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oraclesql去掉重復

發布時間: 2022-07-12 00:53:17

❶ oracle資料庫中如何用sql語句查出重復欄位以及如何刪除

查詢可用group by語句,刪除則用delete語句。

1、創建測試表,插入測試數據:

createtabletest
(idint,
namevarchar2(20));
insertintotestvalues(1,'張三');
insertintotestvalues(1,'張三');
insertintotestvalues(2,'李四');
insertintotestvalues(2,'李四');
insertintotestvalues(3,'王五');
insertintotestvalues(3,'王五');
insertintotestvalues(3,'王五');
insertintotestvalues(4,'趙六');
commit;

2、查詢重復數據,用語句:

selectid,namefromtestgroupbyid,namehavingcount(*)>1;

結果:

deletefromtestwhererowidnotin(selectmin(rowid)fromtestgroupbyid,name);
commit;

❷ Oracle 查詢並刪除重復記錄的SQL語句,如下內容

1、查找表中多餘的重復記錄,重復記錄是根據單個欄位(peopleId)來判斷

select * from people

where peopleId in (select peopleId from people group by peopleId
having count(peopleId) > 1)

2、刪除表中多餘的重復記錄,重復記錄是根據單個欄位(peopleId)來判斷,只留有 rowid最小的記錄

delete from people

where peopleId in (select peopleId from people group by peopleId
having count(peopleId) > 1)

and rowid not in (select min(rowid) from people group by peopleId having
count(peopleId )>1)

注:rowid為oracle自帶不用該.....

3、查找表中多餘的重復記錄(多個欄位)

select * from vitae a

where (a.peopleId,a.seq) in (select peopleId,seq from vitae group by
peopleId,seq having count(*) > 1)

4、刪除表中多餘的重復記錄(多個欄位),只留有rowid最小的記錄

delete from vitae a

where (a.peopleId,a.seq) in (select peopleId,seq from vitae group by
peopleId,seq having count(*) > 1)

and rowid not in (select min(rowid) from vitae group by peopleId,seq having
count(*)>1)

5、查找表中多餘的重復記錄(多個欄位),不包含rowid最小的記錄

select * from vitae a

where (a.peopleId,a.seq) in (select peopleId,seq from vitae group by
peopleId,seq having count(*) > 1)

and rowid not in (select min(rowid) from vitae group by peopleId,seq having
count(*)>1)

❸ 在Oracle中如何用一條sql語句刪除重復的數據(留一條數據)

delete
Emp
p
where
rowid
in
(
select
tmpid
(select
ROW_NUMBER()
OVER(PARTITION
BY
id
)
id
,rowid
tmpid
from
emp
)
where
id
<>
1
)
可以試試

❹ oracle sql語句,如何去掉重復的,我的意思是 如有重復的就都不要

計算name列的數量,取數量為1的

❺ oracle sql 去重復記錄不用distinct如何實現

1、查找表中多餘的重復記錄,重復記錄是根據單個欄位(peopleId)來判斷

select*frompeople

wherepeopleIdin((peopleId)>1)

2、刪除表中多餘的重復記錄,重復記錄是根據單個欄位(peopleId)來判斷,只留有rowid最小的記錄

deletefrompeople

wherepeopleIdin((peopleId)>1)

androwidnotin(selectmin(rowid)(peopleId)>1)

❻ 去除重復問題oracle sql

用 distinct 屬性,在select之後加distinct
例:
select distinct *
from table;
select distinct name,age
from table
where 條件;

如果對您有幫助,請記得採納為滿意答案,謝謝!祝您生活愉快!

❼ Oracle刪除重復數據的SQL語句 有點疑問

這個只會刪除前兩條數據
也就是第一,二行的那兩條
你可以驗證一下
select
rowid,table_name.*
from
table_name;
執行完把幾個rowid記下
然後執行你的刪除語句,你看最後保留下來的是後兩行數據
rowid是記錄每條數據的物理位置,你說的把兩條1,2刪除,不知道你是怎麼理解的呢?

❽ oracle的查詢sql怎麼去重復數據

oracle的查詢sql怎麼去重復數據
select * from table t1

where not exists (select 1 from table t2 where t1.colA=t2.colA and t1.colB=t2.colB and t1.colC=t2.colC and t2.rowid>t1.rowid)
大概醬紫吧。好久沒用oracle了

❾ oracle刪除重復的行怎麼刪啊

可用rowid來刪除。

如表中有如下數據:

注意事項:delete語句執行後,需要commit提交,否則只在當前session下有效。