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加密的病號單c語言

發布時間: 2022-06-16 19:24:44

A. c語言文件加密和解密

c語言文件加密和解密方法如下:

1、首先打開VC++6.0;

voidDecryptFile(FILE*sfp,FILE*dfp,charpwd)
{
charch;
while((ch=fgetc(sfp))!=EOF)
{
if((ch>='a')&&(ch<='z'))
{
ch=ch^pwd;
ch=(ch-'a'+25)%26+'a';
}
if((ch>='A')&&(ch<='Z'))
{
ch=ch^pwd;
ch=(ch-'A'+25)%26+'A';
}
fputc(ch,dfp);
}
}

輸出函數,輸出文件內容
voidOutputFile(FILE*fp)
{
charch;
while((ch=fgetc(fp))!=EOF)
putchar(ch);
}
主函數,主要調用這幾個函數
intmain()
{
/*用戶輸入的要加密的文件名*/
charsfilename[20];
/*用戶輸入加密後保存的文件名*/
chardfilename[20];
/*用來保存密碼字元*/
charpwd;
FILE*sfp,*dfp;

printf(": ");
/*得到要加密的文件名*/
gets(sfilename);
/*得到加密後你要的文件名*/
printf(": ");
gets(dfilename);
/*得到加密字元*/
printf("PleaseinputyourPassword: ");
//scanf("%c",&pwd);
pwd=getch();
/*屏幕以*來表示輸入的加密字元*/
printf("* ");
/*以只讀方式打開要加密的文件*/
if((sfp=fopen(sfilename,"r"))==0)
{
printf("Can'topenthefile:%s ",sfilename);
exit(0);
}
/*輸出要加密的文件*/
printf(": ");
OutputFile(sfp);
/*建立加密後的文件*/
if((dfp=fopen(dfilename,"w+"))==0)
{
printf("Can'topenorcreatethefile:%s ",dfilename);
//exit(0);
}
/*文件加密*/
fseek(sfp,0L,SEEK_SET);
EncryptFile(sfp,dfp,pwd);
printf(" Encryptedthefilesuccessfully! ");
/*輸出加密後的文件*/
printf(": ");
fseek(dfp,0L,SEEK_SET);
OutputFile(dfp);
fclose(sfp);
fclose(dfp);
getch();
return0;
}


B. c語言文件加密

/************************************************************************/
/* 版權所有:信息工程學院 王明 使用時請註明出處!! */
/* 演算法:凱撒密碼體制 */
/************************************************************************/
#include <stdio.h>
#define N 5

void jiami(char namea[256])
{
FILE *fp_jiami,*fp_file2;
char c;
fp_jiami=fopen(namea,"rb");
fp_file2=fopen("file2.txt","wb");
while(EOF!=(fscanf(fp_jiami,"%c",&c)))
{
if((c>='A'&&c<='Z')||(c>='a'&&c<='z'))
{
c=c+N;
if (!((c>='A'&&c<='Z')||(c>='a'&&c<='z')))c=c-26;
if(c>='a'&&c<='z')c=c-32;
}
fprintf(fp_file2,"%c",c);
}
fclose(fp_file2);
fclose(fp_jiami);
}

void jiemi(char en_name[256])
{
FILE *fp_jiemi,*fp_file3;
char c;
fp_jiemi=fopen(en_name,"rb");
fp_file3=fopen("file3.txt","wb");
while(EOF!=(fscanf(fp_jiemi,"%c",&c)))
{
if((c>='A'&&c<='Z')||(c>='a'&&c<='z'))
{
c=c-N;
if (!((c>='A'&&c<='Z')||(c>='a'&&c<='z')))c=c+26;
if(c>='A'&&c<='Z')c=c+32;
}

fprintf(fp_file3,"%c",c);
}
fclose(fp_file3);
fclose(fp_jiemi);

}

int main()
{
char name[256];
int n;

printf("輸入你要操作的TXT文本:");
gets(name);

printf("\n請選擇需要進行的操作:\n");
printf(" 1:加密 2:解密 \n");
printf("輸入你的選擇:");

scanf("%d",&n);
switch(n) {
case 1:{jiami(name);printf("\t加密成功!!\n\n");
break;}
case 2:{jiemi(name);printf("\t解密成功!!\n\n");
break;}
default:{printf("輸入操作不存在!");}
}

return 0;

}

C. C語言設計一個簡單的加密解密程序

C語言設計一個簡單的加密解密程序如下:
加密程序代碼:
#include<stdio.h>
main()
{
char c,filename[20];
FILE *fp1,*fp2;
printf("請輸入待加密的文件名:\n");
scanf("%s",filename);
fp1=fopen(filename,"r");
fp2=fopen("miwen.txt","w");
do
{
c=fgetc(fp1);
if(c>=32&&c<=126)
{
c=c-32;
c=126-c;
}
if(c!=-1)
fprintf(fp2,"%c",c);
}
while(c!=-1);
}
解密程序代碼:
#include<stdio.h>
#include<string.h>
main()
{
char c,filename[20];
char yanzhengma[20];
FILE *fp1,*fp2;
printf("請輸入待解密文件名:\n");
scanf("%s",filename);
printf("請輸入驗證碼:\n");
scanf("%s",yanzhengma);
if(strcmp(yanzhengma,"shan")==0)
{
fp1=fopen(filename,"r");
fp2=fopen("yuanwen.txt","w");
do
{
c=fgetc(fp1);
if(c>=32&&c<=126)
{
c=126-c;
c=32+c;
}
if(c!=-1)
fprintf(fp2,"%c",c);
}
while(c!=-1);
}
else
{
printf("驗證碼錯誤!請重新輸入:\n");
scanf("%s",filename);
}
}

D. c語言編寫加密程序

#include <stdio.h>
#include <string.h>
#include "global.h"
#include "md5.h"

#define S11 7
#define S12 12
#define S13 17
#define S14 22
#define S21 5
#define S22 9
#define S23 14
#define S24 20
#define S31 4
#define S32 11
#define S33 16
#define S34 23
#define S41 6
#define S42 10
#define S43 15
#define S44 21

static void MD5Transform PROTO_LIST ((UINT4 [4], unsigned char
[64]));
static void Encode PROTO_LIST
((unsigned char *, UINT4 *, unsigned int));
static void Decode PROTO_LIST
((UINT4 *, unsigned char *, unsigned int));
static void MD5_memcpy PROTO_LIST ((POINTER, POINTER, unsigned
int));
static void MD5_memset PROTO_LIST ((POINTER, int, unsigned int));

static unsigned char PADDING[64] = {
0x80, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0,
0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0,
0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0
};

#define F(x, y, z) (((x) & (y)) | ((~x) & (z)))
#define G(x, y, z) (((x) & (z)) | ((y) & (~z)))
#define H(x, y, z) ((x) ^ (y) ^ (z))
#define I(x, y, z) ((y) ^ ((x) | (~z)))

#define ROTATE_LEFT(x, n) (((x) << (n)) | ((x) >> (32-(n))))

#define FF(a, b, c, d, x, s, ac) { (a) += F ((b), (c), (d)) + (x) + (UINT4)(ac); (a) = ROTATE_LEFT ((a), (s)); (a) += (b);}
#define GG(a, b, c, d, x, s, ac) { \
(a) += G ((b), (c), (d)) + (x) + (UINT4)(ac); \
(a) = ROTATE_LEFT ((a), (s)); \
(a) += (b); \
}
#define HH(a, b, c, d, x, s, ac) { \
(a) += H ((b), (c), (d)) + (x) + (UINT4)(ac); \
(a) = ROTATE_LEFT ((a), (s)); \
(a) += (b); \
}
#define II(a, b, c, d, x, s, ac) { \
(a) += I ((b), (c), (d)) + (x) + (UINT4)(ac); \
(a) = ROTATE_LEFT ((a), (s)); \
(a) += (b); \
}

void MD5Init (context)
MD5_CTX *context;
{
context->count[0] = context->count[1] = 0;
context->state[0] = 0x67452301;
context->state[1] = 0xefcdab89;
context->state[2] = 0x98badcfe;
context->state[3] = 0x10325476;
}

void MD5Update (context, input, inputLen)
MD5_CTX *context;
unsigned char *input;
unsigned int inputLen;
{
unsigned int i, index, partLen;
index = (unsigned int)((context->count[0] >> 3) & 0x3F);
if ((context->count[0] += ((UINT4)inputLen << 3))< ((UINT4)inputLen << 3))
context->count[1]++;
context->count[1] += ((UINT4)inputLen >> 29);
partLen = 64 - index;
if (inputLen >= partLen)
{
MD5_memcpy((POINTER)&context->buffer[index], (POINTER)input, partLen);
MD5Transform (context->state, context->buffer);
for (i = partLen; i + 63 < inputLen; i += 64)
MD5Transform (context->state, &input[i]);
index = 0;
}
else
i = 0;
MD5_memcpy((POINTER)&context->buffer[index], (POINTER)&input[i],inputLen-i);
}

void MD5Final (digest, context)
unsigned char digest[16];
MD5_CTX *context;
{
unsigned char bits[8];
unsigned int index, padLen;
Encode (bits, context->count, 8);
index = (unsigned int)((context->count[0] >> 3) & 0x3f);
padLen = (index < 56) ? (56 - index) : (120 - index);
MD5Update (context, PADDING, padLen);
MD5Update (context, bits, 8);
Encode (digest, context->state, 16);
MD5_memset ((POINTER)context, 0, sizeof (*context));
}

static void MD5Transform (UINT4 state[4], unsigned char block[64])
{
UINT4 a = state[0], b = state[1], c = state[2], d = state[3], x[16];
Decode (x, block, 64);
FF (a, b, c, d, x[ 0], S11, 0xd76aa478); /* 1 */
FF (d, a, b, c, x[ 1], S12, 0xe8c7b756); /* 2 */
FF (c, d, a, b, x[ 2], S13, 0x242070db); /* 3 */
FF (b, c, d, a, x[ 3], S14, 0xc1bdceee); /* 4 */
FF (a, b, c, d, x[ 4], S11, 0xf57c0faf); /* 5 */
FF (d, a, b, c, x[ 5], S12, 0x4787c62a); /* 6 */
FF (c, d, a, b, x[ 6], S13, 0xa8304613); /* 7 */
FF (b, c, d, a, x[ 7], S14, 0xfd469501); /* 8 */
FF (a, b, c, d, x[ 8], S11, 0x698098d8); /* 9 */
FF (d, a, b, c, x[ 9], S12, 0x8b44f7af); /* 10 */
FF (c, d, a, b, x[10], S13, 0xffff5bb1); /* 11 */
FF (b, c, d, a, x[11], S14, 0x895cd7be); /* 12 */
FF (a, b, c, d, x[12], S11, 0x6b901122); /* 13 */
FF (d, a, b, c, x[13], S12, 0xfd987193); /* 14 */
FF (c, d, a, b, x[14], S13, 0xa679438e); /* 15 */
FF (b, c, d, a, x[15], S14, 0x49b40821); /* 16 */

/* Round 2 */
GG (a, b, c, d, x[ 1], S21, 0xf61e2562); /* 17 */
GG (d, a, b, c, x[ 6], S22, 0xc040b340); /* 18 */
GG (c, d, a, b, x[11], S23, 0x265e5a51); /* 19 */
GG (b, c, d, a, x[ 0], S24, 0xe9b6c7aa); /* 20 */
GG (a, b, c, d, x[ 5], S21, 0xd62f105d); /* 21 */
GG (d, a, b, c, x[10], S22, 0x2441453); /* 22 */
GG (c, d, a, b, x[15], S23, 0xd8a1e681); /* 23 */
GG (b, c, d, a, x[ 4], S24, 0xe7d3fbc8); /* 24 */
GG (a, b, c, d, x[ 9], S21, 0x21e1cde6); /* 25 */
GG (d, a, b, c, x[14], S22, 0xc33707d6); /* 26 */
GG (c, d, a, b, x[ 3], S23, 0xf4d50d87); /* 27 */

GG (b, c, d, a, x[ 8], S24, 0x455a14ed); /* 28 */
GG (a, b, c, d, x[13], S21, 0xa9e3e905); /* 29 */
GG (d, a, b, c, x[ 2], S22, 0xfcefa3f8); /* 30 */
GG (c, d, a, b, x[ 7], S23, 0x676f02d9); /* 31 */
GG (b, c, d, a, x[12], S24, 0x8d2a4c8a); /* 32 */

/* Round 3 */
HH (a, b, c, d, x[ 5], S31, 0xfffa3942); /* 33 */
HH (d, a, b, c, x[ 8], S32, 0x8771f681); /* 34 */
HH (c, d, a, b, x[11], S33, 0x6d9d6122); /* 35 */
HH (b, c, d, a, x[14], S34, 0xfde5380c); /* 36 */
HH (a, b, c, d, x[ 1], S31, 0xa4beea44); /* 37 */
HH (d, a, b, c, x[ 4], S32, 0x4bdecfa9); /* 38 */
HH (c, d, a, b, x[ 7], S33, 0xf6bb4b60); /* 39 */
HH (b, c, d, a, x[10], S34, 0xbebfbc70); /* 40 */
HH (a, b, c, d, x[13], S31, 0x289b7ec6); /* 41 */
HH (d, a, b, c, x[ 0], S32, 0xeaa127fa); /* 42 */
HH (c, d, a, b, x[ 3], S33, 0xd4ef3085); /* 43 */
HH (b, c, d, a, x[ 6], S34, 0x4881d05); /* 44 */
HH (a, b, c, d, x[ 9], S31, 0xd9d4d039); /* 45 */
HH (d, a, b, c, x[12], S32, 0xe6db99e5); /* 46 */
HH (c, d, a, b, x[15], S33, 0x1fa27cf8); /* 47 */
HH (b, c, d, a, x[ 2], S34, 0xc4ac5665); /* 48 */

/* Round 4 */
II (a, b, c, d, x[ 0], S41, 0xf4292244); /* 49 */
II (d, a, b, c, x[ 7], S42, 0x432aff97); /* 50 */
II (c, d, a, b, x[14], S43, 0xab9423a7); /* 51 */
II (b, c, d, a, x[ 5], S44, 0xfc93a039); /* 52 */
II (a, b, c, d, x[12], S41, 0x655b59c3); /* 53 */
II (d, a, b, c, x[ 3], S42, 0x8f0ccc92); /* 54 */
II (c, d, a, b, x[10], S43, 0xffeff47d); /* 55 */
II (b, c, d, a, x[ 1], S44, 0x85845dd1); /* 56 */
II (a, b, c, d, x[ 8], S41, 0x6fa87e4f); /* 57 */
II (d, a, b, c, x[15], S42, 0xfe2ce6e0); /* 58 */
II (c, d, a, b, x[ 6], S43, 0xa3014314); /* 59 */
II (b, c, d, a, x[13], S44, 0x4e0811a1); /* 60 */
II (a, b, c, d, x[ 4], S41, 0xf7537e82); /* 61 */
II (d, a, b, c, x[11], S42, 0xbd3af235); /* 62 */
II (c, d, a, b, x[ 2], S43, 0x2ad7d2bb); /* 63 */
II (b, c, d, a, x[ 9], S44, 0xeb86d391); /* 64 */

state[0] += a;
state[1] += b;
state[2] += c;
state[3] += d;
MD5_memset ((POINTER)x, 0, sizeof (x));
}

static void Encode (output, input, len)
unsigned char *output;
UINT4 *input;
unsigned int len;
{
unsigned int i, j;
for (i = 0, j = 0; j < len; i++, j += 4)
{
output[j] = (unsigned char)(input[i] & 0xff);
output[j+1] = (unsigned char)((input[i] >> 8) & 0xff);
output[j+2] = (unsigned char)((input[i] >> 16) & 0xff);
output[j+3] = (unsigned char)((input[i] >> 24) & 0xff);
}
}

static void Decode (output, input, len)
UINT4 *output;
unsigned char *input;
unsigned int len;
{
unsigned int i, j;
for (i = 0, j = 0; j < len; i++, j += 4)
output[i] = ((UINT4)input[j]) | (((UINT4)input[j+1]) << 8) |(((UINT4)input[j+2]) << 16) | (((UINT4)input[j+3]) << 24);
}

static void MD5_memcpy (output, input, len)
POINTER output;
POINTER input;
unsigned int len;
{
unsigned int i;
for (i = 0; i < len; i++)
output[i] = input[i];
}

static void MD5_memset (output, value, len)
POINTER output;
int value;
unsigned int len;
{
unsigned int i;
for (i = 0; i < len; i++)
((char *)output)[i] = (char)value;
}
#ifndef MD
#define MD 5
#endif

#define TEST_BLOCK_LEN 1000
#define TEST_BLOCK_COUNT 1000

static void MDString PROTO_LIST ((char *));
static void MDPrint PROTO_LIST ((unsigned char [16]));

#define MD_CTX MD5_CTX
#define MDInit MD5Init
#define MDUpdate MD5Update
#define MDFinal MD5Final

int main (int argc, char *argv[])
{
int i;
if (argc > 1)
{ MDString(argv[1]);
return (0);
}
}

static void MDString (char *string)
{
MD_CTX context;
unsigned char digest[16];
unsigned int len = strlen (string);

MDInit (&context);
MDUpdate (&context, string, len);
MDFinal (digest, &context);

printf ("MD%d (\"%s\") = ", MD, string);
MDPrint (digest);
printf ("\n");
}

static void MDPrint (unsigned char digest[16])
{
unsigned int i;
for (i = 0; i < 16; i++)
printf ("%02x", digest[i]);

}

E. C語言簡單加密

#include "stdio.h"
#define N 80
void main()
{
char str[N];
int i;
printf("Please input string:\n");
gets(str);
for(i=0;str[i]!='\0';i++)
{
if((str[i]>=97)&&(str[i]<=112))
{
str[i]+=10;
}
else if((str[i]>112)&&(str[i]<=122))
{
str[i]-=16;
}
}
str[i]='\0';
printf("Result:\n");
puts(str);
getch();
}

F. C語言加密演算法(簡單)

MD5是HASH演算法,他不能用來解密的,他主要是用來校驗信息的完整型,也就是我們常說的數值簽名,你可以去RFC文檔上收索,上邊有他具體的演算法,代碼也是封裝好了的,可以去研究研究

G. 簡單的C語言加密程序

#include<stdio.h>
#include<stdlib.h>
main()
{
int key;
char ch;
printf("\n請輸入密鑰:");
scanf("%d",&key);

printf("得到對應明文如下:");
while((ch=getchar())!='\r')
(ch+key)>122?putchar(ch-122+33+key):
((ch+key)<33?putchar(ch+122+key):putchar(ch+key));
}

輸入輸出如下:

請輸入密鑰:20addse
得到對應明文如下:uxx.y

你先輸入一個任意的整數,如20,然後在鍵盤上輸入一段任意的字元如addse
按回車鍵結束,就會得到結果 如:uxx.y

下面是另一組輸入輸出:

請輸入密鑰:35asjRYIRER!@#$^^*&
得到對應明文如下:+=4u#luhuDcFG((MI-
具體是如何加密,你應該能看懂,就是用一個三目運算符 ? :控制。

H. c語言 數據加密

  1. 什麼是異或演算法

  2. 異或的特點是原始值經過兩次異或某一個數後會變成原來的值,所以有時利用這個特性來進行加密,加密端把數據與一個密鑰進行異或操作,生成密文。接收方收到密文後利用加密方提供的密鑰進行再次異或操作就能得到明文。

常式:

/*以DWORD為單位對文件進行加密,將每個DWORD與0xfcba0000(密鑰)做異或,寫入另一個文件*/

#include<stdio.h>
#include<stdlib.h>
#defineDWORDunsignedlong
#defineBYTEunsignedchar
#definefalse0
#definetrue1
intmain(intargc,char*argv[])
{
FILE*hSource;
FILE*hDestination;

DWORDdwKey=0xfcba0000;
char*pbBuffer;
DWORDdwBufferLen=sizeof(DWORD);
DWORDdwCount;
DWORDdwData;
if(argv[1]==0||argv[2]==0)
{
printf("missingargument! ");
returnfalse;
}
char*szSource=argv[1];
char*szDestination=argv[2];

hSource=fopen(szSource,"rb");//打開源文件.
hDestination=fopen(szDestination,"wb");//打開目標文件
if(hSource==NULL){printf("openSourceFileerror!");returnfalse;}
if(hDestination==NULL){printf("openDestinationFileerror!");returnfalse;}

//分配緩沖區
pbBuffer=(char*)malloc(dwBufferLen);

do{
//從源文件中讀出dwBlockLen個位元組
dwCount=fread(pbBuffer,1,dwBufferLen,hSource);
//加密數據
dwData=*(DWORD*)pbBuffer;//char*TOdword
dwData^=dwKey;//xoroperation
pbBuffer=(char*)&dwData;
//將加密過的數據寫入目標文件
fwrite(pbBuffer,1,dwCount,hDestination);
}while(!feof(hSource));

//關閉文件、釋放內存
fclose(hSource);
fclose(hDestination);

printf("%sisencryptedto%s ",szSource,szDestination);
return0;
}

I. c語言加密演算法

看你催就倉促寫了個,自我感覺寫的不是很好,但是能用了。數據只能是大寫字母組成的字元串。
加密的時候,輸入Y,然後輸入要加密的文本(大寫字母)
解密的時候,輸入N,然後輸入一個整數n表示密文的個數,然後n個整數表示加密時候得到的密文。
/*RSA algorithm */
#include <stdio.h>
#include <string.h>
#include <stdlib.h>
#define MM 7081
#define KK 1789
#define PHIM 6912
#define PP 85
typedef char strtype[10000];
int len;
long nume[10000];
int change[126];
char antichange[37];

void initialize()
{ int i;
char c;
for (i = 11, c = 'A'; c <= 'Z'; c ++, i ++)
{ change[c] = i;
antichange[i] = c;
}
}
void changetonum(strtype str)
{ int l = strlen(str), i;
len = 0;
memset(nume, 0, sizeof(nume));
for (i = 0; i < l; i ++)
{ nume[len] = nume[len] * 100 + change[str[i]];
if (i % 2 == 1) len ++;
}
if (i % 2 != 0) len ++;
}
long binamod(long numb, long k)
{ if (k == 0) return 1;
long curr = binamod (numb, k / 2);
if (k % 2 == 0)
return curr * curr % MM;
else return (curr * curr) % MM * numb % MM;
}
long encode(long numb)
{ return binamod(numb, KK);
}
long decode(long numb)
{ return binamod(numb, PP);
}
main()
{ strtype str;
int i, a1, a2;
long curr;
initialize();
puts("Input 'Y' if encoding, otherwise input 'N':");
gets(str);
if (str[0] == 'Y')
{ gets(str);
changetonum(str);
printf("encoded: ");
for (i = 0; i < len; i ++)
{ if (i) putchar('-');
printf(" %ld ", encode(nume[i]));
}
putchar('\n');
}
else
{ scanf("%d", &len);
for (i = 0; i < len; i ++)
{ scanf("%ld", &curr);
curr = decode(curr);
a1 = curr / 100;
a2 = curr % 100;
printf("decoded: ");
if (a1 != 0) putchar(antichange[a1]);
if (a2 != 0) putchar(antichange[a2]);
}
putchar('\n');
}
putchar('\n');
system("PAUSE");
return 0;
}
測試:
輸入:
Y
FERMAT
輸出:
encoded: 5192 - 2604 - 4222
輸入
N
3 5192 2604 4222
輸出
decoded: FERMAT