❶ sql怎麼把兩張表合並成一張
sql把兩張表合並成一張步驟如下：
1、我們首先將以A為基準用leftjoin以B為基準用right，都要就用fulljoin 。
❷ 如何用sql語句將三張表合並為一張表
select
a.id,
a.data1,
a.notes1,
b.data2,
b.note2,
c.data3,
c.notes3
into
x
from
a,b,c
where
a.id
=
b.id
and
a.id
=
c.id
這樣三張表的數據就都放在表x里了
注意是在表x不存在的情況下
存在的話這樣
insert
into
x
select
a.id,
a.data1,
a.notes1,
b.data2,
b.note2,
c.data3,
c.notes3
from
a,b,c
where
a.id
=
b.id
and
a.id
=
c.id
❸ SQL 含有不同欄位的多張表合並
select
*
from
t1,t2,t3這是講三張表全部顯示出來，、
如果要查詢某一欄位信息，就條件where=xx
❹ 怎樣用sql語句實現將兩個沒有關系的表拼接成一張表
1、創建測試表，
create table test_aaa( value varchar2(20));
create table test_bbb( value varchar2(20));
❺ sql如何將多個表合並成一個表
--復雜點的方法，
DECLARE @startTime DATETIME --開始的時間
DECLARE @endTime DATETIME --結束的時間
--比如我要得到1月到2月的數據
SET @startTime = '2014-01-01 00:00:00.000' --從新年第一天開始
SET @endTime = GETDATE() --一直到當前時間
--准備創建表
--根據月份創建
DECLARE @mi INT
--(這里必須要是開始時間和結束時間在一年之內的情況,如果不是在一年以內則要另外考慮,懶得寫)
SET @mi = MONTH(@endTime) - MONTH(@startTime) + 1 --用結束月份減去開始月份，得到總共要創建幾個月份表（加上當前月份）
--PRINT @mi
WHILE @mi >0
BEGIN
DECLARE @tableName VARCHAR(6) --月份表名
DECLARE @sql NVARCHAR(1000)
SET @tableName = '2014'
IF @mi<10
BEGIN
SET @tableName = @tableName + '0'
END
SET @tableName = @tableName + CAST(@mi AS VARCHAR)
IF NOT EXISTS (SELECT * FROM sysobjects WHERE [name] = @tableName AND [type] = 'U')
BEGIN
--如果當前月份表不存在,創建當前月份表
SET @sql = 'CREATE TABLE '+@tableName + ' (MId INT PRIMARY KEY IDENTITY(1,1))'
PRINT @sql
--執行
--EXECUTE sp_executesql N@sql
END
DECLARE @dayName VARCHAR(8) --天表名
WHILE CONVERT(VARCHAR(6),@endTime,112)=@tableName --確定當前時間是否是當前月的
BEGIN
SET @sql = ''
SET @dayName = CONVERT(VARCHAR(8),@endTime,112)
SET @sql = 'INSERT INTO '+@tableName +' VALUES SELECT * FROM ' + @dayName
PRINT @sql
--執行
--EXECUTE sp_executesql N@sql
SET @sql = ''
SET @endTime = DATEADD(DAY,-1,@endTime)
END
SET @mi = @mi - 1 --月份減一
/*
------------------------------------------------------------
CREATE TABLE 201402 (MId INT PRIMARY KEY IDENTITY(1,1))
INSERT INTO 201402 VALUES SELECT * FROM 20140219
INSERT INTO 201402 VALUES SELECT * FROM 20140218
INSERT INTO 201402 VALUES SELECT * FROM 20140217
INSERT INTO 201402 VALUES SELECT * FROM 20140216
INSERT INTO 201402 VALUES SELECT * FROM 20140215
INSERT INTO 201402 VALUES SELECT * FROM 20140214
INSERT INTO 201402 VALUES SELECT * FROM 20140213
INSERT INTO 201402 VALUES SELECT * FROM 20140212
INSERT INTO 201402 VALUES SELECT * FROM 20140211
INSERT INTO 201402 VALUES SELECT * FROM 20140210
INSERT INTO 201402 VALUES SELECT * FROM 20140209
INSERT INTO 201402 VALUES SELECT * FROM 20140208
INSERT INTO 201402 VALUES SELECT * FROM 20140207
INSERT INTO 201402 VALUES SELECT * FROM 20140206
INSERT INTO 201402 VALUES SELECT * FROM 20140205
INSERT INTO 201402 VALUES SELECT * FROM 20140204
INSERT INTO 201402 VALUES SELECT * FROM 20140203
INSERT INTO 201402 VALUES SELECT * FROM 20140202
INSERT INTO 201402 VALUES SELECT * FROM 20140201
CREATE TABLE 201401 (MId INT PRIMARY KEY IDENTITY(1,1))
INSERT INTO 201401 VALUES SELECT * FROM 20140131
INSERT INTO 201401 VALUES SELECT * FROM 20140130
INSERT INTO 201401 VALUES SELECT * FROM 20140129
INSERT INTO 201401 VALUES SELECT * FROM 20140128
INSERT INTO 201401 VALUES SELECT * FROM 20140127
INSERT INTO 201401 VALUES SELECT * FROM 20140126
INSERT INTO 201401 VALUES SELECT * FROM 20140125
INSERT INTO 201401 VALUES SELECT * FROM 20140124
INSERT INTO 201401 VALUES SELECT * FROM 20140123
INSERT INTO 201401 VALUES SELECT * FROM 20140122
INSERT INTO 201401 VALUES SELECT * FROM 20140121
INSERT INTO 201401 VALUES SELECT * FROM 20140120
INSERT INTO 201401 VALUES SELECT * FROM 20140119
INSERT INTO 201401 VALUES SELECT * FROM 20140118
INSERT INTO 201401 VALUES SELECT * FROM 20140117
INSERT INTO 201401 VALUES SELECT * FROM 20140116
INSERT INTO 201401 VALUES SELECT * FROM 20140115
INSERT INTO 201401 VALUES SELECT * FROM 20140114
INSERT INTO 201401 VALUES SELECT * FROM 20140113
INSERT INTO 201401 VALUES SELECT * FROM 20140112
INSERT INTO 201401 VALUES SELECT * FROM 20140111
INSERT INTO 201401 VALUES SELECT * FROM 20140110
INSERT INTO 201401 VALUES SELECT * FROM 20140109
INSERT INTO 201401 VALUES SELECT * FROM 20140108
INSERT INTO 201401 VALUES SELECT * FROM 20140107
INSERT INTO 201401 VALUES SELECT * FROM 20140106
INSERT INTO 201401 VALUES SELECT * FROM 20140105
INSERT INTO 201401 VALUES SELECT * FROM 20140104
INSERT INTO 201401 VALUES SELECT * FROM 20140103
INSERT INTO 201401 VALUES SELECT * FROM 20140102
INSERT INTO 201401 VALUES SELECT * FROM 20140101
*/
❻ SQL 表如何兩張表合並成一張 !!
UNION 操作符用於合並兩個或多個 SELECT 語句的結果集。
請注意，UNION 內部的 SELECT 語句必須擁有相同數量的列。列也必須擁有相似的數據類型。同時，每條 SELECT 語句中的列的順序必須相同。
SQL UNION 語法
SELECT column_name(s) FROM table_name1
UNION
SELECT column_name(s) FROM table_name2
注釋：默認地，UNION 操作符選取不同的值。如果允許重復的值，請使用 UNION ALL。
SQL UNION ALL 語法
SELECT column_name(s) FROM table_name1
UNION ALL
SELECT column_name(s) FROM table_name2
另外，UNION 結果集中的列名總是等於 UNION 中第一個 SELECT 語句中的列名。
❼ 怎麼把SQL多個表關聯合並成一個表
用union all+group by。多少ID都沒關系吧，除非你說的是有上千個表。。。
selectID,sum(qty1)qty1,sum(qty2)qty2,sum(qty3)qty3(
selectID,qty1,0qty2,0qty3from表1unionall
selectID,0qty1,qty2,0qty3from表2unionall
selectID,0qty1,0qty2,qty3from表3)ast1
groupbyID
❽ SQL 如何將 兩個table 的 欄位怎麼 合並到一張表
可以通過以下sql實現
sql：create table tablename1 as select t2.filename1, t3.filename2 from tablename2 t2,tablename3 t3 where t2.id =t3.id;
解釋：
從tablename2表中讀取出filename1欄位,從tablename3表中讀取出filename2欄位插入到新建的tablename1表中。
後面的where條件是通過id欄位，將查詢的兩張表關聯起來確定依賴關系。
❾ 如何用SQL語句實現將兩個不同結構的表合並到一個新表中
如何用SQL語句實現將兩個不同結構的表合並到一個新表中
select * from table1 union select * from table2
❿ SQL多張表如何合並成一張報表
select
a.*,b.*,c.*
from
table1
a,table2
b,table3
c
where
關聯性
select
a.*,b.*,c.*
from
table1
a
join
table2
b
on
....
join
table3
c
on.....
省略的地方
自行補齊
每個表之間的聯系