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c语言周一到周五

发布时间: 2022-07-16 06:01:18

⑴ 编写程序,输入周一至周五中的任意一天,屏幕显示一条不同的短语,短语内容自拟。c语言

#include <stdio.h>

int main()
{
int day=0;
printf("输入星期几(要求输入1—7中的一个整数,例如星期六,输入 6)\n");
scanf("%d",&day);
switch(day)
{
case 1:printf("星期一快乐!");break;
case 2:printf("星期二快乐!");break;
case 3:printf("星期三快乐!");break;
case 4:printf("星期四快乐!");break;
case 5:printf("星期五快乐!");break;
case 6:printf("星期六快乐!");break;
case 7:printf("星期日快乐!");break;
default:printf("跟你说了要输入1—7中的一个整数");break;

}

printf("\n");

return 0;
}

⑵ 用c语言编程,各位大虾帮帮忙

#include<stdio.h>
void main()
{
int hour,week;
int money;
float tax;
printf("请输入星期与工作时间:");
scanf("%d%d",&hour,&week);
switch(week)
{
case 1:
money=20*hour;
break;
case 2:
money=20*hour;
break;
case 3:
money=20*hour;
break;
case 4:
money=20*hour;
break;
case 5:
money=20*hour;
break;
case 6:
money=20*hour*3;
break;
case 7:
money=20*hour*3;
break;
}
tax=(float)0.08*money;
printf("该日的税前工资为:%d\n",money);
printf("税金为:%.2f\n",tax);
}

⑶ c语言编写一个程序计算长途电话费。电话费根据以下费率计算: 1)周一到周五,上午八点到下午六点之间

#include <stdio.h>
int main()
{
char str[2];
int b,c,d,flag=0;
double e=0;
scanf("%s %d %d %d",&str,&b,&c,&d);

if((str[0]=='m' ||str[0]=='M') &&(str[1]=='O' ||str[1]=='o'))
flag=1;
if((str[0]=='t' ||str[0]=='T') &&(str[1]=='u' ||str[1]=='U'))
flag=1;
if((str[0]=='w' ||str[0]=='W') &&(str[1]=='e' ||str[1]=='E'))
flag=1;
if((str[0]=='T' ||str[0]=='t') &&(str[1]=='H' ||str[1]=='h'))
flag=1;
if((str[0]=='f' ||str[0]=='F') &&(str[1]=='r' ||str[1]=='R'))
flag=1;
if((str[0]=='S' ||str[0]=='s') &&(str[1]=='A' ||str[1]=='a'))
flag=2;
if((str[0]=='s' ||str[0]=='S') &&(str[1]=='u' ||str[1]=='U'))
flag=2;

while(str!="\0")
{
if(flag==2)
e=d*0.15;
if(flag==1 && (60*b+c>=0 && 60*b+c<=480 && 60*b+c+d<=480 ))
e=d*0.25;
if(flag==1 && (60*b+c>=1080 && 60*b+c<=1440 && 60*b+c+d<=1440 ))
e=d*0.25;
if(flag==1 && (60*b+c>480 && 60*b+c<1080 && 60*b+c+d<1080 ))
e=d*0.4;
if(flag==1 && (60*b+c>=0 && 60*b+c<=480 && 60*b+c+d>=480 && 60*b+c+d<=1080 ))
e=(480-(60*b+c))*0.25+(d-(480-(60*b+c)))*0.4;
if(flag==1 && (60*b+c>=0 && 60*b+c<=480 && 60*b+c+d>=1080 && 60*b+c+d<=1440 ))
e=(480-(60*b+c))*0.25+(1080-480)*0.4+(d-(480-(60*b+c))-(1080-480))*0.25;
if(flag==1 && (60*b+c>480 && 60*b+c<1080 && 60*b+c+d>=1080 && 60*b+c+d<=1440 ))
e=(1080-(60*b+c))*0.4+(d-(1080-(60*b+c)))*0.25;
printf("%lf\n",e);
scanf("%s %d %d %d",&str,&b,&c,&d);

}
return 0;

}

⑷ 需要c语言大神啊,,,,例如,宿舍排值日表,宿舍6个人住,星期六星期日不算,星期一到星期五轮流排值

#include<stdio.h>
int main()
{
int i,m,n=1;
for(i=1;i<=40;i++)
{
printf("第%d周:\n",i);
for(m=1;m<=5;m++)
{
printf("星期%d:%d号床值日\n",m,n);
n++;
if(n==7)
n=1;
}
}
return 0;
}
//40周的安排

⑸ 急急!!用C语言编课程表,要求:每星期5天,每天不超过6节课,有语文、数学、英语、政治、历史、音乐

#include <stdio.h>
#include <time.h>
#include <stdlib.h>

#define DAYS_OF_A_WEEK 5
#define MAX_CLASSES_A_DAY 6
#define MAX_CLASS_NAME_LEN 10
#define TOTAL_CLASSESS_TYPE_NUM 5

typedef struct
{
char class_name[MAX_CLASS_NAME_LEN];
int class_num_per_week;
}Class;

Class class_data[]=
{
{"语文",3},{"数学",3},{"英语",3},{"政治",2},{"历史",2},{"音乐",2}
};

char week_days_name[][10] ={"星期天","星期一","星期二","星期三","星期四","星期五","星期六"};

char class_arrange_table[MAX_CLASSES_A_DAY][DAYS_OF_A_WEEK][MAX_CLASS_NAME_LEN]={0};

int main(int argc, char *argv[])
{
int i,j,k;
int row,col;

srand(time(NULL));

for(i=0;i<TOTAL_CLASSESS_TYPE_NUM;i++)
{
for(j=0;j<class_data[i].class_num_per_week;j++)
{
row = rand()% DAYS_OF_A_WEEK ;
col = rand()% MAX_CLASSES_A_DAY;

while(strlen(class_arrange_table[row][col]) != 0)
{
row = rand()% DAYS_OF_A_WEEK ;
col = rand()% MAX_CLASSES_A_DAY;
}

strcpy(class_arrange_table[row][col],class_data[i].class_name);
}
}

printf("%4s","");
for(i=1;i<=DAYS_OF_A_WEEK;i++)
{
printf("|%10s",week_days_name[i]);
}
printf("\n");

for(i=0;i<MAX_CLASSES_A_DAY;i++)
{
for(j=0;j<4+DAYS_OF_A_WEEK*10+DAYS_OF_A_WEEK;j++){ printf("-"); }
printf("\n");

printf("%4d",i+1);
for(j=0;j<DAYS_OF_A_WEEK;j++)
{
printf("|%10s",class_arrange_table[i][j]);
}
printf("\n");
}

for(j=0;j<4+DAYS_OF_A_WEEK*10+DAYS_OF_A_WEEK;j++){ printf("-"); }
printf("\n");

return 0;
}

⑹ C语言编程输入数字1到7 分别输出周一到周日的英文单词

//这个就不用注释了吧
#include
"stdio.h"
void
main()
{
int
i;
printf("输入1~7其中一个数字:");
scanf("%d",&i);
switch(i)
{
case
1:
printf("Monday\n");break;
case
2:
printf("Tuesday\n");break;
case
3:
printf("Wednesday\n");break;
case
4:
printf("Thursday\n");break;
case
5:
printf("Friday\n");break;
case
6:
printf("Saturday\n");break;
case
7:
printf("Sunday\n");break;
default:
printf("April
Fools'
Day\n");break;
}
}

⑺ c语言输出字母星期一到星期日

#include<stdio.h>

enumweekday{
MON=1,TUE,WIN,THE,FRI,THI,SUN
};
intmain(intargc,char*argv[]){
inti;
charday[][3]="{MON},{TUE},{WIN},{THE},{FRI},{THI},{SUN}";
for(i=MON;i<=SUM,i++)
printf("%s ",day[MON-1][0]);
return0;
}

//不懂追问

⑻ C语言程序设计求助,求设计一个程序,要求输入1-7的整数,对应输出星期一~星期天,最好附上思路,谢谢

#include<stdio.h>
void main()
{
int i;
printf("请输入1-7数字 ");
scanf("%d",&i);
switch(i)
{
case 1: printf("今天星期一");break;
case 2: printf("今天星期二");break;
case 3: printf("今天星期三");break;
case 4: printf("今天星期四");break;
case 5: printf("今天星期五");break;
case 6: printf("今天星期六");break;
case 7: printf("今天星期天");break;



}

}



switch语句应该学了吧 直接用switch语句进行选择就行了 运行结果:

⑼ C语言的简单日历代码,求大神帮忙!!

#include<stdio.h>
#include <string.h>
#include <time.h>
#include <math.h>
#include <windows.h>
int year , month , day ;
int day_of_month[12] = {31,28,31,30,31,30,31,31,30,31,30,31};
//char wek[7]={'周日','周一','周二','周三','周四','周五','周六'};
int current_year,current_month,current_day;
/************************************通用关键函数**************************************************/
void cls_screen()
{
printf("请按任意键返回!\n");
getchar();
getchar();
system("cls");
}
void get_current_time() //获取当前时间
{
time_t timep;
struct tm *p;
time(&timep);
p = gmtime(&timep);
current_year=1900+p->tm_year;
current_month=1+p->tm_mon;
current_day=p->tm_mday;
}
int judgement (int y)
{
if (y % 400 == 0 || (y % 100 !=0 && y %4 ==0))
return 1 ;
else return 0 ;
}
int show_week (int year , int month , int day)
{
/*
公式:w=(y+[y/4]+[c/4]-2c+[26(m+1)/10]+d-1)%7
*/
int w ,k; //记录周几
int year_last=year %100,c=year/100 , m = month;
if (month==1 )
{
year_last-=1 ;
m=13 ;
}
else if (month==2)
{
year_last-=1;
m=14;
}
w = (year_last + year_last/4 + c/4 - 2*c +26*(m+1)/10+day-1); // abs 绝对值
if (w<0)
{
k=(w%7+7)%7;
}
else k=w%7;
return k ;
}
/************************************第一部分**************************************************/
void print_year (int year)
{
int i , k ,x ,first_week;
printf ("请输入想要查询的年月(格式如2012):");
scanf ("%d",&year);
printf("=======================%d年===========================\n",year);
printf("\n");
if (judgement(year))
{
day_of_month[1]=29;
}
else day_of_month[1]=28;
for (i=1 ; i <13 ; i++)
{
first_week = show_week(year,i,1);
printf("=====================%d月日历如下========================\n",i);
printf ("Sun\tMon\tTue\tWed\tThu\tFri\tSat\n");
for (x=1;x<=first_week;x++)
{
printf("\t");
if (x%7==0) printf ("\n");
}
for (k=1;k<=day_of_month[i-1];k++)
{
printf("%d\t",k);
if (x%7==0) printf ("\n");
x++;
}
printf("\n");
printf("\n");
printf("\n");
}
}
/************************************第二部分**************************************************/
void print_year_month ()
{
int k ,x ,first_week;
printf ("请输入想要查询的年月(格式如2012 12):");
do
{
scanf ("%d %d",&year,&month);
if (month<1||month>12)
{
printf("您输入的月份有误哦~请输入正确的月份\n");
printf ("请输入想要查询的年月(格式如2012 12):");
}
}while(1>month||month>12);
printf("=====================%d年%d月======================\n",year,month);
if (judgement(year))
{
day_of_month[1]=29;
}
else day_of_month[1]=28;
first_week = show_week(year,month,1);
printf ("Sun\tMon\tTue\tWed\tThu\tFri\tSat\n");
for (x=1;x<=first_week;x++)
{
printf("\t");
if (x%7==0) printf ("\n");
}
for (k=1;k<=day_of_month[month-1];k++)
{
printf("%d\t",k);
if (x%7==0) printf ("\n");
x++;
}
printf("\n");
}
/************************************第三部分**************************************************/
int year_before_sumdays (int year,int month, int day)
{
int days=0 ,i,judgement1;
int temp_day=0 ,sum_days; //
//printf ("%d,%d\n",current_year,current_month);
judgement1=judgement(year);
/*===================比当前少=====================*/
if (year < current_year )
{
for (i = year+1;i < current_year ;i++)
{
if (judgement(i))
{
days=days+356;
}
else days+=355;
}
for (i = month+1;i<=12;i++)
{
days=days+day_of_month[i-1];
}
days = days + day_of_month[month-1]-day; //指定日子距离当年结束还有多少天
//printf("去年还有%d\n",days);
for (i = 0;i < current_month-1;i++ )
{
if (judgement1)
{
day_of_month[1]=29;
}
temp_day = temp_day + day_of_month[i];
}
//当前日子是这一年的多少天
temp_day = temp_day + current_day;
//printf("今天是第%d天\n",temp_day);
sum_days=temp_day + days ;
}
/*===================比当前多=====================*/
if (year > current_year )
{
for (i =current_year+1;i < current_year ;i++)
{
if (judgement(i))
{
days=days+356;
}
else days+=355;
}
for (i = current_month+1;i<=12;i++)
{
days=days+day_of_month[i-1];
}
days = days + day_of_month[month-1]-current_day; //指定日子距离当年结束还有多少天
//printf("去年还有%d\n",days);
for (i = 0;i <month-1;i++ )
{
if (judgement1)
{
day_of_month[1]=29;
}
temp_day = temp_day + day_of_month[i];
}
//当前日子是这一年的多少天
temp_day = temp_day + day;
//printf("今天是第%d天\n",temp_day);
sum_days=temp_day + days ;
}
/*===================比当前一样=====================*/
if (year == current_year )
{
if(month <current_month)
{
for (i=month+1;i<current_month;i++)
{
if (judgement1)
{
day_of_month[1]=29;
}
days = days + day_of_month[i];
}
sum_days = days + current_day + day_of_month[month-1] - day ;
}
if (month>current_month)
{
for (i=current_month+1;i<month;i++)
{
if (judgement1)
{
day_of_month[1]=29;
}
days = days + day_of_month[i];
}
sum_days = days + day + day_of_month[month-1] - current_day ;
printf("%d\n",days);
}
if (month==current_month)
{
sum_days= abs(day-current_day);
}
}
return sum_days ;
}
void print(int year,int month,int day)
{
int week;
printf ("请输入想要查询的年月(格式如2012 12 12 ):");
do
{
scanf ("%d %d %d",&year,&month,&day);
if (judgement(year))
{
day_of_month[1]=29;
}
printf("\n");
if (day<=0 || day >day_of_month[month-1])
printf ("%d月没有%d,请重新输入(格式如2012 12 12 ):",month,day);
}while(day<=0 || day >day_of_month[month-1]);
week=show_week (year,month ,day);
printf("\n");
switch(month)//判断查找天是否阳历节日先由月份判断是否有节日的月份再由日判断是否为节日
{
case 1:switch(day)
{
case 1:printf("元旦") ;break;
default:printf("不是阳历节日");
}break;
case 2:switch(day)
{
case 14:printf("情人节(Valentines Day)");break;
default:printf("不是阳历节日");
}break;
case 3:switch(day)
{
case 8:printf("妇女节¨(Women's Day)");break;
case 12:printf("植树节(Arbor Day)");break;
default:printf("不是阳历节日");
}break;
case 4:switch(day)
{
case 1:printf("愚人节(April Fools Day)");break;
case 5:printf("清明节(Tomb-sweeping Day)");break;
default:printf("不是阳历节日");
}break;
case 5:switch(day)
{
case 1:printf("劳动节(Labor Day)");break;
case 4:printf("中国青年节(Chinese Youth Day)");
default:printf("不是阳历节日");
}break;
case 6:switch(day)
{
case 1:printf("儿童节(Children's Day)");break;
default:printf("不是阳历节日");
}break;
case 8:switch(day)
{
case 1:printf("建军节(the Army's Day)");break;
default:printf("不是阳历节日");
}break;
case 9:switch(day)
{
case 10:printf("教师节(Teacher's Day)");break;
default:printf("不是阳历节日");
}break;
case 10:switch(day)
{
case 1:printf("国庆节(National Day)");break;
case 31:printf("万圣节(Helloween Day)");break;
default:printf("不是阳历节日");
}break;
case 12:switch(day)
{
case 25 :printf("圣诞节(Christmas Day)");break;
default:printf("不是阳历节日");
}break;
}
printf("\n");
printf("%d年%d月%d号是:",year,month,day);
switch(week)//判断所查找天是星期几
{
case 0:printf("Sunday");break;
case 1:printf("Monday");break;
case 2:printf("Tuesday");break;
case 3:printf("Wednesday");;break;
case 4:printf("Thursday");break;
case 5:printf("Friday");break;
case 6:printf("Saturday");break;
}
printf("\n");
printf("距离今天有%d天\n",year_before_sumdays ( year, month, day));
printf("\n");
}
/********************************************************************************************/
void main ()
{
int choice,year,month,day,flag=1;
char c , k;
for(;1;)//显示程序菜单,为永真,每次查找完回到程序菜单ì
{
printf("===================================菜单选项===================================\n");
printf("请选择:\n");
printf("* * * * * * * * 1.查找某一年的年历 * * * * * * * *\n");
printf("* * * * * * * * 2.查找某一月的月历 * * * * * * * *\n");
printf("* * * * * * * * 3.查找某一天 * * * * * * * *\n");
printf("* * * * * * * * 0.退出 * * * * * * * *\n");
printf("=========================================================

⑽ c语言 指针数组打印星期一到星期日

# include <stdio.h>
void printstr(char **p);
int main()
{
char i;
char str[100];
char *num[]={"monday","tuesday","wednesday","thursday","friday","saturday","sunday"};
char **p;
p=num;
// printf("请输入1到7之间的数字 ");
printstr(p);
}
void printstr(char **p)
{
char i;
_start:
printf("请输入1到7之间的数字 ");
fflush(stdin);
scanf("%c", &i);
if(Ƈ'<=i && i<=ƍ')
printf("%s i=%d ",*(p+i-49),i);
//**************************************************************
if(i<Ƈ')
printf("*输入错误!i=%d ",i);
//***********************************************************
if(i>ƍ' && i!='a')
printf("**输入错误! ");
if(i=='a')
{
printf("程序结束了 ");
return;
}
goto _start;
}

10是换行字符' '的ascii码。用scanf读取字符的时候,敲的回车回遗留在缓存里,下次再调用scanf读取字符时,会把这个' '读出来,就不会再要求键盘输入了。

另外,每次输出后,又递归调用,这样随着输入次数的增加,递归会越来越深,很容易导致栈溢出。