成績從高到低顯示所有學生的“資料庫”、“企業管理”、“英語”三門的課程成績,按如下形式顯示: 學生ID,,資料庫,企業管理,英語,有效課程數,有效平均分

SELECT S# as 學生ID

,(SELECT score FROM SC WHERE SC.S#=t.S# AND C#='004') AS 資料庫

,(SELECT score FROM SC WHERE SC.S#=t.S# AND C#='001') AS 企業管理

,(SELECT score FROM SC WHERE SC.S#=t.S# AND C#='006') AS 英語

,COUNT(*) AS 有效課程數, AVG(t.score) AS 平均成績

FROM SC AS t

GROUP BY S#

ORDER BY avg(t.score)

18、查詢各科成績最高和最低的分:以如下形式顯示:課程ID,最高分,最低分

SELECT L.C# As 課程ID,L.score AS 最高分,R.score AS 最低分

FROM SC L ,SC AS R

WHERE L.C# = R.C# and

L.score = (SELECT MAX(IL.score)

FROM SC AS IL,Student AS IM

WHERE L.C# = IL.C# and IM.S#=IL.S#

GROUP BY IL.C#)

AND

R.Score = (SELECT MIN(IR.score)

FROM SC AS IR

WHERE R.C# = IR.C#

GROUP BY IR.C#

);

19、按各科平均成績從低到高和及格率的百分數從高到低順序

SELECT t.C# AS 課程號,max(course.Cname)AS 課程名,isnull(AVG(score),0) AS 平均成績

,100 * SUM(CASE WHEN isnull(score,0)>=60 THEN 1 ELSE 0 END)/COUNT(*) AS 及格百分數

FROM SC T,Course

where t.C#=course.C#

GROUP BY t.C#

ORDER BY 100 * SUM(CASE WHEN isnull(score,0)>=60 THEN 1 ELSE 0 END)/COUNT(*) DESC

20、查詢如下課程平均成績和及格率的百分數(用"1行"顯示): 企業管理(001),馬克思(002),OO&UML (003),資料庫(004)

SELECT SUM(CASE WHEN C# ='001' THEN score ELSE 0 END)/SUM(CASE C# WHEN '001' THEN 1 ELSE 0 END) AS 企業管理平均分

,100 * SUM(CASE WHEN C# = '001' AND score >= 60 THEN 1 ELSE 0 END)/SUM(CASE WHEN C# = '001' THEN 1 ELSE 0 END) AS 企業管理及格百分數

,SUM(CASE WHEN C# = '002' THEN score ELSE 0 END)/SUM(CASE C# WHEN '002' THEN 1 ELSE 0 END) AS 馬克思平均分

,100 * SUM(CASE WHEN C# = '002' AND score >= 60 THEN 1 ELSE 0 END)/SUM(CASE WHEN C# = '002' THEN 1 ELSE 0 END) AS 馬克思及格百分數

,SUM(CASE WHEN C# = '003' THEN score ELSE 0 END)/SUM(CASE C# WHEN '003' THEN 1 ELSE 0 END) AS UML平均分

,100 * SUM(CASE WHEN C# = '003' AND score >= 60 THEN 1 ELSE 0 END)/SUM(CASE WHEN C# = '003' THEN 1 ELSE 0 END) AS UML及格百分數

,SUM(CASE WHEN C# = '004' THEN score ELSE 0 END)/SUM(CASE C# WHEN '004' THEN 1 ELSE 0 END) AS 資料庫平均分

,100 * SUM(CASE WHEN C# = '004' AND score >= 60 THEN 1 ELSE 0 END)/SUM(CASE WHEN C# = '004' THEN 1 ELSE 0 END) AS 資料庫及格百分數

FROM SC

21、查詢不同老師所教不同課程平均分從高到低顯示

SELECT max(Z.T#) AS 教師ID,MAX(Z.Tname) AS 教師姓名,C.C# AS 課程ID,MAX(C.Cname) AS 課程名稱,AVG(Score) AS 平均成績

FROM SC AS T,Course AS C ,Teacher AS Z

where T.C#=C.C# and C.T#=Z.T#

GROUP BY C.C#

ORDER BY AVG(Score) DESC

22、查詢如下課程成績第 3 名到第 6 名的學生成績單:企業管理(001),馬克思(002),UML (003),資料庫(004)

[學生ID],[學生姓名],企業管理,馬克思,UML,資料庫,平均成績

SELECT DISTINCT top 3

SC.S# As 學生學號,

Student.Sname AS 學生姓名 ,

T1.score AS 企業管理,

T2.score AS 馬克思,

T3.score AS UML,

T4.score AS 資料庫,

ISNULL(T1.score,0) + ISNULL(T2.score,0) + ISNULL(T3.score,0) + ISNULL(T4.score,0) as 總分

FROM Student,SC LEFT JOIN SC AS T1

ON SC.S# = T1.S# AND T1.C# = '001'

LEFT JOIN SC AS T2

ON SC.S# = T2.S# AND T2.C# = '002'

LEFT JOIN SC AS T3

ON SC.S# = T3.S# AND T3.C# = '003'

LEFT JOIN SC AS T4

ON SC.S# = T4.S# AND T4.C# = '004'

WHERE student.S#=SC.S# and

ISNULL(T1.score,0) + ISNULL(T2.score,0) + ISNULL(T3.score,0) + ISNULL(T4.score,0)

NOT IN

(SELECT

DISTINCT

TOP 15 WITH TIES

ISNULL(T1.score,0) + ISNULL(T2.score,0) + ISNULL(T3.score,0) + ISNULL(T4.score,0)

FROM sc

LEFT JOIN sc AS T1

ON sc.S# = T1.S# AND T1.C# = 'k1'

LEFT JOIN sc AS T2

ON sc.S# = T2.S# AND T2.C# = 'k2'

LEFT JOIN sc AS T3

ON sc.S# = T3.S# AND T3.C# = 'k3'

LEFT JOIN sc AS T4

ON sc.S# = T4.S# AND T4.C# = 'k4'

ORDER BY ISNULL(T1.score,0) + ISNULL(T2.score,0) + ISNULL(T3.score,0) + ISNULL(T4.score,0) DESC);

23、統計列印各科成績,各分數段人數:課程ID,課程名稱,[100-85],[85-70],[70-60],[ <60]

SELECT SC.C# as 課程ID, Cname as 課程名稱

,SUM(CASE WHEN score BETWEEN 85 AND 100 THEN 1 ELSE 0 END) AS [100 - 85]

,SUM(CASE WHEN score BETWEEN 70 AND 85 THEN 1 ELSE 0 END) AS [85 - 70]

,SUM(CASE WHEN score BETWEEN 60 AND 70 THEN 1 ELSE 0 END) AS [70 - 60]

,SUM(CASE WHEN score < 60 THEN 1 ELSE 0 END) AS [60 -]

FROM SC,Course

where SC.C#=Course.C#

GROUP BY SC.C#,Cname;

24、查詢學生平均成績及其名次

SELECT 1+(SELECT COUNT( distinct 平均成績)

FROM (SELECT S#,AVG(score) AS 平均成績

FROM SC

GROUP BY S#

) AS T1

WHERE 平均成績 > T2.平均成績) as 名次,

S# as 學生學號,平均成績

FROM (SELECT S#,AVG(score) 平均成績

FROM SC

GROUP BY S#

) AS T2

ORDER BY 平均成績 desc;

25、查詢各科成績前三名的記錄:(不考慮成績並列情況)

SELECT t1.S# as 學生ID,t1.C# as 課程ID,Score as 分數

FROM SC t1

WHERE score IN (SELECT TOP 3 score

FROM SC

WHERE t1.C#= C#

ORDER BY score DESC

)

ORDER BY t1.C#;

26、查詢每門課程被選修的學生數

select c#,count(S#) from sc group by C#;

27、查詢出只選修了一門課程的全部學生的學號和姓名

select SC.S#,Student.Sname,count(C#) AS 選課數

from SC ,Student

where SC.S#=Student.S# group by SC.S# ,Student.Sname having count(C#)=1;

28、查詢男生、女生人數

Select count(Ssex) as 男生人數 from Student group by Ssex having Ssex='男';

Select count(Ssex) as 女生人數 from Student group by Ssex having Ssex='女';

29、查詢姓“張”的.學生名單

SELECT Sname FROM Student WHERE Sname like '張%';

30、查詢同名同性學生名單,並統計同名人數

select Sname,count(*) from Student group by Sname having count(*)>1;;

31、1981年出生的學生名單(註:Student表中Sage列的類型是datetime)

select Sname, CONVERT(char (11),DATEPART(year,Sage)) as age

from student

where CONVERT(char(11),DATEPART(year,Sage))='1981';

32、查詢每門課程的平均成績,結果按平均成績升序排列,平均成績相同時,按課程號降序排列

Select C#,Avg(score) from SC group by C# order by Avg(score),C# DESC ;

33、查詢平均成績大於85的所有學生的學號、姓名和平均成績

select Sname,SC.S# ,avg(score)

from Student,SC

where Student.S#=SC.S# group by SC.S#,Sname having avg(score)>85;

34、查詢課程名稱為“資料庫”,且分數低於60的學生姓名和分數

Select Sname,isnull(score,0)

from Student,SC,Course

where SC.S#=Student.S# and SC.C#=Course.C# and Course.Cname='資料庫'and score <60;

35、查詢所有學生的選課情況;

SELECT SC.S#,SC.C#,Sname,Cname

FROM SC,Student,Course

where SC.S#=Student.S# and SC.C#=Course.C# ;

36、查詢任何一門課程成績在70分以上的姓名、課程名稱和分數;

SELECT distinct student.S#,student.Sname,SC.C#,SC.score

FROM student,Sc

WHERE SC.score>=70 AND SC.S#=student.S#;

37、查詢不及格的課程,並按課程號從大到小排列

select c# from sc where scor e <60 order by C# ;

38、查詢課程編號為003且課程成績在80分以上的學生的學號和姓名;

select SC.S#,Student.Sname from SC,Student where SC.S#=Student.S# and Score>80 and C#='003';

39、求選了課程的學生人數

select count(*) from sc;

40、查詢選修“葉平”老師所授課程的學生中,成績最高的學生姓名及其成績

select Student.Sname,score

from Student,SC,Course C,Teacher

where Student.S#=SC.S# and SC.C#=C.C# and C.T#=Teacher.T# and Teacher.Tname='葉平' and SC.score=(select max(score)from SC where C#=C.C# );

41、查詢各個課程及相應的選修人數

select count(*) from sc group by C#;

42、查詢不同課程成績相同的學生的學號、課程號、學生成績

select distinct A.S#,B.score from SC A ,SC B where A.Score=B.Score and A.C# <>B.C# ;

43、查詢每門功成績最好的前兩名

SELECT t1.S# as 學生ID,t1.C# as 課程ID,Score as 分數

FROM SC t1

WHERE score IN (SELECT TOP 2 score

FROM SC

WHERE t1.C#= C#

ORDER BY score DESC

)

ORDER BY t1.C#;

44、統計每門課程的學生選修人數(超過10人的課程才統計)。要求輸出課程號和選修人數,查詢結果按人數降序排列,查詢結果按人數降序排列,若人數相同,按課程號升序排列

select C# as 課程號,count(*) as 人數

from sc

group by C#

order by count(*) desc,c#

45、檢索至少選修兩門課程的學生學號

select S#

from sc

group by s#

having count(*) > = 2

46、查詢全部學生都選修的課程的課程號和課程名

select C#,Cname

from Course

where C# in (select c# from sc group by c#)

47、查詢沒學過“葉平”老師講授的任一門課程的學生姓名

select Sname from Student where S# not in (select S# from Course,Teacher,SC where Course.T#=Teacher.T# and SC.C#=course.C# and Tname='葉平');

48、查詢兩門以上不及格課程的同學的學號及其平均成績

select S#,avg(isnull(score,0)) from SC where S# in (select S# from SC where score <60 group by S# having count(*)>2)group by S#;

49、檢索“004”課程分數小於60,按分數降序排列的同學學號

select S# from SC where C#='004'and score <60 order by score desc;

50、刪除“002”同學的“001”課程的成績

delete from Sc where S#='001'and C#='001';

;

❺ sql問題,查找每門課程選課學生,平均分,最高分,最低分 。怎麼解答啊

你好,很高興回答你的問題。
解決這個問題需要用到分組查詢和聚合函數。
sql大致如下:
select 課程,avg(分數),max(分數),min(分數) from 表 group by 課程。
其中avg是算平均分。
max是算最大分。
min是算最小分。
如果有幫助到你,請點擊採納。
我解答的大部分是軟體開發新人遇到的問題,如果有興趣可以關注我。

❻ SQL查詢面試題與答案

SQL查詢面試題與答案

SQL語言是一種資料庫查詢和程序設計語言,用於存取數據以及查詢、更新和管理關系資料庫系統;同時也是資料庫腳本文件的擴展名。下面是我搜集的SQL查詢面試題與答案,歡迎大家閱讀。

SQL查詢面試題與答案一

1.一道SQL語句面試題,關於group by表內容:

2005-05-09 勝

2005-05-09 勝

2005-05-09 負

2005-05-09 負

2005-05-10 勝

2005-05-10 負

2005-05-10 負

如果要生成下列結果, 該如何寫sql語句?

勝 負

2005-05-09 2 2

2005-05-10 1 2

------------------------------------------

create table #tmp(rq varchar(10),shengfu nchar(1))

insert into #tmp values('2005-05-09','勝')

insert into #tmp values('2005-05-09','勝')

insert into #tmp values('2005-05-09','負')

insert into #tmp values('2005-05-09','負')

insert into #tmp values('2005-05-10','勝')

insert into #tmp values('2005-05-10','負')

insert into #tmp values('2005-05-10','負')

1)select rq, sum(case when shengfu='勝' then 1 else 0 end)'勝',sum(case when shengfu='負' then 1 else 0 end)'負' from #tmp group by rq

2) select N.rq,N.勝,M.負 from (

select rq,勝=count(*) from #tmp where shengfu='勝'group by rq)N inner join

(select rq,負=count(*) from #tmp where shengfu='負'group by rq)M on N.rq=M.rq

3)select a.col001,a.a1 勝,b.b1 負 from

(select col001,count(col001) a1 from temp1 where col002='勝' group by col001) a,

(select col001,count(col001) b1 from temp1 where col002='負' group by col001) b

where a.col001=b.col001

2.請教一個面試中遇到的SQL語句的查詢問題

表中有A B C三列,用SQL語句實現:當A列大於B列時選擇A列否則選擇B列,當B列大於C列時選擇B列否則選擇C列。

------------------------------------------

select (case when a>b then a else b end ),

(case when b>c then b esle c end)

from table_name

3.面試題:一個日期判斷的sql語句?

請取出tb_send表中日期(SendTime欄位)為當天的所有記錄?(SendTime欄位為datetime型,包含日期與時間)

------------------------------------------

select * from tb where datediff(dd,SendTime,getdate())=0

4.有一張表,裡面有3個欄位:語文,數學,英語。其中有3條記錄分別表示語文70分,數學80分,英語58分,請用一條sql語句查詢出這三條記錄並按以下條件顯示出來(並寫出您的思路):

大於或等於80表示優秀,大於或等於60表示及格,小於60分表示不及格。

顯示格式:

語文 數學 英語

及格 優秀 不及格

------------------------------------------

select

(case when 語文>=80 then '優秀'

when 語文>=60 then '及格'

else '不及格') as 語文,

(case when 數學>=80 then '優秀'

when 數學>=60 then '及格'

else '不及格') as 數學,

(case when 英語>=80 then '優秀'

when 英語>=60 then '及格'

else '不及格') as 英語,

from table

5.在sqlserver2000中請用sql創建一張用戶臨時表和系統臨時表,裡麵包含兩個欄位ID和IDValues,類型都是int型,並解釋下兩者的區別?

------------------------------------------

用戶臨時表:create table #xx(ID int, IDValues int)

系統臨時表:create table ##xx(ID int, IDValues int)

區別:

用戶臨時表只對創建這個表的用戶的Session可見,對其他進程是不可見的.

當創建它的進程消失時這個臨時表就自動刪除.

全局臨時表對整個SQL Server實例都可見,但是所有訪問它的Session都消失的時候,它也自動刪除.

6.sqlserver2000是一種大型資料庫,他的`存儲容量只受存儲介質的限制,請問它是通過什麼方式實現這種無限容量機制的。

------------------------------------------

它的所有數據都存儲在數據文件中(*.dbf),所以只要文件夠大,SQL Server的存儲容量是可以擴大的.

SQL Server 2000 資料庫有三種類型的文件:

主要數據文件

主要數據文件是資料庫的起點,指向資料庫中文件的其它部分。每個資料庫都有一個主要數據文件。主要數據文件的推薦文件擴展名是 .mdf。

次要數據文件

次要數據文件包含除主要數據文件外的所有數據文件。有些資料庫可能沒有次要數據文件,而有些資料庫則有多個次要數據文件。次要數據文件的推薦文件擴展名是 .ndf。

日誌文件

日誌文件包含恢復資料庫所需的所有日誌信息。每個資料庫必須至少有一個日誌文件,但可以不止一個。日誌文件的推薦文件擴展名是 .ldf。

7.請用一個sql語句得出結果

從table1,table2中取出如table3所列格式數據,注意提供的數據及結果不準確,只是作為一個格式向大家請教。

如使用存儲過程也可以。

table1

月份mon 部門dep 業績yj

-------------------------------

一月份 01 10

一月份 02 10

一月份 03 5

二月份 02 8

二月份 04 9

三月份 03 8

table2

部門dep 部門名稱dname

--------------------------------

01 國內業務一部

02 國內業務二部

03 國內業務三部

04 國際業務部

table3 (result)

部門dep 一月份 二月份 三月份

--------------------------------------

01 10 null null

02 10 8 null

03 null 5 8

04 null null 9

------------------------------------------

1)

select a.部門名稱dname,b.業績yj as '一月份',c.業績yj as '二月份',d.業績yj as '三月份'

from table1 a,table2 b,table2 c,table2 d

where a.部門dep = b.部門dep and b.月份mon = '一月份' and

a.部門dep = c.部門dep and c.月份mon = '二月份' and

a.部門dep = d.部門dep and d.月份mon = '三月份' and

2)

select a.dep,

sum(case when b.mon=1 then b.yj else 0 end) as '一月份',

sum(case when b.mon=2 then b.yj else 0 end) as '二月份',

sum(case when b.mon=3 then b.yj else 0 end) as '三月份',

sum(case when b.mon=4 then b.yj else 0 end) as '四月份',

sum(case when b.mon=5 then b.yj else 0 end) as '五月份',

sum(case when b.mon=6 then b.yj else 0 end) as '六月份',

sum(case when b.mon=7 then b.yj else 0 end) as '七月份',

sum(case when b.mon=8 then b.yj else 0 end) as '八月份',

sum(case when b.mon=9 then b.yj else 0 end) as '九月份',

sum(case when b.mon=10 then b.yj else 0 end) as '十月份',

sum(case when b.mon=11 then b.yj else 0 end) as '十一月份',

sum(case when b.mon=12 then b.yj else 0 end) as '十二月份',

from table2 a left join table1 b on a.dep=b.dep

8.華為一道面試題

一個表中的Id有多個記錄,把所有這個id的記錄查出來,並顯示共有多少條記錄數。

------------------------------------------

select id, Count(*) from tb group by id having count(*)>1

select * from(select count(ID) as count from table group by ID)T where T.count>1

SQL查詢面試題與答案二

1、查詢不同老師所教不同課程平均分從高到低顯示

SELECT max(Z.T#) AS 教師ID,MAX(Z.Tname) AS 教師姓名,C.C# AS 課程ID,MAX(C.Cname) AS 課程名稱,AVG(Score) AS 平均成績

FROM SC AS T,Course AS C ,Teacher AS Z

where T.C#=C.C# and C.T#=Z.T#

GROUP BY C.C#

ORDER BY AVG(Score) DESC

2、查詢如下課程成績第 3 名到第 6 名的學生成績單:企業管理(001),馬克思(002),UML (003),資料庫(004)

[學生ID],[學生姓名],企業管理,馬克思,UML,資料庫,平均成績

SELECT DISTINCT top 3

SC.S# As 學生學號,

Student.Sname AS 學生姓名 ,

T1.score AS 企業管理,

T2.score AS 馬克思,

T3.score AS UML,

T4.score AS 資料庫,

ISNULL(T1.score,0) + ISNULL(T2.score,0) + ISNULL(T3.score,0) + ISNULL(T4.score,0) as 總分

FROM Student,SC LEFT JOIN SC AS T1

ON SC.S# = T1.S# AND T1.C# = '001'

LEFT JOIN SC AS T2

ON SC.S# = T2.S# AND T2.C# = '002'

LEFT JOIN SC AS T3

ON SC.S# = T3.S# AND T3.C# = '003'

LEFT JOIN SC AS T4

ON SC.S# = T4.S# AND T4.C# = '004'

WHERE student.S#=SC.S# and

ISNULL(T1.score,0) + ISNULL(T2.score,0) + ISNULL(T3.score,0) + ISNULL(T4.score,0)

NOT IN

(SELECT

DISTINCT

TOP 15 WITH TIES

ISNULL(T1.score,0) + ISNULL(T2.score,0) + ISNULL(T3.score,0) + ISNULL(T4.score,0)

FROM sc

LEFT JOIN sc AS T1

ON sc.S# = T1.S# AND T1.C# = 'k1'

LEFT JOIN sc AS T2

ON sc.S# = T2.S# AND T2.C# = 'k2'

LEFT JOIN sc AS T3

ON sc.S# = T3.S# AND T3.C# = 'k3'

LEFT JOIN sc AS T4

ON sc.S# = T4.S# AND T4.C# = 'k4'

ORDER BY ISNULL(T1.score,0) + ISNULL(T2.score,0) + ISNULL(T3.score,0) + ISNULL(T4.score,0) DESC);

3、統計列印各科成績,各分數段人數:課程ID,課程名稱,[100-85],[85-70],[70-60],[ <60]

SELECT SC.C# as 課程ID, Cname as 課程名稱

,SUM(CASE WHEN score BETWEEN 85 AND 100 THEN 1 ELSE 0 END) AS [100 - 85]

,SUM(CASE WHEN score BETWEEN 70 AND 85 THEN 1 ELSE 0 END) AS [85 - 70]

,SUM(CASE WHEN score BETWEEN 60 AND 70 THEN 1 ELSE 0 END) AS [70 - 60]

,SUM(CASE WHEN score < 60 THEN 1 ELSE 0 END) AS [60 -]

FROM SC,Course

where SC.C#=Course.C#

GROUP BY SC.C#,Cname;

4、查詢學生平均成績及其名次

SELECT 1+(SELECT COUNT( distinct 平均成績)

FROM (SELECT S#,AVG(score) AS 平均成績

FROM SC

GROUP BY S#

) AS T1

WHERE 平均成績 > T2.平均成績) as 名次,

S# as 學生學號,平均成績

FROM (SELECT S#,AVG(score) 平均成績

FROM SC

GROUP BY S#

) AS T2

ORDER BY 平均成績 desc;

5、查詢各科成績前三名的記錄:(不考慮成績並列情況)

SELECT t1.S# as 學生ID,t1.C# as 課程ID,Score as 分數

FROM SC t1

WHERE score IN (SELECT TOP 3 score

FROM SC

WHERE t1.C#= C#

ORDER BY score DESC

)

ORDER BY t1.C#;

6、查詢每門課程被選修的學生數

select c#,count(S#) from sc group by C#;

7、查詢出只選修了一門課程的全部學生的學號和姓名

select SC.S#,Student.Sname,count(C#) AS 選課數

from SC ,Student

where SC.S#=Student.S# group by SC.S# ,Student.Sname having count(C#)=1;

8、查詢課程編號“002”的成績比課程編號“001”課程低的所有同學的學號、姓名;

Select S#,Sname from (select Student.S#,Student.Sname,score ,(select score from SC SC_2 where SC_2.S#=Student.S# and SC_2.C#='002') score2

from Student,SC where Student.S#=SC.S# and C#='001') S_2 where score2

9、查詢所有課程成績小於60分的同學的學號、姓名;

select S#,Sname

from Student

where S# not in (select Student.S# from Student,SC where S.S#=SC.S# and score>60);

10、查詢沒有學全所有課的同學的學號、姓名;

select Student.S#,Student.Sname

from Student,SC

where Student.S#=SC.S# group by Student.S#,Student.Sname having count(C#) <(select count(C#) from Course);

11、查詢至少有一門課與學號為“1001”的同學所學相同的同學的學號和姓名;

select S#,Sname from Student,SC where Student.S#=SC.S# and C# in select C# from SC where S#='1001';

12、查詢至少學過學號為“001”同學所有一門課的其他同學學號和姓名;

select distinct SC.S#,Sname

from Student,SC

where Student.S#=SC.S# and C# in (select C# from SC where S#='001');

13、把“SC”表中“葉平”老師教的課的成績都更改為此課程的平均成績;

update SC set score=(select avg(SC_2.score)

from SC SC_2

where SC_2.C#=SC.C# ) from Course,Teacher where Course.C#=SC.C# and Course.T#=Teacher.T# and Teacher.Tname='葉平');

14、查詢和“1002”號的同學學習的課程完全相同的其他同學學號和姓名;

select S# from SC where C# in (select C# from SC where S#='1002')

group by S# having count(*)=(select count(*) from SC where S#='1002');

15、刪除學習“葉平”老師課的SC表記錄;

Delect SC

from course ,Teacher

where Course.C#=SC.C# and Course.T#= Teacher.T# and Tname='葉平';

16、向SC表中插入一些記錄,這些記錄要求符合以下條件:沒有上過編號“003”課程的同學學號、2、

號課的平均成績;

Insert SC select S#,'002',(Select avg(score)

from SC where C#='002') from Student where S# not in (Select S# from SC where C#='002');

17、按平均成績從高到低顯示所有學生的“資料庫”、“企業管理”、“英語”三門的課程成績,按如下形式顯示: 學生ID,,資料庫,企業管理,英語,有效課程數,有效平均分

SELECT S# as 學生ID

,(SELECT score FROM SC WHERE SC.S#=t.S# AND C#='004') AS 資料庫

,(SELECT score FROM SC WHERE SC.S#=t.S# AND C#='001') AS 企業管理

,(SELECT score FROM SC WHERE SC.S#=t.S# AND C#='006') AS 英語

,COUNT(*) AS 有效課程數, AVG(t.score) AS 平均成績

FROM SC AS t

GROUP BY S#

ORDER BY avg(t.score)

18、查詢各科成績最高和最低的分:以如下形式顯示:課程ID,最高分,最低分

SELECT L.C# As 課程ID,L.score AS 最高分,R.score AS 最低分

FROM SC L ,SC AS R

WHERE L.C# = R.C# and

L.score = (SELECT MAX(IL.score)

FROM SC AS IL,Student AS IM

WHERE L.C# = IL.C# and IM.S#=IL.S#

GROUP BY IL.C#)

AND

R.Score = (SELECT MIN(IR.score)

FROM SC AS IR

WHERE R.C# = IR.C#

GROUP BY IR.C#

);

19、按各科平均成績從低到高和及格率的百分數從高到低順序

SELECT t.C# AS 課程號,max(course.Cname)AS 課程名,isnull(AVG(score),0) AS 平均成績

,100 * SUM(CASE WHEN isnull(score,0)>=60 THEN 1 ELSE 0 END)/COUNT(*) AS 及格百分數

FROM SC T,Course

where t.C#=course.C#

GROUP BY t.C#

ORDER BY 100 * SUM(CASE WHEN isnull(score,0)>=60 THEN 1 ELSE 0 END)/COUNT(*) DESC

20、查詢如下課程平均成績和及格率的百分數(用"1行"顯示): 企業管理(001),馬克思(002),OO&UML (003),資料庫(004)

SELECT SUM(CASE WHEN C# ='001' THEN score ELSE 0 END)/SUM(CASE C# WHEN '001' THEN 1 ELSE 0 END) AS 企業管理平均分

,100 * SUM(CASE WHEN C# = '001' AND score >= 60 THEN 1 ELSE 0 END)/SUM(CASE WHEN C# = '001' THEN 1 ELSE 0 END) AS 企業管理及格百分數

,SUM(CASE WHEN C# = '002' THEN score ELSE 0 END)/SUM(CASE C# WHEN '002' THEN 1 ELSE 0 END) AS 馬克思平均分

,100 * SUM(CASE WHEN C# = '002' AND score >= 60 THEN 1 ELSE 0 END)/SUM(CASE WHEN C# = '002' THEN 1 ELSE 0 END) AS 馬克思及格百分數

,SUM(CASE WHEN C# = '003' THEN score ELSE 0 END)/SUM(CASE C# WHEN '003' THEN 1 ELSE 0 END) AS UML平均分

,100 * SUM(CASE WHEN C# = '003' AND score >= 60 THEN 1 ELSE 0 END)/SUM(CASE WHEN C# = '003' THEN 1 ELSE 0 END) AS UML及格百分數

,SUM(CASE WHEN C# = '004' THEN score ELSE 0 END)/SUM(CASE C# WHEN '004' THEN 1 ELSE 0 END) AS 資料庫平均分

,100 * SUM(CASE WHEN C# = '004' AND score >= 60 THEN 1 ELSE 0 END)/SUM(CASE WHEN C# = '004' THEN 1 ELSE 0 END) AS 資料庫及格百分數

FROM SC

;

❼ 怎麼用SQL的查詢語句列出某同學所有課程的課程名和成績啊,並按成績從低到高排序啊

1、打開Microsoft SQL Server 2012,選中需要查詢所有表的資料庫。

❽ SQL計算並顯示班上每位同學成績的總分和平均分,並按總分從高到低排序

----統計函數----
AVG
--求平均值
COUNT
--統計數目
MAX
--求最大值
MIN
--求最小值
SUM
--求和
order
by
stockid
desc(asc)
---------
排序,desc-降序,asc-升序