㈠ c语言编写菜单程序
#include<stdio.h>
#include<graphics.h>
#include<conio.h>
void main()
{
char str;
int i,k,choice=1;
int gd=DETECT,gm;
initgraph(&gd,&gm," ");
setbkcolor(2);
settextstyle(3,0,3);
outtextxy(140,120,"A. The Mock Clock.");
outtextxy(140,150,"B. The Digital Clock.");
outtextxy(140,180,"C. Exit.");
setlinestyle(0,0,3);
rectangle(170,115,370,145);
/*按上下键选择所需选项*/
for(i=1;i<=100;i++)
{
str=getch();
if(str==72)
{
--choice;
if(choice==0)choice=3;
}
if(str==80)
{
++choice;
if(choice==4)choice=1;
}
if(str==13)break; /*按回车键确认*/
/*画图做菜单*/
cleardevice();
switch(choice)
{ case 1: setlinestyle(0,0,3);
rectangle(170,115,400,145);
settextstyle(3,0,3);
outtextxy(140,120,"A. The Mock Clock.");
settextstyle(3,0,3);
outtextxy(140,150,"B. The Digital Clock.");
outtextxy(140,180,"C. Exit.");
break;
case 2: setlinestyle(0,0,3);
rectangle(170,145,400,175);
settextstyle(3,0,3);
outtextxy(140,120,"A. The Mock Clock.");
settextstyle(3,0,3);
outtextxy(140,150,"B. The Digital Clock.");
settextstyle(3,0,3);
outtextxy(140,180,"C. Exit.");
break;
case 3: settextstyle(3,0,3);
outtextxy(140,120,"A. The Mock Clock.");
outtextxy(140,150,"B. The Digital Clock.");
settextstyle(3,0,3);
outtextxy(140,180,"C. Exit.");
setlinestyle(0,0,3);
rectangle(170,175,400,205);
break;
}
}
if(i>=100)exit(0);/*如果按键超过100次退出*/
switch(choice)/*这里引用函数,实现所要的功能*/
{
case 1: cleardevice();
setbkcolor(4);
settextstyle(3,0,4);
outtextxy(160,120,"No.1 have not built."); break;
case 2: cleardevice();
setbkcolor(4);
settextstyle(3,0,4);
outtextxy(160,150,"No.2 have not built.");
break;
case 3: exit(0);
}
getch();
closegraph();
}
㈡ 用c语言写一个简单的菜单程序,一个主函数至少四个子函数急求!!就像这样的。
分析:问题库(QAS)用外部的配置文件保存,每次运行前先载入库中已经建立的问题。然后再进入操作选择。完整代码如下:/*1.暂时不考虑汉字;2.可以用链表优化;3.将每一种操作封装成一个函数;*/#include#include#include#include////////////////////////////////////////////////////////////////////////////字符串最大长度#defineMAX_STR_LEN2048//题库上限#defineMAX_QAS_LEN1024//配置文件路径#defineQAS_FILE_PATH"d:\\qasconfig.txt"////////////////////////////////////////////////////////////////////////////问题结点typedefstructtagQASNode{charQuestion[MAX_STR_LEN];charAnswer[MAX_STR_LEN];doubleScore;boolIsAnswered;}QASNode;//问题库QASNode*g_QASLib[MAX_QAS_LEN];intg_QASIndex=0;////////////////////////////////////////////////////////////////////////////添加boolInsertToLib(char*pQuestion,char*pAnswer,doublescore){if(pQuestion==NULL||strcmp(pQuestion,"")==0||pAnswer==NULL)returnfalse;QASNode*pNewNode=(QASNode*)malloc(sizeof(QASNode));memset(pNewNode,0L,sizeof(QASNode));strcpy_s(pNewNode->Question,pQuestion);strcpy_s(pNewNode->Answer,pAnswer);pNewNode->Score=score;g_QASLib[g_QASIndex++]=pNewNode;returntrue;}//随机一个不重复的序号intGetQuestionIndex(){intretVal=-1;inttryCnt=0;while(tryCnt++IsAnswered){retVal=randVal;break;}}returnretVal;}//////////////////////////////////////////////////////////////////////////intmain(){//打开配置文件FILE*pStream=NULL;if(fopen_s(&pStream,QAS_FILE_PATH,"a+")!=0){printf_s("Opentheconfigfilefailed.\n");return-1;}//加载已有的QASfseek(pStream,0L,SEEK_END);intfileSize=ftell(pStream);fseek(pStream,0L,SEEK_SET);while(!feof(pStream)&&fileSize){if(g_QASIndexQuestion);printf_s("Inputanswer:");chartempA[MAX_STR_LEN]={0};fflush(stdin);gets_s(tempA,MAX_STR_LEN);if(strcmp(tempA,g_QASLib[currentIndex]->Answer)==0){printf("Right!\n");totalSocore+=g_QASLib[currentIndex]->Score;g_QASLib[currentIndex]->IsAnswered=true;}else{printf("Wrong!\n");}}else{printf("你已经答对了所有的问题!\n");}}break;case2:{if(currentIndex!=-1){printf("Quest:%s\nScore=%.2f\n",g_QASLib[currentIndex]->Question,g_QASLib[currentIndex]->Score);}else{printf("请先选择\"回答问题\"!\n");}}break;case3:{//一次只添加一个问题if(g_QASIndexQuestion,g_QASLib[i]->Answer,g_QASLib[i]->Score);}}break;default:break;}}printf("\n");return0;}运行起来后先建立问题库!
㈢ C语言中怎么编制简单的菜单,通过菜单选择能实现程序的各项功能
#include <iostream>
#include <stdlib.h>
#include <conio.h>
#include <ctype.h>
using namespace std;
void xuanzepaixu() //选择排序函数
{
printf("待添加,请按任意键继续...");
getchar();
}
void erfenpaixu() //二分查找函数
{
printf("待添加,请按任意键继续...");
getchar();
}
void menu() //主菜单
{
system("cls"); //清屏
printf("\n\t\t\t 菜单\n");
printf("\t\t\t#***********************#\n");
printf("\t\t\t# 1选择排序 #\n");
printf("\t\t\t# 2二分查找 #\n");
printf("\t\t\t# 3返回 #\n");
printf("\t\t\t# 4---关闭 #\n");
printf("\t\t\t#***********************#\n");
printf("\t\t\t 请选择(1-4) =:");
}
void main()
{
char select;
while(1)
{
menu();
system("COLOR 9f");
scanf("%c",&select);
if(select=='3')
break; //返回上级菜单
else
{
getchar(); //读入回车符
if(!isdigit(select)) //如果不是数字字符
{
printf("\n\7Your select may be wrong, must enter the digit!\n");_getch();
}
else
{
switch (select)
{
case '1': xuanzepaixu();break;
case '2': erfenpaixu();break;
case '4':exit(0); //直接退出
default:
{
printf("\n\7\7Your selected digit may be wrong, select again!\n");
_getch();
break;
}
}
}
}
}
}
㈣ C语言编写菜单
#include<stdio.h>
#include<string.h>
#include<stdlib.h>
//值传递
voidfun1(chara)
{
a='b';
}
//地址传递
charfun2(char*a)
{
*a='a';
return*a;
}
//动态分配数组
voidfun3(char*&a)
{
a=(char*)malloc(sizeof(char));
}
charcaidan()
{
charchoose[5];
printf(" *************************************** ");
printf("┌──────┐ ");
printf("│菜单│ ");
printf("__________________________________ ");
printf("│1,按值传递| ");
printf("│2,按地址传递| ");
printf("│3,动态数组演示| ");
printf("│4,退出| ");
printf("└────────────────┙ ");
printf("************************************** ");
do
{
printf("请输入您的选择(1-4):");
scanf("%s",choose);
}while(strcmp(choose,"1")&&strcmp(choose,"2")&&strcmp(choose,"3")&&strcmp(choose,"4"));
//返回选择的菜单,注意如果输入太长这里会异常,因为choose[5],只申请了5个字节。
returnchoose[0];
}
voidmain()
{
//执行菜单的选择
while(1)
{
switch(caidan())
{
case'1':
{
chara='a';
fun1(a);
//按值传递内容不变
break;
}
case'2':
{
charb='b';
chara=fun2(&b);
//按地址传递内容会变
break;
}
case'3':
{
char*p=NULL;
fun3(p);
//动态数组分配成功
break;
}
case'4':exit(0);
}
}
}
㈤ C语言菜单程序编写
#include
<stdio.h>
#include
<math.h>
void
armstrong(int
a)
{
int
i;
int
n
=
1;
int
b
=
a;
int
s
=
0;
while(b
/=
10)
n++;
b
=
a;
for(i
=
0;
i
<
n;
i
++){
s
+=
(int)pow(b%10,
n);
b
/=
10;
}
if(s
==
a){
printf("%d
是水仙花数!\n",
a);
}else{
printf("%d
不是水仙花数!\n",
a);
}
}
void
prime(int
a)
{
int
i;
if(a
<
2)
{
printf("%d
不是素数!\n",
a);
return
;
}
for(i
=
2;
i
<
a;
i
++){
if(a
%
i
==
0)
{
printf("%d
不是素数!\n",
a);
return
;
}
}
printf("%d
是素数!\n",
a);
}
void
max(int
a,
int
b,
int
c)
{
if(b
>
a)
a
=
b;
if(c
>
a)
a
=
c;
printf("最大值是:%d\n",
a);
}
void
factorial(int
a)
{
int
i;
int
f
=
1;
for(i
=
a;
i
>1;
i
--)
f
*=
i;
printf("%d
的阶乘是:%d\n",
a,
f);
}
int
main(int
argc,
char
**argv)
{
int
a,
b,
c;
int
type
;
int
run
=
1;
printf("本程序可完成某些数学计算:\n");
printf(
"***********************************\n"
"*
1.判断一个数是否为水仙花数。
*\n"
"*
2.判断一个数是否为素数。
*\n"
"*
3.求三个数的最大值。
*\n"
"*
4.求一个数的阶乘。
*\n"
"*
0.退出。
*\n"
"***********************************\n");
do{
printf("请按菜单进行选择(0-4):");
scanf("%d",
&type);
switch(type){
case
0:
while(1){
getchar();
printf("你确定退出吗?(y/n)");
a
=
getchar();
switch(a){
case
'y':
run
=
0;
break;
case
'n':
run
=
1;
break;
default:
break;
}
if((a
==
'y')
||
(a
==
'n'))
break;
}
break;
case
1:
printf("请输入一个数:");
scanf("%d",
&a);
armstrong(a);
break;
case
2:
printf("请输入一个数:");
scanf("%d",
&a);
prime(a);
break;
case
3:
printf("请输入三个数:");
scanf("%d%d%d",
&a,
&b,
&c);
max(a,
b,
c);
break;
case
4:
printf("请输入一个数:
");
scanf("%d",
&a);
factorial(a);
break;
default:
break;
}
}while(run);
return
0;
}
㈥ C语言菜单选项程序
改一下试试:
int main(){
void (void);
void han(void);
void shu(void);
void fen(int x);
void xun(int x);
char chose,s[20];
int n;
for(;;){
printf("1:分支程序
2:循环程序
3:函数程序
4:数组程序
5:指针程序
0:退出
选择数字:");
scanf("%s",s); chose=s[0];
switch(chose){
case'1':printf("这是个销售量与其相应等级的分支程序,请输入相应销售量!
");
scanf("%d",&n);
fen(n);
break;
case'2':printf("这是个求0——n累加之和的循环结构,输入n,下面为其值!
");
scanf("%d",&n);
xun(n);
break;
case'3':printf("这是一个求最大公约数的函数程序,请输入两个数的值!
");
han();
break;
case'4':printf("这是一个数组逆行排序的数组程序,请输入10个整数!
");
shu();
break;
case'5':printf("这是一个用指针求一个三个数的数组和的指针程序,请输入这三个数!
");
();
break;
case'0':exit(1);
default:break;
}
}
return 0;
}
㈦ 求一个C语言菜单函数的程序
1、对于窗口组件菜单,需要根据不同平台,通过图形编程接口,进行菜单的编制。
例程:
#include<stdio.h>
#include<graphics.h>
#include<conio.h>
voidmain()
{
charstr;
inti,k,choice=1;
intgd=DETECT,gm;
initgraph(&gd,&gm,"");
setbkcolor(2);
settextstyle(3,0,3);
outtextxy(140,120,"A.TheMockClock.");
outtextxy(140,150,"B.TheDigitalClock.");
outtextxy(140,180,"C.Exit.");
setlinestyle(0,0,3);
rectangle(170,115,370,145);
/*按上下键选择所需选项*/
for(i=1;i<=100;i++)
{
str=getch();
if(str==72)
{
--choice;
if(choice==0)choice=3;
}
if(str==80)
{
++choice;
if(choice==4)choice=1;
}
if(str==13)break;/*按回车键确认*/
/*画图做菜单*/
cleardevice();
switch(choice)
{case1:setlinestyle(0,0,3);
rectangle(170,115,400,145);
settextstyle(3,0,3);
outtextxy(140,120,"A.TheMockClock.");
settextstyle(3,0,3);
outtextxy(140,150,"B.TheDigitalClock.");
outtextxy(140,180,"C.Exit.");
break;
case2:setlinestyle(0,0,3);
rectangle(170,145,400,175);
settextstyle(3,0,3);
outtextxy(140,120,"A.TheMockClock.");
settextstyle(3,0,3);
outtextxy(140,150,"B.TheDigitalClock.");
settextstyle(3,0,3);
outtextxy(140,180,"C.Exit.");
break;
case3:settextstyle(3,0,3);
outtextxy(140,120,"A.TheMockClock.");
outtextxy(140,150,"B.TheDigitalClock.");
settextstyle(3,0,3);
outtextxy(140,180,"C.Exit.");
setlinestyle(0,0,3);
rectangle(170,175,400,205);
break;
}
}
if(i>=100)exit(0);/*如果按键超过100次退出*/
switch(choice)/*这里引用函数,实现所要的功能*/
{
case1:cleardevice();
setbkcolor(4);
settextstyle(3,0,4);
outtextxy(160,120,"No.1havenotbuilt.");break;
case2:cleardevice();
setbkcolor(4);
settextstyle(3,0,4);
outtextxy(160,150,"No.2havenotbuilt.");
break;
case3:exit(0);
}
getch();
closegraph();
}
2、对于命令行菜单,直接通过不断刷新输出来模拟菜单行为。
例程:
#include<stdio.h>
#include<stdlib.h>
#include<string.h>
intn,t,k;
intm;
chars1[20],s2[20],c;
char**l;
char*num[]={"one","two","three","four","five","six","seven","eight","nine","ten"};
voidmenu()
{
printf(" ******************************************************* ");
printf(" **1.查找字符串S1中S2出现的次数** ");
printf(" **2.统计字符串中大小写字母,数字出现的次数** ");
printf(" **3.将数字翻译成英语** ");
printf(" **4.结束** ");
printf(" ******************************************************* ");
printf(" 您的输入:");
fflush(stdin);
scanf("%d",&n);
}
voidcheck()
{
chara[20],b[20];
intj=0,k,m,l=0;
intt=0,n=0;
printf("请输入主字符串: ");
scanf("%s",a);
k=strlen(a);
printf("请输入子字符串: ");
scanf("%s",b);
m=strlen(b);
for(n=0;n<k;n++)
if(a[n]==b[0])
{
j++;/*记录相同的字符数*/
do
{
if(a[++n]==b[++t])
{
j++;
if(j==m)
{
l++;/*子字符串相同数*/
j=0;/*判断后相同字符数归零*/
t=-1;/*判断中if中++t;t将会归零*/
}
}
else
{
j=0;
t=0;
break;/*如果不同跳出while循环让for使n+1继续判断*/
}
}while(a[n]!='