❶ sql怎么把两张表合并成一张
sql把两张表合并成一张步骤如下:
1、我们首先将以A为基准用leftjoin以B为基准用right,都要就用fulljoin 。
❷ 如何用sql语句将三张表合并为一张表
select
a.id,
a.data1,
a.notes1,
b.data2,
b.note2,
c.data3,
c.notes3
into
x
from
a,b,c
where
a.id
=
b.id
and
a.id
=
c.id
这样三张表的数据就都放在表x里了
注意是在表x不存在的情况下
存在的话这样
insert
into
x
select
a.id,
a.data1,
a.notes1,
b.data2,
b.note2,
c.data3,
c.notes3
from
a,b,c
where
a.id
=
b.id
and
a.id
=
c.id
❸ SQL 含有不同字段的多张表合并
select
*
from
t1,t2,t3这是讲三张表全部显示出来,、
如果要查询某一字段信息,就条件where=xx
❹ 怎样用sql语句实现将两个没有关系的表拼接成一张表
1、创建测试表,
create table test_aaa( value varchar2(20));
create table test_bbb( value varchar2(20));
❺ sql如何将多个表合并成一个表
--复杂点的方法,
DECLARE @startTime DATETIME --开始的时间
DECLARE @endTime DATETIME --结束的时间
--比如我要得到1月到2月的数据
SET @startTime = '2014-01-01 00:00:00.000' --从新年第一天开始
SET @endTime = GETDATE() --一直到当前时间
--准备创建表
--根据月份创建
DECLARE @mi INT
--(这里必须要是开始时间和结束时间在一年之内的情况,如果不是在一年以内则要另外考虑,懒得写)
SET @mi = MONTH(@endTime) - MONTH(@startTime) + 1 --用结束月份减去开始月份,得到总共要创建几个月份表(加上当前月份)
--PRINT @mi
WHILE @mi >0
BEGIN
DECLARE @tableName VARCHAR(6) --月份表名
DECLARE @sql NVARCHAR(1000)
SET @tableName = '2014'
IF @mi<10
BEGIN
SET @tableName = @tableName + '0'
END
SET @tableName = @tableName + CAST(@mi AS VARCHAR)
IF NOT EXISTS (SELECT * FROM sysobjects WHERE [name] = @tableName AND [type] = 'U')
BEGIN
--如果当前月份表不存在,创建当前月份表
SET @sql = 'CREATE TABLE '+@tableName + ' (MId INT PRIMARY KEY IDENTITY(1,1))'
PRINT @sql
--执行
--EXECUTE sp_executesql N@sql
END
DECLARE @dayName VARCHAR(8) --天表名
WHILE CONVERT(VARCHAR(6),@endTime,112)=@tableName --确定当前时间是否是当前月的
BEGIN
SET @sql = ''
SET @dayName = CONVERT(VARCHAR(8),@endTime,112)
SET @sql = 'INSERT INTO '+@tableName +' VALUES SELECT * FROM ' + @dayName
PRINT @sql
--执行
--EXECUTE sp_executesql N@sql
SET @sql = ''
SET @endTime = DATEADD(DAY,-1,@endTime)
END
SET @mi = @mi - 1 --月份减一
/*
------------------------------------------------------------
CREATE TABLE 201402 (MId INT PRIMARY KEY IDENTITY(1,1))
INSERT INTO 201402 VALUES SELECT * FROM 20140219
INSERT INTO 201402 VALUES SELECT * FROM 20140218
INSERT INTO 201402 VALUES SELECT * FROM 20140217
INSERT INTO 201402 VALUES SELECT * FROM 20140216
INSERT INTO 201402 VALUES SELECT * FROM 20140215
INSERT INTO 201402 VALUES SELECT * FROM 20140214
INSERT INTO 201402 VALUES SELECT * FROM 20140213
INSERT INTO 201402 VALUES SELECT * FROM 20140212
INSERT INTO 201402 VALUES SELECT * FROM 20140211
INSERT INTO 201402 VALUES SELECT * FROM 20140210
INSERT INTO 201402 VALUES SELECT * FROM 20140209
INSERT INTO 201402 VALUES SELECT * FROM 20140208
INSERT INTO 201402 VALUES SELECT * FROM 20140207
INSERT INTO 201402 VALUES SELECT * FROM 20140206
INSERT INTO 201402 VALUES SELECT * FROM 20140205
INSERT INTO 201402 VALUES SELECT * FROM 20140204
INSERT INTO 201402 VALUES SELECT * FROM 20140203
INSERT INTO 201402 VALUES SELECT * FROM 20140202
INSERT INTO 201402 VALUES SELECT * FROM 20140201
CREATE TABLE 201401 (MId INT PRIMARY KEY IDENTITY(1,1))
INSERT INTO 201401 VALUES SELECT * FROM 20140131
INSERT INTO 201401 VALUES SELECT * FROM 20140130
INSERT INTO 201401 VALUES SELECT * FROM 20140129
INSERT INTO 201401 VALUES SELECT * FROM 20140128
INSERT INTO 201401 VALUES SELECT * FROM 20140127
INSERT INTO 201401 VALUES SELECT * FROM 20140126
INSERT INTO 201401 VALUES SELECT * FROM 20140125
INSERT INTO 201401 VALUES SELECT * FROM 20140124
INSERT INTO 201401 VALUES SELECT * FROM 20140123
INSERT INTO 201401 VALUES SELECT * FROM 20140122
INSERT INTO 201401 VALUES SELECT * FROM 20140121
INSERT INTO 201401 VALUES SELECT * FROM 20140120
INSERT INTO 201401 VALUES SELECT * FROM 20140119
INSERT INTO 201401 VALUES SELECT * FROM 20140118
INSERT INTO 201401 VALUES SELECT * FROM 20140117
INSERT INTO 201401 VALUES SELECT * FROM 20140116
INSERT INTO 201401 VALUES SELECT * FROM 20140115
INSERT INTO 201401 VALUES SELECT * FROM 20140114
INSERT INTO 201401 VALUES SELECT * FROM 20140113
INSERT INTO 201401 VALUES SELECT * FROM 20140112
INSERT INTO 201401 VALUES SELECT * FROM 20140111
INSERT INTO 201401 VALUES SELECT * FROM 20140110
INSERT INTO 201401 VALUES SELECT * FROM 20140109
INSERT INTO 201401 VALUES SELECT * FROM 20140108
INSERT INTO 201401 VALUES SELECT * FROM 20140107
INSERT INTO 201401 VALUES SELECT * FROM 20140106
INSERT INTO 201401 VALUES SELECT * FROM 20140105
INSERT INTO 201401 VALUES SELECT * FROM 20140104
INSERT INTO 201401 VALUES SELECT * FROM 20140103
INSERT INTO 201401 VALUES SELECT * FROM 20140102
INSERT INTO 201401 VALUES SELECT * FROM 20140101
*/
❻ SQL 表如何两张表合并成一张 !!
UNION 操作符用于合并两个或多个 SELECT 语句的结果集。
请注意,UNION 内部的 SELECT 语句必须拥有相同数量的列。列也必须拥有相似的数据类型。同时,每条 SELECT 语句中的列的顺序必须相同。
SQL UNION 语法
SELECT column_name(s) FROM table_name1
UNION
SELECT column_name(s) FROM table_name2
注释:默认地,UNION 操作符选取不同的值。如果允许重复的值,请使用 UNION ALL。
SQL UNION ALL 语法
SELECT column_name(s) FROM table_name1
UNION ALL
SELECT column_name(s) FROM table_name2
另外,UNION 结果集中的列名总是等于 UNION 中第一个 SELECT 语句中的列名。
❼ 怎么把SQL多个表关联合并成一个表
用union all+group by。多少ID都没关系吧,除非你说的是有上千个表。。。
selectID,sum(qty1)qty1,sum(qty2)qty2,sum(qty3)qty3(
selectID,qty1,0qty2,0qty3from表1unionall
selectID,0qty1,qty2,0qty3from表2unionall
selectID,0qty1,0qty2,qty3from表3)ast1
groupbyID
❽ SQL 如何将 两个table 的 字段怎么 合并到一张表
可以通过以下sql实现
sql:create table tablename1 as select t2.filename1, t3.filename2 from tablename2 t2,tablename3 t3 where t2.id =t3.id;
解释:
从tablename2表中读取出filename1字段,从tablename3表中读取出filename2字段插入到新建的tablename1表中。
后面的where条件是通过id字段,将查询的两张表关联起来确定依赖关系。
❾ 如何用SQL语句实现将两个不同结构的表合并到一个新表中
如何用SQL语句实现将两个不同结构的表合并到一个新表中
select * from table1 union select * from table2
❿ SQL多张表如何合并成一张报表
select
a.*,b.*,c.*
from
table1
a,table2
b,table3
c
where
关联性
select
a.*,b.*,c.*
from
table1
a
join
table2
b
on
....
join
table3
c
on.....
省略的地方
自行补齐
每个表之间的联系